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![]() Dave, your considerable effort to explain the nuances of diodes to John is commendable, but your explanation is rather misleading. It's not true that for a diode to conduct, the "barrier potential must be exceeded," and "the junction becomes forward biased and conducts heavily." Instead the diode current has an exponential relationship to the voltage across it, and gradually turns on over many hundreds of millivolts, not abruptly at say 600mV. Here, examine some diode measurements I made a long time ago, http://www.picovolt.com/win/elec/com...de-curves.html The theory confirms your results. I diode ~K*exp(Vsignal/Vt) =K+ a*Vsignal + b*Vsignal^2+ .... by the binomial theorem So at low signal amplitudes the diode current follows a linear relationship as predicted by the diode equation and confirmed by the graphs there. At higher values the higher terms start dominating and the exponential term takes over. |
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