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#1
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wrote in message oups.com... How close Z11=((1+s11)*(1-s22)+s12*s21)/((1-s11) *(1-s22)-s12*s21) will be to the stated large signal impedances after you convert it to a series equivalent impedance on the Smith chart, I don't really know. Note: In the above formula Z11 should be replaced by Z11 / Z0. In other words Z11 is "normalized" with respect to Z0 in this formula. See the Gonzalez reference. In a "normalized" Smith chart Z0=1.0. Bill W0IYH |
#2
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William E. Sabin wrote: wrote in message oups.com... How close Z11=((1+s11)*(1-s22)+s12*s21)/((1-s11) *(1-s22)-s12*s21) will be to the stated large signal impedances after you convert it to a series equivalent impedance on the Smith chart, I don't really know. Note: In the above formula Z11 should be replaced by Z11 / Z0. In other words Z11 is "normalized" with respect to Z0 in this formula. See the Gonzalez reference. In a "normalized" Smith chart Z0=1.0. Bill W0IYH You're correct according to Pozar. I'm gonna assume that this was just a typo on Gottlieb's part (pg.131, Practical RF power Design Tech.), and what he really meant to type was lowercase "z11", to show it was normalized. (I have a feeling Gottlieb just copied this out of another book, just like i copied it from him! heheh...) But you bring up a good point: I might be barking up the wrong tree here if Z11 or z11 is defined as the input impedance when port 2 is open circuited. This shouldn't be the same as the large signal input impedance, when the output is approximately conjugately matched. Slick |
#3
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Note:
In the above formula Z11 should be replaced by Z11 / Z0. In other words Z11 is "normalized" with respect to Z0 in this formula. See the Gonzalez reference. In a "normalized" Smith chart Z0=1.0. Bill W0IYH If the output is terminated with a 50 ohm pure resistance load then S11 is the complex input reflection coefficient, 0 to 1.0. In an active circuit (amplifier or oscillator) S11 can be outside these limits due to positive internal DUT feedback. Bill W0IYH |
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