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			I read in sci.electronics.design that john jardine 
		
		
		
		
		
		
		
		
	
	wrote (in k) about 'Diode and very small amplitude high frequencies signals', on Sat, 5 Feb 2005: Test on a 1N4148. ForwardV DiodeR +50mV 8megs. +30mV 9megs. +20mV 10megs. +10mv 12megs. +5mV 21megs. ReverseV -5mV 21megs. -10mV 30megs. -30mV 270megs. How did you measure the resistance? Is it an incremental resistance (slope of the V/I curve at the data point) or the slope of a line joining the origin to the data point on the curve. -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk  | 
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			 "John Woodgate" wrote in message news ![]() I read in sci.electronics.design that john jardine wrote (in k) about 'Diode and very small amplitude high frequencies signals', on Sat, 5 Feb 2005: Test on a 1N4148. ForwardV DiodeR +50mV 8megs. +30mV 9megs. +20mV 10megs. +10mv 12megs. +5mV 21megs. ReverseV -5mV 21megs. -10mV 30megs. -30mV 270megs. How did you measure the resistance? Is it an incremental resistance (slope of the V/I curve at the data point) or the slope of a line joining the origin to the data point on the curve. -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk I didn't measure the resistance. The values just come from the static V and I plot points on the graph. Having had my remaining bench DVM, (good ol'e UK, Datron ****e) pack in on me and 2 battery DVMs keel over with flat batteries and the CMOS buffers floating off to la la land and 2 crocodile clips secretly fail and finally my electric pencil sharpener going tits up, I was not of a mind to press on :-) regards john  | 
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			john jardine wrote: 
		
		
		
		
		
		
		
		
	
	"John Woodgate" wrote in message news ![]() I read in sci.electronics.design that john jardine wrote (in k) about 'Diode and very small amplitude high frequencies signals', on Sat, 5 Feb 2005: Test on a 1N4148. ForwardV DiodeR +50mV 8megs. +30mV 9megs. +20mV 10megs. +10mv 12megs. +5mV 21megs. ReverseV -5mV 21megs. -10mV 30megs. -30mV 270megs. How did you measure the resistance? Is it an incremental resistance (slope of the V/I curve at the data point) or the slope of a line joining the origin to the data point on the curve. -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk I didn't measure the resistance. The values just come from the static V and I plot points on the graph. Having had my remaining bench DVM, (good ol'e UK, Datron ****e) pack in on me and 2 battery DVMs keel over with flat batteries and the CMOS buffers floating off to la la land and 2 crocodile clips secretly fail and finally my electric pencil sharpener going tits up, I was not of a mind to press on :-) regards john In other words, this data is just a plot of a diode's DC I vs V characteristic, right? What is of more interest is the slope at a given DC operating point. If we pick 0V, for example, the above data (within the limits of its precision) gives a flat line around that point (+5mV 21 Mohms, -5mV 21 Mohms). With a 100 uV signal, you might as well throw a 21 M ohm resistor in there instead. -- Paul Hovnanian ------------------------------------------------------------------ Think honk if you're a telepath.  | 
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			 "Paul Hovnanian P.E." wrote in message ... In other words, this data is just a plot of a diode's DC I vs V characteristic, right? What is of more interest is the slope at a given DC operating point. If we pick 0V, for example, the above data (within the limits of its precision) gives a flat line around that point (+5mV 21 Mohms, -5mV 21 Mohms). With a 100 uV signal, you might as well throw a 21 M ohm resistor in there instead. -- Paul Hovnanian ------------------------------------------------------------------ Think honk if you're a telepath. Yep. Straight as a die between +/- 4mV. Incremental resistance dV/di =10Mohm regards john  | 
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			Paul Hovnanian P.E. wrote: 
		
		
		
		
		
		
		
		
	
	In other words, this data is just a plot of a diode's DC I vs V characteristic, right? What is of more interest is the slope at a given DC operating point. If we pick 0V, for example, the above data (within the limits of its precision) gives a flat line around that point (+5mV 21 Mohms, -5mV 21 Mohms). With a 100 uV signal, you might as well throw a 21 M ohm resistor in there instead. Exactly. At very small currents, the diode is just a resistor (shunted by a capacitance). At slightly small currents, it's a very poor diode, with reverse current almost equal to the forward current, so on each negative half cycle you suck out nearly all the charge you delivered during the positive half cycle. Roy Lewallen, W7EL  | 
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