Richard Clark wrote:
Gene Fuller wrote:

reversing momentum

Imagine the G forces of that for an infinitesmal 1/10¹² second or so.

The pressure of such a momentum change can be calculated.
From "Optics", by Hecht, 4th edition, page 57:
"When the surface under illumination is *perfectly
reflecting*, the beam that entered with a velocity
of +c will emerge with a velocity of -c. This
corresponds to twice the change in momentum that
occurs on absorption, and hence,"

Pressure of a absorbed wave = S(t)/c

Pressure of a reflected wave = 2*S(t)/c
--
73, Cecil http://www.w5dxp.com