On Dec 29, 2:36*am, Art Unwin wrote:
Gauss's boundary contains static particles

not in YOUR world where you have added a time dependency to his law.


Faraday cage contains static particles

Faraday doesn't care about particles


Both have a boundary that is conductive and thus can radiate.

Both radiate when a time varying field is applied

both have a boundry, this is true. Faraday cages are conductive and
could radiate if properly excited. But gaussian surfaces are
conceptual and have not physical manifestation so can not be
conductive nor radiate, though radiative fields could pass through
them.


Both receive when transformed into a time varying field
provided when the magnetic and electric moves to cancellation

I have no idea what this means.


Both are applicable to Maxwell's equations for radiation

Gaussian surfaces are part of maxwell's equations by his inclusion of
Gauss's law. the Faraday cage is a result of the effects of maxwell's
equations in a practical application.


Both start and finish with a time varient current.

Both produce a charge by accelerating or removal of a charge via
deceleration of a particle.

Only after YOU add the time factor to Gauss's law.



The accelerant in both cases is the intersection of two closed fields.
( Electric field and a static field encircled by
the displacement current)

I would like to see how you encircle a static field (which by
definition must be infinite in extent) by a displacement current.


In both cases the particle has a straight line projection with spin

In both cases the particle vector angles equate exactly with that of
gravity and the Earth's rotation

right, maybe in your twisted world.


Question * *;
How does the particle ( singular) referred to in each case act like a
wave or become a wave as stated in Classical Physics?

its all a matter of perspective. quite simple in fact so i'll leave
it as an exercise for the student...
show your work, papers due by 9am tomorrow.