Think "Ohm's Law." The meter movement responds to a current. To read
voltage, you put a resistor in series with the meter movement so that
V(full scale) = R(total)*I(meter, full scale). R(total) is the sum of
the meter's internal resistance and the external series resistor. So
a 1mA meter movement always gives 1kohms/volt, and a 20uA meter
movement gives 50kohms/volt.

Cheers,
Tom

Uwe Langmesser wrote in message ...
Is there a simple relationship between a meters internal resistance and its
sensitivity (ohms per volt).

Maybe this is trivial but I don't see it.

Uwe