Gene Fuller wrote:
Does Hecht really say that more power goes into the glass than enters
the 1/4WL film?

No, and neither did I. The 0.01W of power reflected
in the diagram undergoes destructive interference.
That's why they call it "non-reflective" glass.
The 0.01W is known as the external reflection. There
is a matching 0.01W (not shown) from the internal
reflection that causes wave cancellation. All of this
is explained in any good physics book. If anyone is
willing to go step by step with me, I will either prove
my point or be disproved in the process. What I cannot
figure out is why everyone is avoiding a step by step
technical discussion and instead engaging in ad hominem
comments - hoping to prove what?

By the way, those irradiance equations go back a couple hundred years.
It seems unlikely that Dr. Best was the first to publish them, even
considering only amateur-oriented publications.

Well, I said that was to the best of my knowledge. I
had never seen Ptot = P1 + P2 + 2*SQRT(P1*P2)cos(A)
in an amateur radio publication before and I have
been reading them since 1952.
--
73, Cecil, http://www.qsl.net/w5dxp