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September 11th 03, 03:09 AM

(Tom Bruhns) wrote in message om...
(Garvin) wrote in message . com...
...
If we are talking about only DISSIPATED power, do we have
to say P=Vrms**2/Re(Zo)?

Well, you'll probably find a way to argue about it, but for a long
time a lot of people have been using P=Irms^2*Re(Z). Note that that
equation does NOT tell you where the power actually ends up.

Well, the Re(z) part makes a bit of sense.

If you want dissipated power in a TEM line, then P=Irms^2*R+Erms^2*G
(at a particular frequency where R and G have fixed values). Since
Irms and Erms are functions of position along the line,

I would dissagree with this last statement. The root mean square
is a type of averaging (not really just the average though), so how
could it be a function of position??

Slick (GArvin)