Revisiting the Power Explanation
On 23 Mar 2007 09:21:07 -0700, "Dr. Honeydew"
wrote:
Thank you, Mr. Clark. But I'm having trouble reconciling what you
wrote with what Mr. Harrison posted about the output impedance being
equal to the conjugate of the load which dissipates the most power.
Clearly the 40 ohm load dissipates more power than the 50 ohm load, so
we don't see how your answer and Mr. Harrison's posting can both be
correct.
It is a problem of apples and oranges. Your source is not
representative of either a commercial transmitter, nor a amateur
transmitter. It is a precision source. It has no need to exhibit
impedance matching, and is thus not designed to perform that purpose.
It is happy to run quite inefficiently as efficiency is a discardable
quality. Rather, it is incumbent upon you to enforce matching by
careful load selection. Otherwise, its utility is wasted and makes it
a rather expensive choice for a general purpose signal generator.
73's
Richard Clark, KB7QHC
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