Cecil Moore wrote in message ...
Dr. Slick wrote:
Cecil, when are you gonna come out with your 2+2=4 dissertation?

I already did. 2 amps added in phase with 2 amps equals 4 amps flowing
in the same direction. Some people say that 4 amps stands still. Do
you think current can stand still?


The other poster is right. Hint: dQ/dt=current flow. That's the
number of Coulombs that passes a particular plane in a unit of time,
usually seconds.

Hint: In a standing wave ratio, there is still the flow of
coulombs, but it's more like they are sloshing back and forth (AC)
between the high voltage nodes.

But if you measure the _DC_ current at a high voltage node, you
will see that there is none.

But Jesus, you argued about this for a million posts in the past.

Can't you maybe up the complexity to something like 2x3=6?

God, i wonder how long you could argue about that one!


Slick

"Cecil Moore" wrote in message
...
That means when you look at the voltage waveform
across a one ohm resistor, you are also looking at the current
waveform.

Please give an example of when the voltage waveform across a resistor is
*not* due to the current flowing through the resistor.

73, Jim AC6XG

Tdonaly wrote:
You're the victim of sloppy thinking and theorizing, Cecil.

OK, Tom, let's see if you are right. At a point on a transmission line,
the current waveform from a calibrated pickup coil is sinusoidal with
a maximum amplitude of one amp. Are there any standing waves on that
transmission line? With your vast knowledge, you should be able to
answer the question.
--
73, Cecil http://www.qsl.net/w5dxp



-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----

Dr. Slick wrote:
Hint: In a standing wave ratio, there is still the flow of
coulombs, but it's more like they are sloshing back and forth (AC)
between the high voltage nodes.

Uhhhhh Slick, with coulombs sloshing back and forth in an RF environment,
dQ/dt is a sine wave.
--
73, Cecil http://www.qsl.net/w5dxp



-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----

Jim Kelley wrote:

"Cecil Moore" wrote:
That means when you look at the voltage waveform
across a one ohm resistor, you are also looking at the current
waveform.

Please give an example of when the voltage waveform across a resistor is
*not* due to the current flowing through the resistor.

That's the guys on the other side of the argument, Jim, who say coulombs
are sloshing back and forth through that resistor but there is no current.
--
73, Cecil http://www.qsl.net/w5dxp



-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----

----- Original Message -----
From: "Cecil Moore"
Newsgroups: rec.radio.amateur.antenna
Sent: Saturday, February 07, 2004 9:16 PM
Subject: Semantic Nonsense

I already did. 2 amps added in phase with 2 amps equals 4 amps flowing
in the same direction.

You mean both directions. AC doesn't flow in just one direction. That
would be DC.

Some people say that 4 amps stands still.

And one even says that AC moves in one direction. Isn't that silly? :-)

73, Jim AC6XG

Jim Kelley wrote:

From: "Cecil Moore"
2 amps added in phase with 2 amps equals 4 amps flowing
in the same direction.

You mean both directions. AC doesn't flow in just one direction. That
would be DC.

Instantaneous, Jim, instantaneous. AC flows in one direction for 1/2 cycle
and flows in the opposite direction for the other 1/2 cycle. A 2 amp phasor
at zero degrees added to a 2 amp phasor at zero degrees equals 4 amps at
zero degrees, flowing in the same instantaneous direction as the instantaneous
phasor components. When the two component phasors are at 180 degrees, they
and their sum are flowing in the opposite direction.
--
73, Cecil http://www.qsl.net/w5dxp



-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----

Cecil Moore wrote in message ...
Dr. Slick wrote:
Hint: In a standing wave ratio, there is still the flow of
coulombs, but it's more like they are sloshing back and forth (AC)
between the high voltage nodes.

Uhhhhh Slick, with coulombs sloshing back and forth in an RF environment,
dQ/dt is a sine wave.


Errr, Cecil, dQ/dt is zero at the voltage nodes.

Hint: Just like the jump rope doesn't move at the ends...


Slick

Dr. Slick wrote:

Cecil Moore wrote:
Uhhhhh Slick, with coulombs sloshing back and forth in an RF environment,
dQ/dt is a sine wave.

Errr, Cecil, dQ/dt is zero at the voltage nodes.

Nope, not over half a cycle, it isn't (starting at the zero crossing).

Let me get this straight: You are given an instrument for measuring RF
current on a transmission line and the task of measuring current at
a particular point. You measure one amp. Are you telling me you don't
know if that measurement is current or not? If it's at a voltage node,
it's not current????????????? Get real!
--
73, Cecil http://www.qsl.net/w5dxp



-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----

Dr. Slick wrote:
"Err, Cecil, dQ/dt is zero at the voltage nodes."

dQ/dt is the rate of change in electrical charge with respect to time.

Charge moves in synch the applied voltage in a resistance. So, a
sinusoidal voltage node is a point in the cycle where the voltage has
zero amplitude, and so does the current. dQ/dt is hardly zero at zero
crossings of the a-c waveform.

A standing wave node is different. The voltage is always zero at a
complete cancellation type standing wave node because at all points in
the cycle the voltage sum is zero if the node voltage is composed of
equal and oppositely phased waves. The nodal point is a minimum but is
not nescessarily a zero point if the reflected wave is not the equal of
the incident wave.

In the sinewave cycle, zero amplitude occurs at zero crossing points in
time. The rate of change, or slope of the a-c charge movement line is
maximum at zero-crossings, i.e., the change in movement of charges is
most at zero-crossings.

At positive and negative peaks of the sinewave, the slope is zero.

Cecil wrote:
"Nope, not over half a cycle, it isn`t (starting at the zero crossing)."

Cecil is getting at the effective value of an a-c waveform which is rms.

Slick and Cecil are talking about two different things.

Best regards, Richard Harrison, KB5WZI