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Ken Scharf wrote:
John Popelish wrote: Wes Stewart wrote: On Fri, 18 Nov 2005 23:06:03 -0500, John Popelish wrote: Ken Scharf wrote: I was looking at some power supply circuits for tube linears and was thinking about the full wave voltage doubler. This is basicly two half wave rectifiers in series. Now I could build this circuit with a choke input filter for each half wave rectifier of the voltage doubler, and I could put the chokes in the lead without the rectifier. In this case I could use one choke for both halfs of the voltage doubler. The output should then be about .9 * rms input voltage * 2 or 1.8 times the rms voltage of the transformer. Has anybody ever tried this? ------|-------- ) | | ) | --- ) | --- )-----^^^^^^----| | | | --- | --- |--|--------| Crude schematic showing transformer secondary diodes filter choke and capacitors. If the choke is directly in series with the transformer, it will have to pass AC, and that won't provide normal choke input filtering (which steadies the DC current after the rectifier), but just puts an impedance between the transformer and the doubler. All chokes are in series with the transformer and pass some AC component. If they only passed DC we would need them. I was using DC in the "unidirectional current" sense, not the "having no AC components" sense. Without giving this too much (likely enought) thought I think this will fail because without loads across -each- filter cap, the critical inductance will not be obtained. Regardless of the loads across the caps, this inductor cannot ever achieve critical inductance, since that is the inductance that keeps the current reaching zero, each half cycle. In this circuit, the inductor precedes the rectifiers, so its current must pass through zero twice per cycle, regardless of the capacitor load. You could also put it in series with the primary, instead, and achieve the same effect (with the proper scaling to account for the turns ratio). There may be a way to incorporate an inductor into a doubler, but I don't think this is it. Why you all may be right, what you are failing to see is that the choke is simply in the negative leg of the positive half wave rectifier, and in the positive leg of the negative half wave rectifier, and both rectifier outputs are in series. ------|----- ) | ) --- ) --- ) | ---^^^^^^^---- This is a half wave rectifier with a choke input filter with the choke in the negative end. Will this work? Not at all well, because you have provided no path for the inductor current when the voltage from the transformer tires to reverse bias the diode. So the inductor will keep the diode conducting as the voltage reverses. This is not at all the way a choke input filter acts with a full wave rectifier. I am quite sure you have never seen a choke input filter in a half wave supply, for this reason. Now connect this circuit in series with negative output half wave and you notice you have two chokes in parallel. Yes you do need a bleeder resistor or minimal load to satisify the choke current requirement, I simply didn't draw this, the resting current of a class AB1 linear would satisfy that. Now what am I failing to see? That there is a second current path through the inductor that involves the other rectifier. So AC is applied to the inductor, instead of unidirectional voltage. |
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