Keith Dysart wrote:
So using the same 12.5 ohm example,
X.inst = 50 + 50 cos(2wt)
Y.inst = 18 + 18 cos(2wt)
X.inst + Y.inst = 68 + 68 cos(2wt)
Where do you take into account that the forward wave
is 90 degrees out of phase with the reflected wave?
Z.inst = 68 + 68 cos(2wt - 61.9degrees)
Where does the 61.9 degrees come from?
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73, Cecil
http://www.w5dxp.com