On Jun 25, 5:25*pm, John S wrote:
But, it does. First, it causes the 50 ohms line (looking into the 291.4
ohms line to see a match due to the reflection. Second, the
re-reflection from that discontinuity is half of what maintains the
circulating energy on the line. The other half is the discontinuity of
the non-virtual load.

John, EM wave reflection is what happens to a single wave. EM wave
superposition/interference is what happens between two (or more)
waves. They are not the same phenomenon and do NOT obey the same rules
of physics. Wave cancellation between two waves is *NOT a reflection*
but it does *redistribute* reflected energy back toward the load at
the Z0-match point. The destructive interference energy toward the
source is redistributed as constructive interference energy toward the
load but one can tell from the resulting phase and magnitude that it
was NOT a reflection.

A good reference on the differences between wave reflection and wave
superposition/interference is "Optics", by Eugene Hecht. The
international 4th edition is available in paperback for around $20
from Abebooks.com.
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73, Cecil, w5dxp.com