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#1
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Hi all,
In his very skimpy explanation on basic DC biasing for FETs, Chris Bowick (in RF Circuit Design) gives the suggested bias network that I've posted to a.b.s.e under the same subject title as this message. I don't see how this arrangement can possibly work for any N-Jfet since for one thing at least, the gate is positive with respect to the source. I've tried to scan the page in and post that, but the scanner's messing about, so I've redrawn it as a spice schematic and posted that instead. If it turns out the arrangement is incorrect, as I suspect, I will endeavor to post his explanation for how he arrived at these resistor values. So: is he wrong or am I nuts? p. Note: for anyone using LTspice, the fet shown is not a working model; I'm simply posting this as a diagram for illustration. -- "What is now proved was once only imagin'd." - William Blake, 1793. |
#2
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On Wed, 11 Aug 2004 20:46:24 +0100, Paul Burridge
wrote: Hi all, In his very skimpy explanation on basic DC biasing for FETs, Chris Bowick (in RF Circuit Design) gives the suggested bias network that I've posted to a.b.s.e under the same subject title as this message. I don't see how this arrangement can possibly work for any N-Jfet since for one thing at least, the gate is positive with respect to the source. I've tried to scan the page in and post that, but the scanner's messing about, so I've redrawn it as a spice schematic and posted that instead. If it turns out the arrangement is incorrect, as I suspect, I will endeavor to post his explanation for how he arrived at these resistor values. So: is he wrong or am I nuts? p. Note: for anyone using LTspice, the fet shown is not a working model; I'm simply posting this as a diagram for illustration. Looks like the jfet will be saturated with the values shown, not good for RF work. Looks like he got the sign of Vgs backwards. The next example on the same page illustrates that Vg must be near zero, not +5. Really silly, putting these two circuits side-by-side. John |
#3
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![]() John Larkin wrote: Looks like the jfet will be saturated with the values shown, not good for RF work. Looks like he got the sign of Vgs backwards. The next example on the same page illustrates that Vg must be near zero, not +5. Really silly, putting these two circuits side-by-side. John Shhhh...don't tell the resident idiot, but it's going to be damn tough biasing that IDSS=5mA JFET to a quiescent ID=10ma.... |
#4
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On Thu, 12 Aug 2004 02:58:57 GMT, Fred Bloggs
wrote: John Larkin wrote: Looks like the jfet will be saturated with the values shown, not good for RF work. Looks like he got the sign of Vgs backwards. The next example on the same page illustrates that Vg must be near zero, not +5. Really silly, putting these two circuits side-by-side. John Shhhh...don't tell the resident idiot, but it's going to be damn tough biasing that IDSS=5mA JFET to a quiescent ID=10ma.... Good point. Bowick seems to be applying the jfet gate-voltage equation backwards to enhance it! The other example on page 120 is even sillier. Just shows you that an RF expert can't always handle DC. John |
#5
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On Thu, 12 Aug 2004 08:28:41 -0700, John Larkin wrote:
On Thu, 12 Aug 2004 02:58:57 GMT, Fred Bloggs wrote: John Larkin wrote: Looks like the jfet will be saturated with the values shown, not good for RF work. Looks like he got the sign of Vgs backwards. The next example on the same page illustrates that Vg must be near zero, not +5. Really silly, putting these two circuits side-by-side. John Shhhh...don't tell the resident idiot, but it's going to be damn tough biasing that IDSS=5mA JFET to a quiescent ID=10ma.... LOL. That was an astute observation, not that I'm surprised. Either I didn't read that part of the book ( I have a NOV '82 Siliconix data book that sufficed) or I blew it off. Good point. Bowick seems to be applying the jfet gate-voltage equation backwards to enhance it! The other example on page 120 is even sillier. I *do* remember reading *that*. 0 + 2.48 = 0 for sufficiently small values of 2.48, yup. I better compare all his refs to my own collection of app notes in der future and check the math. Just shows you that an RF expert can't always handle DC. It's his math, actually. See my other post and while you're at it, reply to my reply to the idiot so he can see it. A blank post will suffice -) -- Best Regards, Mike |
#6
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On Thu, 12 Aug 2004 18:57:34 -0400, Active8
wrote: I *do* remember reading *that*. 0 + 2.48 = 0 for sufficiently small values of 2.48, yup. Now *that's* funny! Too bad Paul won't see it! John |
#7
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In article ,
Fred Bloggs wrote: John Larkin wrote: Looks like the jfet will be saturated with the values shown, not good for RF work. Looks like he got the sign of Vgs backwards. The next example on the same page illustrates that Vg must be near zero, not +5. Really silly, putting these two circuits side-by-side. John Shhhh...don't tell the resident idiot, but it's going to be damn tough biasing that IDSS=5mA JFET to a quiescent ID=10ma.... Theres no problem getting 10mA to flow in a FET with Idss of 5mA. Just apply a positive bias to the gate. I've had as much as 2 or 3 A flow through a JFET this way. -- -- forging knowledge |
#8
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#9
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![]() Paul Burridge wrote: On Fri, 13 Aug 2004 03:49:15 +0000 (UTC), (Ken Smith) wrote: Theres no problem getting 10mA to flow in a FET with Idss of 5mA. Just apply a positive bias to the gate. I've had as much as 2 or 3 A flow through a JFET this way. How many mS did the Fet last? I suppose you could always stand there with a can of arctic spray directed on it, but I doubt the customer would be impressed. ;-) Actually there have been systems produced that did run quite hot and were arranged with a liquid nitrogen drip onto the electronics to keep things cool. |