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#1
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Soooo...if the modulator is transformer-coupled, how does the DC input
to the RF amplifier increase when modulation is applied? A transformer can't couple DC... Not saying the fellow can't do what he wants, but we need to know a LOT more about the circuit. Remember, too, that the half-power rule is for sinewave modulation. If you use square-wave modulation at 100% depth, you need as much power from the modulator as the DC input to the RF amplifier. The modulated output is four times the unmodulated power, for half the time, and zero for the other half, assuming an RF stage that responds linearly to the modulation voltage. For a given modulated waveform, it's easy enough to figure out what the actual power is, and it all has to come from somewhere. If the plate modulation is linear (current is linear with modulated voltage) and the modulation is coming through a transformer, then the average current from the RF deck plate supply must be constant, and the DC power input is therefore constant. Whatever power you put in the sidebands must come through the transformer. But maybe the circuit he's proposing DC couples the modulation voltage, and thus allows an increase in the DC current going to the RF deck. Cheers, Tom |
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#2
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In article .com,
"K7ITM" wrote: Soooo...if the modulator is transformer-coupled, how does the DC input to the RF amplifier increase when modulation is applied? A transformer can't couple DC... You really don't know the answer to this? Did you actually pass the Theory Exam? Inquiring minds want to know......... |
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#3
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It is so simple you can't believe it. It's only Ohm's Law.
The Class-C plate modulated final amplifier is driven hard on its control grid such that it is driven into saturation even when its DC plate volts is increased to twice its normal DC value. When saturated, the peak RF plate output volts always swing between twice the DC supply volts and some very low value. The final amplifier therefore constitutes a fixed DC load resistance across the DC supply, which depends on unmodulated RF power output and amplifier power efficiency. This fixed resistance is also the value of the audio-frequency load impedance across the secondary of the modulation transformer. For 100 percent modulation, the peak RF plate volts across the tank circuit swing between twice the modulated plate supply DC volts and zero. (Or some very low value.) The harder the grid drives the plate circuit into saturation, the greater the modulating linearity. The drive limit is reached when any of the tube's electrodes approaches its rated power dissipation. Eaxactly the same things happen with transistors. ---- Reg. |
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#4
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Thank you, Reg. My reply would have been much less gracious and not
nearly so complete. Probably something like, "Which part of 'constant DC input' do you not understand?" I appreciate that you took the time to write such a nice reply, one that the lurkers may well learn something from. Another reason, of course, that a tube can't handle modulation peaks is that it's getting weak (or the initial design was inadequate). Seeing the plate current meter wiggle during modulation that's below 100% is a good sign it's time to check the RF output tubes, and as your reply suggests, the drivers as well, though the grid current meter should tell you enough about that. If the filament (cathode) no longer has enough emission, the tube may handle the carrier OK, but not the positive modulation peaks where the current must be about twice as high as with just the carrier. Then the DC current will drop during modulation. Cheers, Tom |
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