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#1
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Omega One Radio is back on the air, on 13.556.00 MHz LSB, with a power
output of 100 watts. Todd N9OGL OMEGA ONBE RADIO 13.556.00 MHz LSB |
#2
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"N9OGL" wrote in
oups.com: Omega One Radio is back on the air, on 13.556.00 MHz LSB, with a power output of 100 watts. Todd N9OGL OMEGA ONBE RADIO 13.556.00 MHz LSB I thought that might be your ****ty music. Welcome back. SC |
#3
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![]() N9OGL wrote: Omega One Radio is back on the air, on 13.556.00 MHz LSB, with a power output of 100 watts. Todd N9OGL OMEGA ONBE RADIO 13.556.00 MHz LSB Hey Toiddie...I forwarded this to Monitoring Times for you so they could get the story about you straight! You can thank me later. Steve, K4YZ |
#4
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![]() K4YZ wrote: N9OGL wrote: Omega One Radio is back on the air, on 13.556.00 MHz LSB, with a power output of 100 watts. Todd N9OGL OMEGA ONBE RADIO 13.556.00 MHz LSB Hey Toiddie...I forwarded this to Monitoring Times for you so they could get the story about you straight! You can thank me later. Steve, K4YZ Steve, I suggest you read Part 15, Part 15 has nothing to do with power (in Wattage) it has to do with the field strength (maininly the electrical field of the electromaganetic wave) you can put out 100 watts and still have the field strength as prescribed under part 15 (on 13.556 MHz it 15,848 microvolts per meter at a distance of 30 meters (90 Feet) CB radio's which run 4 - 5 watts is 10,000 microvolts per meter at 30 meters.....but you wouldn't know anything about that now would you?? Todd N9OGL OMEGA ONE RADIO 13.556.00 MHz. LSB |
#6
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On 6 Nov 2006 16:31:39 -0800, N9OGL wrote:
: : Steve, I suggest you read Part 15, Part 15 has nothing to do with power : (in Wattage) it has to do with the field strength (maininly the : electrical field of the electromaganetic wave) you can put out 100 : watts and still have the field strength as prescribed under part 15 (on : 13.556 MHz it 15,848 microvolts per meter at a distance of 30 meters : (90 Feet) CB radio's which run 4 - 5 watts is 10,000 microvolts per : meter at 30 meters.....but you wouldn't know anything about that now Odd. If you take the formula for an isotropic radiator emitting P watts and solve it for the electric field, e, you come up with e = sqr(30*P)/r at a distance of "r" meters (see my earlier posts). For a power of 5 watts at a distance of 30 meters, that becomes e = sqr(30*5)/30 = 0.408 volts/meter = 408,000 microvolts/meter. That number is 400 times larger than the value you quoted. Where in the heck are you obtaining figures like 10,000 microvolts/meter? Have you been consulting Woger again? |
#7
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#8
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On Tue, 07 Nov 2006 23:08:19 -0500, wrote:
: On Wed, 8 Nov 2006 03:28:13 +0000 (UTC), Stagger Lee : wrote: : : On Tue, 07 Nov 2006 21:48:10 -0500, wrote: : : On Tue, 7 Nov 2006 23:47:02 +0000 (UTC), Stagger Lee : : wrote: : : : : On 6 Nov 2006 16:31:39 -0800, N9OGL wrote: : : : : : : Steve, I suggest you read Part 15, Part 15 has nothing to do with power : : : (in Wattage) it has to do with the field strength (maininly the : : : electrical field of the electromaganetic wave) you can put out 100 : : : watts and still have the field strength as prescribed under part 15 (on : : : 13.556 MHz it 15,848 microvolts per meter at a distance of 30 meters : : : (90 Feet) CB radio's which run 4 - 5 watts is 10,000 microvolts per : : : meter at 30 meters.....but you wouldn't know anything about that now : : : : Odd. If you take the formula for an isotropic radiator emitting P : : watts and solve it for the electric field, e, you come up with : : e = sqr(30*P)/r at a distance of "r" meters (see my earlier posts). : : : : what is odd is that you keep leaving the apporoate contants that : : adjust for the presence of AIR (amoug other thing : : Air and vacuum have nearly identical permittivity and permeability - : the properties which control the impedance of air and of free space : and which in turn relate electric field strength to the spatial power : density. It sounds to me as though you are simply blowing smoke and : have no real understanding of what you just attempted to write. : : you are the one without any idea idea of what you are writting : : you simply have NO understanding of Gausses law which deteremines : electircal feild strength Wrong. In the case of an electromagnetic field, Gauss' law is only one of four equations (Maxwell's equations) that are needed to determine the electric field strength. Since a changing magnetic field can produce an electric field too (Faraday's law), Gauss' law is not enough. The only time it is sufficient is in the electrostatic case. Fortunately, the case under discussion doesn't require the solution of a set of partial differential equations (Maxwell's equations), because the solution has been incorporated into the idea of the impedance of free space. That includes the permittivity of the medium (as used by Gauss' law) plus the permeability of the medium, and it allows one to express the power density in space with an Ohm's law type of equation that involves only the electric field and the impedance. That simple equation says that 5 watts of radiated power will produce an electric field strength which is 40 times larger than that claimed by N9OGL. That's why I asked him if he'd been consulting with Woger again. Perhaps he's been consulting with you instead. You just got an "F" in electromagnetics. ==================== God said, "div D = rho, div B = 0, curl E = -@B/@t, curl H = J + @D/@t," and then there was light. |
#9
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![]() Stagger Lee wrote: On Tue, 07 Nov 2006 21:48:10 -0500, wrote: : On Tue, 7 Nov 2006 23:47:02 +0000 (UTC), Stagger Lee : wrote: : : On 6 Nov 2006 16:31:39 -0800, N9OGL wrote: : : : : Steve, I suggest you read Part 15, Part 15 has nothing to do with power : : (in Wattage) it has to do with the field strength (maininly the : : electrical field of the electromaganetic wave) you can put out 100 : : watts and still have the field strength as prescribed under part 15 (on : : 13.556 MHz it 15,848 microvolts per meter at a distance of 30 meters : : (90 Feet) CB radio's which run 4 - 5 watts is 10,000 microvolts per : : meter at 30 meters.....but you wouldn't know anything about that now : : Odd. If you take the formula for an isotropic radiator emitting P : watts and solve it for the electric field, e, you come up with : e = sqr(30*P)/r at a distance of "r" meters (see my earlier posts). : : what is odd is that you keep leaving the apporoate contants that : adjust for the presence of AIR (amoug other thing Air and vacuum have nearly identical permittivity and permeability - the properties which control the impedance of air and of free space and which in turn relate electric field strength to the spatial power density. It sounds to me as though you are simply blowing smoke and have no real understanding of what you just attempted to write. Todd is operating illegally. No amount of bloviating can make that fact go away. Deal with it. If you think that, then complain, if not shut the hell up, bottom line is when the FCC Does (if they every will) come and check it and it's within the rules your going to be the one with eggs on his face. Everyone on here will know it. Todd N9OGL OMEGA ONE RADIO |
#10
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![]() N9OGL wrote: Omega One Radio is back on the air, on 13.556.00 MHz LSB, with a power output of 100 watts. Been listening on and off since the original posting above and NEVER heard it once. Just heard some commercial USB around 13.551 that sounded like marine traffic from Europe. Apart from that, it's been dead air static on 13.556 LSB. Conclusion: Omega One Radio exists in your head. (The phone calls are comming from INSIDE the house folks...) Get help Todd. Or go back to the Legion Hall and drown yer sorrows in those cheap suds at 10:00 AM like the rest of the barstools do.... |
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