Thread: Rho = (Zload-Zo*)/(Zload+Zo), for complex Zo
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Old September 23rd 03, 07:14 AM
Richard Clark
 
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On Mon, 22 Sep 2003 22:49:22 -0500, Cecil Moore
wrote:
So what?

Hi Cecil,

Exactly, you don't have a clue by how much do you?

73's
Richard Clark, KB7QHC
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