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Hi Andy,
"AndyS" wrote in message ups.com... Now, if the counterpoise was at infinity, the Efield must always be zero, since any voltage divided by infinity ( to give V/M) will be zero. If I take a charged sphere with 1V applied, the E field falls off as 1/R all the way out to infinity; it is only there that it's actually zero, yes? If you know of an antenna that has no counterpoise for the "hot" side to work against, please post some information about it...... How about a half-wave antenna (end-fed zepp)? Assuming it's being fed by coax, would you suggest the counterpoise is the ring making up the shield of the coax right where the coax stops and the antenna starts? I would like to hear from someone like Roy as well, since I certainly am well outside of any areas of significant experience here. ---Joel |
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