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#1
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On Fri, 25 Feb 2005 11:53:52 -0500, "xpyttl"
wrote: "Spajky" wrote in message IMHO not, (practically maximum about 10x less probably with good The current record on 80 meters is 546.8 miles with 0.0406 mW. with just probably 40mW IMHO (not 40 microW) Incredible distance, must had ben hell of a reciever & antennas & probably a reflected wave ... wow if this is true .. even for very narrowBand non-modulated carrier CW BTW, that my simplified formula I calculated for Phono work, with CW the distances achieved normally I know are few times greater ... -- Regards , SPAJKY ® & visit my site @ http://www.spajky.vze.com "Tualatin OC-ed / BX-Slot1 / inaudible setup!" E-mail AntiSpam: remove ## |
#2
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"Spajky" wrote in message
... with just probably 40mW IMHO (not 40 microW) Yeah, 40 microwatts, really. I probably should hasten to add that this was not a random QSO. The transmitting station has been sending a beacon at various times, frequencies, and power levels for several weeks. There have probably been several hundred stations listening for that beacon. While this particular one was the best on 80 meters, it really isn't all that much of an outlier. Plenty of other stations were in the same general neighborhood on other nights. It did surprise me to see this on 80, though. As Roy points out, the absence of atmospheric noise is not a valid assumption on HF, and noise does increase with decreasing frequency. This is exactly the opposite to your radar experience where it is all about receivernoise. Even at 10 MHz, the most basic receiver will be sufficiently sensitive that it is limited by atmospheric noise. This seems to be a particularly bad winter for noise on 80, although there have been occasional evenings when the conditions have been pretty astonishing. Also, the noise causes in the lower HF region tend to be somewhat different than those in the upper HF. Paul Harden made a couple of nice postings to QRP-L explaining some of that after that quasar whacked us back in December I think it was. Interesting to note that the news media only picked up on that event last week. Pretty astonishing, though, that something millions of light years away could be so energetic as to shut down 80 meters for a couple of days! By the way, I see that Paul will be speaking at Dayton (FDIM) this year. I was planning to go anyway, but it would be worth the trip just to hear him. This guy *really* understands what space weather does to our propagation. ... |
#3
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On Sat, 26 Feb 2005 10:29:29 -0500, "xpyttl"
wrote: It did surprise me to see this on 80, though. As Roy points out, the absence of atmospheric noise is not a valid assumption on HF, and noise does increase with decreasing frequency. However, the noise power is proportional to bandwidth, so if the throughput rate is not defined, slow down the bit rate to reduce the required receiver bandwidth, until the noise is weaker than the signal. While the lower HF noise is not pure white noise, this principle can still be applied. For instance on the 135 kHz LF band, it is quite common to use QRSS with a dot time of several seconds or even a minute and the reception is done visually on the "Waterfall" (spectrogram) display. Although the LF transmitter power might be several hundred watts, the transmitter antenna efficiency is usually much worse than -30 dB, so the radiated power is well below 1 Werp and the noise level is much higher than on HF. Paul OH3LWR |
#4
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On Sat, 26 Feb 2005 10:29:29 -0500, "xpyttl"
wrote: Yeah, 40 microwatts, really. I probably should hasten to add that this was not a random QSO. The transmitting station has been sending a beacon at various times, frequencies, and power levels for several weeks. There have probably been several hundred stations listening for that beacon. oh, that was the case ... .... well, I recalculated reached distance for usuable everydays connection in real normal conditions with average equipment /forgetting the extremes!/ (after some additional thinking reading these posts) to even simplier formula than before & more realistic (a bit larger distances reached) as follows: to reach the distance of ONE full wavelenght (ex.80m for 3,75MHz) you approx. need Rf RMS voltage on TX out for antenna (50ohm) : 1mV - for narrowBand unmod.carr.CW 3,16mV - for ordinary CW & SSB (+10dB) 10mV !! - for ordinary FM & AM or other (another +10dB = +20dB) 30mV - for PacketRadio - for no data loss (+ another 10dB) .... so original poster (Peter) could get out of his set normally 5Km for sure (more than 3 miles with his 7mW-atts). IMHO this is some kind of reasonable expectations about recieving range ... bye .. :-) -- Regards , SPAJKY ® & visit my site @ http://www.spajky.vze.com "Tualatin OC-ed / BX-Slot1 / inaudible setup!" E-mail AntiSpam: remove ## |
#5
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![]() "Peter Barbella" wrote in message news:2xkTd.30756$ya6.20070@trndny01... I've built a little 80 meter transmitter that seems to be putting out about 7 milliwatts. By my caculation, that should be good for about 40 miles. Anyone have any experience with low a power output? Pete KB1LZH Guys, With this post, I have received several useful suggestions and comments. Thank you very much. Many of you are curious about the assumptions I made when I made my calculation of 40 miles. I simply went with something I know: the radar equation. I made a simple adaptation to the radar equation. It starts with a simple premise that the power in my transmitter will be radiated equally in all directions. That is equivalent to a zero DB gain antenna. I assumed that the receiver will have a sensitivity of -80 dBm. I then, simply applied the basic fact that power diminishes as the square of the range. That leaves a power density at any given range of P divided by 4 pie R*2. (Forgive the lack of an equation editor) The next assumption involved the capture area of the receiving antenna. In radar, the capture area of an antenna is proportional to the wavelength squared. With a zero DB receiving antenna, the capture area would be simply lambda squared divided by four pie. With those simple assumptions you can determine the amount of power available for a receiver. Since my little transmitter is a simple breadboard with three transistors and a wire that runs out of my house and up a maple tree, I made a further assumption that I have about 10 DB of loss delivering my transmitter power to the antenna. That 10 DB loss along with the assumption of only minus 80 dBm sensitivity in the receiver seemed pretty conservative to me. Most receivers can probably do much better, especially with CW operation. Of course, as RegEdwards has pointed out, what is really needed is a good benchmark. Several of you provided me with some interesting benchmarks. Thank you very much for your replies. Regards, Peter Barbella KB1LZH ... |