"John E. Davis" wrote in message
...
On Sat, 10 Mar 2007 20:59:59 GMT, Dave
wrote:
yes, referring to all 4 Maxwell equations you do have a 't' dependency.
however, even equations 1.13 and 1.14 referred to by your quote have NO
time
dependency in them. the equations on the next page,1.15 and 1.16 have the
time dependency that the 't' in your quote refers to. remember, those
integrals are NOT integrals over time, they are over the surface or
volume.

As I stated before, this chapter deals with electrostatics so the time
dependence has been dropped. However, the fact remains that Gauss's
law is the integral form of the first Maxwell equation, which holds
for an arbitrary space-time point. Unless you reject the first
equation, namely

div E(x,t) = 4 \pi \rho(x,t)

or the divergence thereom, you have to accept the fact that

\integral_S E(x,t).dA = 4 \pi \integral_V dV \rho(x,t)

which is Gauss's theorem.

This is my last post regarding this subject.
--John

the later chapter i quoted first is not based on electrostatics, and the
formula for gauss's law is always the same. it is not dependent on time in
any form. thank you for not continuing to prolong the misinformation in
this thread.