Home |
Search |
Today's Posts |
#7
|
|||
|
|||
Think "Ohm's Law." The meter movement responds to a current. To read
voltage, you put a resistor in series with the meter movement so that V(full scale) = R(total)*I(meter, full scale). R(total) is the sum of the meter's internal resistance and the external series resistor. So a 1mA meter movement always gives 1kohms/volt, and a 20uA meter movement gives 50kohms/volt. Cheers, Tom Uwe Langmesser wrote in message ... Is there a simple relationship between a meters internal resistance and its sensitivity (ohms per volt). Maybe this is trivial but I don't see it. Uwe |
Thread Tools | Search this Thread |
Display Modes | |
|
|
Similar Threads | ||||
Thread | Forum | |||
max power transfer theorem | Antenna | |||
Radiation Resistance & Efficiency | Antenna | |||
Internal Resistance (?) | Antenna |