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#1
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I have recently purchased two different VSWR Bridges.
One was made by Johnson. The second is a clone. Both use a fifty ohm resistor in series with the signal path. This strikes me as a lossy setup. Is there a theory of operation posted or a text which can explain the operation of the bridge? Thanks Harry |
#2
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On 24 Feb 2007 08:35:28 -0800, "harry"
wrote: I have recently purchased two different VSWR Bridges. One was made by Johnson. The second is a clone. Both use a fifty ohm resistor in series with the signal path. This strikes me as a lossy setup. Is there a theory of operation posted or a text which can explain the operation of the bridge? Hi Harry, You don't offer enough information. Some resistance is necessary in the bridge to terminate the sample collected. It is often 50 Ohms, and just as often it is not. The actual value is a product of the bridge configuration. 73's Richard Clark, KB7QHC |
#3
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"harry" wrote in
ups.com: I have recently purchased two different VSWR Bridges. One was made by Johnson. The second is a clone. Both use a fifty ohm resistor in series with the signal path. This strikes me as a lossy setup. Is there a theory of operation posted or a text which can explain the operation of the bridge? Harry, I am not familiar with the specific devices you mention, and you have provided very little info. I have made and used a device for impedance measurement that basically had a 50 ohm resistor between tx and antenna sockets, and three voltmeters to measure the RF voltage across the antenna, the internal 50 ohm resistor, and the combination. To make a measurement, you apply a small amount of power at the desired frequency and measure the three voltages. From those, you can calculate the antenna impedance, though there is ambiguity about the sign of the antenna reactance. If you have such a thing, they are for measurment only, you do not leave them inline because of the losses, and of course, they will only withstand very low power. Do you think you may have such a thing? Owen |
#4
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"harry" wrote in news:1172334927.954451.290220
@q2g2000cwa.googlegroups.com: I have recently purchased two different VSWR Bridges. One was made by Johnson. The second is a clone. Both use a fifty ohm resistor in series with the signal path. This strikes me as a lossy setup. Is there a theory of operation posted or a text which can explain the operation of the bridge? The bridge is indeed a simple bridge with a single null indicator. It is for use with less than 1W of RF, and is not intended to be left inline. ftp://bama.sbc.edu/downloads/johnson/250-24/ Owen |
#5
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On Feb 24, 3:31 pm, Owen Duffy wrote:
"harry" wrote in news:1172334927.954451.290220 @q2g2000cwa.googlegroups.com: I have recently purchased two different VSWR Bridges. One was made by Johnson. The second is a clone. Both use a fifty ohm resistor in series with the signal path. This strikes me as a lossy setup. Is there a theory of operation posted or a text which can explain the operation of the bridge? The bridge is indeed a simple bridge with a single null indicator. It is for use with less than 1W of RF, and is not intended to be left inline. ftp://bama.sbc.edu/downloads/johnson/250-24/ Owen Owen. thanks for the link on the BAMA server. It cleared up a lot of questions. What threw for the loop was the coupler has to be removed one the measurement is completed. I had assumed (and you know what they say about that word) it was like other couplers and remained in circuit. I had not tried either one since obviously the 2 watt resistors were going to go poof, if used like its more modern cousins. I apologize to all for the lack of info and will be more diligent in the future. Harry |
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