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#1
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On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer
wrote: On Sat, 17 Apr 2004 07:43:49 GMT, Robert Baer posted this: John Larkin wrote: Well, all the usual methods: resonance width, phase shift, ringdown, stuff like that. I work with gadgets with Qs over 1e9, and people measure them without difficulty. John Ringdown is the easist way when Qs are extremely high. You must still account for the energy you extract from the circuit in order to measure the ringdown. Even the energy needed to drive a high impedance probe is significant when the Q gets high. IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Jim Of course, you can account for the probe loss when you do the math. Or leave the probe disconnected during a ringdown, and add it after some delay to see how much energy is left in the system. John |
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#2
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On Sat, 17 Apr 2004 10:04:36 -0700, John Larkin
posted this: On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer wrote: IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Jim Of course, you can account for the probe loss when you do the math. Or leave the probe disconnected during a ringdown, and add it after some delay to see how much energy is left in the system. John If you have to "do the math", you might as well just calculate the Q from first principles and forget the "measurement". Jim |
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#3
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On Sat, 17 Apr 2004 19:07:12 GMT, James Meyer
wrote: On Sat, 17 Apr 2004 10:04:36 -0700, John Larkin posted this: On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer wrote: IOW, the Q without the probe will be higher than the Q when you insert the probe to measure the Q. Jim Of course, you can account for the probe loss when you do the math. Or leave the probe disconnected during a ringdown, and add it after some delay to see how much energy is left in the system. John If you have to "do the math", you might as well just calculate the Q from first principles and forget the "measurement". Jim How can you calculate Q from first principles? 3D EM simulation? Quantum mechanics? John |
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#4
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Ah, just the person I've been waiting for. How do you account for
current bunching on the conductors (that is, non-uniform distribution of current around the conductors)? What reference, equation, or program do you use? Nearly all "first principle" calculations of Q I've seen grossly overestimate Q, and I believe the failure to take this into account is at least part of the reason. I haven't seen a decent analytical method of dealing with it, and an anxious to see how you do it. Then there's surface corrosion and roughness, radiation, and coupling to nearby objects. How do you deal with those? Have you identified some of the other factors that often make a simplistic "first principle" calculation disagree so badly with carefully made measurements? Roy Lewallen, W7EL James Meyer wrote: If you have to "do the math", you might as well just calculate the Q from first principles and forget the "measurement". Jim |
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#5
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On Sat, 17 Apr 2004 12:22:03 -0700, Roy Lewallen posted this:
Ah, just the person I've been waiting for. How do you account for current bunching on the conductors (that is, non-uniform distribution of current around the conductors)? What reference, equation, or program do you use? Nearly all "first principle" calculations of Q I've seen grossly overestimate Q, and I believe the failure to take this into account is at least part of the reason. I haven't seen a decent analytical method of dealing with it, and an anxious to see how you do it. Then there's surface corrosion and roughness, radiation, and coupling to nearby objects. How do you deal with those? Have you identified some of the other factors that often make a simplistic "first principle" calculation disagree so badly with carefully made measurements? Roy Lewallen, W7EL James Meyer wrote: If you have to "do the math", you might as well just calculate the Q from first principles and forget the "measurement". Jim I was responding to a suggestion that one could do the math to calculate what the Q would have been if you hadn't tried to measure it. I was pointing out that if you could do that math, and get it correct, that you could do the whole exercise with math and forget measuring anything. And how do you know for sure that calculations overestimate Q when measuring Q to verify the calculations disturbs the very thing you're measuring? An engineer knows when to say "close enough". A mathematician is never satisfied. Jim |
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#6
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James Meyer wrote:
. . . And how do you know for sure that calculations overestimate Q when measuring Q to verify the calculations disturbs the very thing you're measuring? An engineer knows when to say "close enough". A mathematician is never satisfied. I've measured quite a number of inductors both with a homebrew setup, in which I account for the losses in the input and output networks, and with an HP Q meter of specified accuracy. With simple input and output networks consisting of a small series C and shunt R, the effect on Q is predictable and easy to calculate. Results from the two methods agree quite closely, even though they use somewhat different methods to arrive at the Q, giving a fair amount of confidence in both results. And both disagree quite dramatically in some cases to Q calculated simply from theoretical calculations which include only conductor resistance (including skin effect, of course), inductance, and shunt capacitance. This is with inductors of only moderate Q -- calculation of very high Q inductors, which is being discussed here, would require more attention to second order effects -- as would measurement. Thanks for the profound observation about mathematicians and engineers. In which category does one put a person who's satisfied with calculations made without thinking about, caring about, or considering the errors caused by ignoring fundamental effects? Certainly not an engineer as I use the term. Roy Lewallen, W7EL |
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#7
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On Sat, 17 Apr 2004 18:56:14 -0700, Roy Lewallen posted this:
Thanks for the profound observation about mathematicians and engineers. In which category does one put a person who's satisfied with calculations made without thinking about, caring about, or considering the errors caused by ignoring fundamental effects? Certainly not an engineer as I use the term. Roy Lewallen, W7EL Such a person as you describe is commonly known as a physicist. I have had to work with several. That some of them are still alive is a testament to my degree of self control. Jim |
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#8
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I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat and compact way to generate RF harmonics...', on Sun, 18 Apr 2004: On Sat, 17 Apr 2004 18:56:14 -0700, Roy Lewallen posted this: Thanks for the profound observation about mathematicians and engineers. In which category does one put a person who's satisfied with calculations made without thinking about, caring about, or considering the errors caused by ignoring fundamental effects? Certainly not an engineer as I use the term. Roy Lewallen, W7EL Such a person as you describe is commonly known as a physicist. I have had to work with several. That some of them are still alive is a testament to my degree of self control. LOL! But physicists are usually *preoccupied* with fundamental effects and tend to ignore others. In my brief skirmish with aeronautical engineering, I formed the opinion that most of the calculations were as pragmatic as RL suggests; the only consolation is that they seem to work. -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk |
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#9
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I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat and compact way to generate RF harmonics...', on Sun, 18 Apr 2004: On Sat, 17 Apr 2004 18:56:14 -0700, Roy Lewallen posted this: Thanks for the profound observation about mathematicians and engineers. In which category does one put a person who's satisfied with calculations made without thinking about, caring about, or considering the errors caused by ignoring fundamental effects? Certainly not an engineer as I use the term. Roy Lewallen, W7EL Such a person as you describe is commonly known as a physicist. I have had to work with several. That some of them are still alive is a testament to my degree of self control. LOL! But physicists are usually *preoccupied* with fundamental effects and tend to ignore others. In my brief skirmish with aeronautical engineering, I formed the opinion that most of the calculations were as pragmatic as RL suggests; the only consolation is that they seem to work. -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk |
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#10
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On Sat, 17 Apr 2004 18:56:14 -0700, Roy Lewallen posted this:
Thanks for the profound observation about mathematicians and engineers. In which category does one put a person who's satisfied with calculations made without thinking about, caring about, or considering the errors caused by ignoring fundamental effects? Certainly not an engineer as I use the term. Roy Lewallen, W7EL Such a person as you describe is commonly known as a physicist. I have had to work with several. That some of them are still alive is a testament to my degree of self control. Jim |