Cecil Moore wrote:

On Feb 27, 2:53 am, "Jeff" wrote:

Adding a circulator to a system will not change "the load line" (if a
transmission line or circulator can have such a thing), but it will cause
the power in the reflected wave to be separated so that it can be monitored
and measured. Surprisingly power monitored in this way ties up with the
notion that power is reflected at a mis-matched load.


Yes, and a little modulation added to the source signal will prove
that the
signal being dissipated by the circulator resistor has made a round
trip
to the load and back. That's hard to explain if reflected energy
doesn't
actually exist.
--
73, Cecil, w5dxp.com

Your example is the same as putting a load resistor on an open
transmission line, measuring the dissipated power, and then claiming
the same thing happens without the load resistor there.

ac6xg

Jim Kelley wrote:


Cecil Moore wrote:
Your example is the same as putting a load resistor on an open
transmission line, measuring the dissipated power, and then claiming the
same thing happens without the load resistor there.

No, it is more akin to presenting all the evidence.
Your approach is akin to rolling dice in the dark
where you are the only one allowed to report the
results. :-)

Are you willing to assert that the power being
dissipated in the circulator resistor didn't
make a round trip to the load and back even though
the actual delay is easy to measure?

Do the reflected waves that you see when looking
at yourself in the mirror contain any joules/sec?
--
73, Cecil http://www.w5dxp.com

Cecil Moore wrote:

Are you willing to assert that the power being
dissipated in the circulator resistor didn't
make a round trip to the load and back even though
the actual delay is easy to measure?

How does inserting a circulator load into a circuit that doesn't have
one illustrate anything about energy flow other than the behavior of a
circuit with a circulator load in it?

Do the reflected waves that you see when looking
at yourself in the mirror contain any joules/sec?

You seem to be laboring under a misconception about my point of view,
Cecil. But it can't be for a lack of attempts on my part to persuade
you of it.

73, Jim AC6XG

Jim Kelley wrote:
How does inserting a circulator load into a circuit that doesn't have
one illustrate anything about energy flow other than the behavior of a
circuit with a circulator load in it?

It proves that the reflected energy made a round trip
to the load and back. If there is no such thing as
reflected energy, how is that possible? If it is
possible in a system with a circulator load, why
is it not possible when the circulator load is removed?

You seem to be laboring under a misconception about my point of view,
Cecil. But it can't be for a lack of attempts on my part to persuade
you of it.

This question of yours from another posting gives insight
into what you are trying to say.

how is it that you were able to ascertain that this heat energy
was caused by energy that was reflected from the load rather than
having come directly from the power supply within the source?

How is it that you are able to ascertain that your reflection
in the mirror was caused by reflections rather than having
come directly from your face?
--
73, Cecil, http://www.qsl.net/w5dxp