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#1
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![]() Lets escape from mixed analysis of VSWR in transient scenarios. Visualise a series circuit of a battery of 100V and negligible internal resistance, a 100 ohm ideal resistor, and an open switch. This circuit is connected to a lossless (ie ideal) transmission line with surge impedance (or characteristic impedance, Zo) of 100 ohms which is open circuit at the far end. It takes T seconds for a wave to travel from one end of the line to the other. The scenario is a source impedance matched to the transmission line, with unmatched load. When the switch is closed, current flows into the line. Until t=2T seconds, the current If that flows into the line equals 100V/(100+100 ohms) = 0.5A, during which time the resistor dissipates heat at the rate of I^2*R = 100W. The voltage of the wave Vf travelling from the source is I*Zo = 50V. This situation is constant until t=2T seconds. At precisely t=T seconds, the wave travelling from the source end reaches the open end of the line, and a reflected wave is established to satisfy the conditions that I at the end of the line must be zero. The reflected wave must have current equal and opposite to the forward wave, so Ir=-If, the negative sign indicates that the wave travels in the opposite direction. Considering the reflected wave, Vr=Zo*Ir = 50V, so the total voltage at the o/c end is Vf+Vr = 50+50 = 100V. At precisely t=2T seconds, the reflected wave reaches the source end of the line, and the voltage at the line terminals instantly becomes Vf+Vr or 100V. At that instant, the current from the source falls to zero, and the dissipation in the source resistor also falls to zero. This situation continues indefinitely. My questions a How much of the energy that was contained in the reflected wave was dissipated in the source resistor? Does existence of a reflected wave necessarily increase dissipation in the equivalent source resistance? Is the reflected wave necessarily absorbed (or partly absorbed) by the equivalent source resistance? Are the principles that apply to this example inconsistent with the general case (eg dc, ac, transient, steady state etc)? One word answers should be sufficient. Owen |
#2
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Owen Duffy wrote:
Lets escape from mixed analysis of VSWR in transient scenarios. Visualise a series circuit of a battery of 100V and negligible internal resistance, a 100 ohm ideal resistor, and an open switch. This circuit is connected to a lossless (ie ideal) transmission line with surge impedance (or characteristic impedance, Zo) of 100 ohms which is open circuit at the far end. It takes T seconds for a wave to travel from one end of the line to the other. At precisely t=2T seconds, the reflected wave reaches the source end of the line, and the voltage at the line terminals instantly becomes Vf+Vr or 100V. At that instant, the current from the source falls to zero, and the dissipation in the source resistor also falls to zero. This situation continues indefinitely. My questions a How much of the energy that was contained in the reflected wave was dissipated in the source resistor? None. Does existence of a reflected wave necessarily increase dissipation in the equivalent source resistance? No. Is the reflected wave necessarily absorbed (or partly absorbed) by the equivalent source resistance? No. Are the principles that apply to this example inconsistent with the general case (eg dc, ac, transient, steady state etc)? Yes. One word answers should be sufficient. Ok. Owen Best, |
#3
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Dan Bloomquist wrote in
: Are the principles that apply to this example inconsistent with the general case (eg dc, ac, transient, steady state etc)? Yes. I would have thought the answer was NO, the principles are *not* inconsistent with the general case. Or did I use too many negatives? Owen |
#4
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Owen Duffy wrote:
Dan Bloomquist wrote in : Are the principles that apply to this example inconsistent with the general case (eg dc, ac, transient, steady state etc)? Yes. I would have thought the answer was NO, the principles are *not* inconsistent with the general case. Hi Owen, See the example I posted where a pulse is sent down the line. In that case all the energy is dissipated in the source resistor. Best, Dan. |
#5
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Cecil Moore wrote in news:96hKh.483$rj1.92
@newssvr23.news.prodigy.net: Owen Duffy wrote: Are the principles that apply to this example inconsistent with the general case (eg dc, ac, transient, steady state etc)? Of course, pure DC principles are not adequate to cover general case distributed network problems. Else, there The principles are those of the behaviour of transmission lines and the theory applying to solving the source circuit. In the 'DC' case, the analysis becomes trivial, but IMHO there were no underlying principles that do not apply in the general case. The example is a specific case of the general, and the outcome that reflected power is not dissipated in the source resistance dissproves any general statement to the contrary. You could devise an example with an AC source that had exactly the same outcome, more complicated mathematics to solve it, but the exactly the same outcome. But you don't need to do that, the example is in the set of the general, and stands against a general statement that power reflected from a source is necessarily dissipated in the source. |
#6
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Owen Duffy wrote in
: You could devise an example with an AC source that had exactly the same outcome, more complicated mathematics to solve it, but the exactly the same outcome. But you don't need to do that, the example is in the set of the general, and stands against a general statement that power reflected from a source is necessarily dissipated in the source. This wasn't so well written, let me move a word around: You could devise an example with an AC source that had exactly the same outcome, more complicated mathematics to solve it, but the exactly the same outcome. But you don't need to do that, the example is in the set of the general, and stands against a general statement that reflected power from a source is necessarily dissipated in the source. Owen |
#7
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Owen Duffy wrote:
You could devise an example with an AC source that had exactly the same outcome, more complicated mathematics to solve it, but the exactly the same outcome. But the point is that I can devise an example with an AC source that has the opposite outcome simply by using a Norton equivalent source. When the reflection arrives, the dissipation doubles. -- 73, Cecil, w5dxp.com |
#8
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Dan Bloomquist wrote in news:4khKh.5006$ya1.3770
@news02.roc.ny: Owen Duffy wrote: Dan Bloomquist wrote in : Are the principles that apply to this example inconsistent with the general case (eg dc, ac, transient, steady state etc)? Yes. I would have thought the answer was NO, the principles are *not* inconsistent with the general case. Hi Owen, See the example I posted where a pulse is sent down the line. In that case all the energy is dissipated in the source resistor. Dan, I don't deny there may be cases where that may happen, but it is not true that reflected power is necessarily dissipated (or partly dissipated) in the equivalent source resistance. Owen |
#9
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Owen Duffy wrote:
Cecil Moore wrote in news:96hKh.483$rj1.92 @newssvr23.news.prodigy.net: Owen Duffy wrote: Are the principles that apply to this example inconsistent with the general case (eg dc, ac, transient, steady state etc)? Of course, pure DC principles are not adequate to cover general case distributed network problems. Else, there The principles are those of the behaviour of transmission lines and the theory applying to solving the source circuit. In the 'DC' case, the analysis becomes trivial, but IMHO there were no underlying principles that do not apply in the general case. But your underlying principle is that the source steps and doesn't change. So any general case where the source is at some different level is now not covered. Best, Dan. |
#10
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Owen Duffy wrote:
Are the principles that apply to this example inconsistent with the general case (eg dc, ac, transient, steady state etc)? Of course, pure DC principles are not adequate to cover general case distributed network problems. Else, there would have been no need to develop the distributed network model. How would your transmission line calculator work if you only used DC principles? For instance, the conditions at the source are opposite between the RF frequency where the feedline length is 1/4WL and the RF frequency where the same feedline length is 1/2WL. Conditions are also opposite depending upon whether a Thevenin equivalent or a Norton equivalent is chosen. Ramo and Whinnery, of "Fields and Waves ..." fame, warn us not to attach any significance to the dissipation within those two equivalent circuits. They are still equivalent even though one is dissipating zero watts and the other is dissipating 200 watts. Even when the impedance is the same between the DC problem and the 1/2WL RF problem, the DC current in the middle of the feedline is zero while the RF current in the middle of the 1/2WL section is at a maximum. -- 73, Cecil, w5dxp.com |
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