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I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat and compact way to generate RF harmonics...', on Sat, 17 Apr 2004: IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Use an inductive current pick-off. That how the Marconi Instruments 1245 series Q-meters work(ed). -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk |
I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat and compact way to generate RF harmonics...', on Sat, 17 Apr 2004: IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Use an inductive current pick-off. That how the Marconi Instruments 1245 series Q-meters work(ed). -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk |
On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer
wrote: On Sat, 17 Apr 2004 07:43:49 GMT, Robert Baer posted this: John Larkin wrote: Well, all the usual methods: resonance width, phase shift, ringdown, stuff like that. I work with gadgets with Qs over 1e9, and people measure them without difficulty. John Ringdown is the easist way when Qs are extremely high. You must still account for the energy you extract from the circuit in order to measure the ringdown. Even the energy needed to drive a high impedance probe is significant when the Q gets high. IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Jim Of course, you can account for the probe loss when you do the math. Or leave the probe disconnected during a ringdown, and add it after some delay to see how much energy is left in the system. John |
On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer
wrote: On Sat, 17 Apr 2004 07:43:49 GMT, Robert Baer posted this: John Larkin wrote: Well, all the usual methods: resonance width, phase shift, ringdown, stuff like that. I work with gadgets with Qs over 1e9, and people measure them without difficulty. John Ringdown is the easist way when Qs are extremely high. You must still account for the energy you extract from the circuit in order to measure the ringdown. Even the energy needed to drive a high impedance probe is significant when the Q gets high. IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Jim Of course, you can account for the probe loss when you do the math. Or leave the probe disconnected during a ringdown, and add it after some delay to see how much energy is left in the system. John |
Robert Baer wrote in message ...
.... Yes, but the emphasis was on small size, and a helical resonator allows a goodly shrinkage of volume wihout a corresponding loss large of Q. As compared with what? A given coil in a helical resonator will result in lower Qu than that same coil unshielded and simply resonated with a good capacitor. .... Maybe his requirements are not too realistic? Seems to commonly be the case. |
Robert Baer wrote in message ...
.... Yes, but the emphasis was on small size, and a helical resonator allows a goodly shrinkage of volume wihout a corresponding loss large of Q. As compared with what? A given coil in a helical resonator will result in lower Qu than that same coil unshielded and simply resonated with a good capacitor. .... Maybe his requirements are not too realistic? Seems to commonly be the case. |
On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
posted this: I read in sci.electronics.design that James Meyer wrote (in ) about 'A neat and compact way to generate RF harmonics...', on Sat, 17 Apr 2004: IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Use an inductive current pick-off. That how the Marconi Instruments 1245 series Q-meters work(ed). Nevertheless, *ANY* method used to probe the field associated with the resonator will load the resonator and degrade the Q. Jim |
On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
posted this: I read in sci.electronics.design that James Meyer wrote (in ) about 'A neat and compact way to generate RF harmonics...', on Sat, 17 Apr 2004: IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Use an inductive current pick-off. That how the Marconi Instruments 1245 series Q-meters work(ed). Nevertheless, *ANY* method used to probe the field associated with the resonator will load the resonator and degrade the Q. Jim |
On Sat, 17 Apr 2004 10:04:36 -0700, John Larkin
posted this: On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer wrote: IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Jim Of course, you can account for the probe loss when you do the math. Or leave the probe disconnected during a ringdown, and add it after some delay to see how much energy is left in the system. John If you have to "do the math", you might as well just calculate the Q from first principles and forget the "measurement". Jim |
On Sat, 17 Apr 2004 10:04:36 -0700, John Larkin
posted this: On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer wrote: IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Jim Of course, you can account for the probe loss when you do the math. Or leave the probe disconnected during a ringdown, and add it after some delay to see how much energy is left in the system. John If you have to "do the math", you might as well just calculate the Q from first principles and forget the "measurement". Jim |
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