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#21
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18:1 all band dipole?
Buck wrote:
Cecil Moore wrote: Please explain your antenna and radio. I am assuming you have a solid state rig with an so-239 connector on it for the basic and then you do what? Hi Buck, Please check out my associated web page and then ask me anything that you don't understand. http://www.w5dxp.com/notuner.htm Contrary to what you may have been told, you can change the 50 ohm SWR seen by your transmitter by changing the length of the 450 ohm ladder-line. -- 73, Cecil http://www.w5dxp.com |
#22
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VSWR doesn't matter? But how about "mismatch loss"?
An understanding of "mismatch loss" doesn't require SWR, reflections,
power waves, "reflected power", "reflected energy", or other real or imagined complexities other than simple impedances. Here's what it means: If you have a generator with a fixed output impedance such as a signal generator, and connect it to a conjugately matched load, the power dissipated in that load is the most you can get in any load connected to the generator. For example, if your generator produces 10 volts RMS open circuit and has a 50 ohm resistive output impedance, it can deliver 0.5 watt to a 50 ohm resistive load. If you connect any other load impedance to the generator, you'll get less power to the load. You can calculate exactly how much with simple circuit theory. "Mismatch loss" is simply a way of expressing the reduction in power you get due to the load being mismatched, compared to how much you'd get with a matched load. For example, if you connect a 100 ohm resistor to the output of the generator, it would dissipate 0.44 watt instead of 0.5, so the mismatch loss is 10 log 0.5/0.44 = 0.51 dB(*). If you connect a 25 ohm resistor to the output, you also get 0.44 watt in the load resistor, again a "mismatch loss" of 0.51 dB. These numbers are calculated using nothing more complicated than simple lumped circuit principles. Mismatch loss is a useful concept when connecting fixed-impedance circuits together, such as in a laboratory environment. But it doesn't apply to either antennas or to VSWR. All you have to do to reduce the "mismatch loss" to zero is to insert a tuner or other matching network between the generator and the load. Presto, the generator sees 50 ohms resistive, the load dissipates 0.5 watt, and the mismatch loss is zero. (*) For the 100 ohm example: The circuit consists of a 10 volt generator, and a 50 ohm resistance (the generator impedance) and 100 ohm resistance (the load) in series. So the current is V / R = 10 / (50 + 100) = 66.67 mA. The power dissipated in the load is I^2 * R = 0.06667^2 * 100 ~ 0.44 watt. No reflections, VSWR, transmission lines, or bouncing power waves required. Roy Lewallen, W7EL billcalley wrote: What I gleaned from the excellent answers for the original "VSWR Doesn't Matter?" thread is that high VSWR doesn't really matter in a lossless transmission line environment between a transmitter's antenna tuner and the antenna, since any reflected RF energy will simply continue to "bounce" back and forth between the tuner's output impedance and the antenna's input impedance until it is, finally, completely radiated from the antenna without loss. But then why does the concept of "mismatch loss" exist in reference to antennas? I have quickly calculated that if a transmitter outputs 100 watts, and the TX antenna has an impedance that will cause a VSWR of 10:1 -- using lossless transmission line -- that the mismatch loss in this "lossless" system would be 4.81dB! (Reflected power 66.9 watts, RL -1.74). Since mismatch loss is the "amount of power lost due to reflection", and is as if an "attenuator with a value of the mismatch loss where placed in series with the transmission line", then I would think that VSWR would *definitely* matter, and not just for highly lossy lines either. But here again, I'm probably not seeing the entire picture here. What am I missing?? Confused! -Bill |
#23
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VSWR doesn't matter? But how about "mismatch loss"?
Roy Lewallen wrote:
An understanding of "mismatch loss" doesn't require SWR, reflections, power waves, "reflected power", "reflected energy", or other real or imagined complexities other than simple impedances. Here's what it means: If you have a generator with a fixed output impedance such as a signal generator, and connect it to a conjugately matched load, the power dissipated in that load is the most you can get in any load connected to the generator. For example, if your generator produces 10 volts RMS open circuit and has a 50 ohm resistive output impedance, it can deliver 0.5 watt to a 50 ohm resistive load. If you connect any other load impedance to the generator, you'll get less power to the load. You can calculate exactly how much with simple circuit theory. "Mismatch loss" is simply a way of expressing the reduction in power you get due to the load being mismatched, compared to how much you'd get with a matched load. For example, if you connect a 100 ohm resistor to the output of the generator, it would dissipate 0.44 watt instead of 0.5, so the mismatch loss is 10 log 0.5/0.44 = 0.51 dB(*). If you connect a 25 ohm resistor to the output, you also get 0.44 watt in the load resistor, again a "mismatch loss" of 0.51 dB. These numbers are calculated using nothing more complicated than simple lumped circuit principles. Mismatch loss is a useful concept when connecting fixed-impedance circuits together, such as in a laboratory environment. But it doesn't apply to either antennas or to VSWR. All you have to do to reduce the "mismatch loss" to zero is to insert a tuner or other matching network between the generator and the load. Presto, the generator sees 50 ohms resistive, the load dissipates 0.5 watt, and the mismatch loss is zero. Bravo. And a great deal simpler to understand than most handwaving on these threads. Roy Lewallen, W7EL Best, Dan. |
#24
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VSWR doesn't matter? But how about "mismatch loss"?
"Cecil Moore" wrote in message . net... bw wrote: Entropy increases Seems to me that evolution violates that principle. -- 73, Cecil http://www.w5dxp.com Not to mention the Noble Prize Ilya Prigogine won for "Dissipative Structures" in 1977. Spontaneous Ordered Structures arising out of disorder. But it takes an Energy Flow to produce them. Robert |
#25
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VSWR doesn't matter? But how about "mismatch loss"?
"Robert" wrote in message link.net... "Cecil Moore" wrote in message . net... bw wrote: Entropy increases Seems to me that evolution violates that principle. -- 73, Cecil http://www.w5dxp.com Not to mention the Noble Prize Ilya Prigogine won for "Dissipative Structures" in 1977. Spontaneous Ordered Structures arising out of disorder. But it takes an Energy Flow to produce them. Robert Sorry. Forgot to include the link. http://en.wikipedia.org/wiki/Ilya_Prigogine Robert |
#26
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VSWR doesn't matter? But how about "mismatch loss"?
On Mar 29, 2:10 pm, "billcalley" wrote:
What I gleaned from the excellent answers for the original "VSWR Doesn't Matter?" thread is that high VSWR doesn't really matter in a lossless transmission line environment between a transmitter's antenna tuner and the antenna, since any reflected RF energy will simply continue to "bounce" back and forth between the tuner's output impedance and the antenna's input impedance until it is, finally, completely radiated from the antenna without loss. There's also the case where a perfect VSWR does no good. That happens when you connect a transmitter to an extremely lossy line and the signal dissipates before it gets to the load : But then why does the concept of "mismatch loss" exist in reference to antennas? I have quickly calculated that if a transmitter outputs 100 watts, and the TX antenna has an impedance that will cause a VSWR of 10:1 -- using lossless transmission line -- that the mismatch loss in this "lossless" system would be 4.81dB! (Reflected power 66.9 watts, RL -1.74). Since mismatch loss is the "amount of power lost due to reflection", and is as if an "attenuator with a value of the mismatch loss where placed in series with the transmission line", then I would think that VSWR would *definitely* matter, and not just for highly lossy lines either. But here again, I'm probably not seeing the entire picture here. What am I missing?? Confused! -Bill |
#27
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18:1 all band dipole?
On Fri, 30 Mar 2007 02:43:38 GMT, Cecil Moore
wrote: Buck wrote: Cecil Moore wrote: Please explain your antenna and radio. I am assuming you have a solid state rig with an so-239 connector on it for the basic and then you do what? Hi Buck, Please check out my associated web page and then ask me anything that you don't understand. http://www.w5dxp.com/notuner.htm Contrary to what you may have been told, you can change the 50 ohm SWR seen by your transmitter by changing the length of the 450 ohm ladder-line. Ok, I have seen that. It isn't that the antenna isn't tuned, it is tuned with the twin-lead instead of a conventional tuner. I might have enough twin lead to build one of those. I'll have to consider it. It has always tweaked my interest. Thanks -- 73 for now Buck, N4PGW www.lumpuckeroo.com |
#28
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18:1 all band dipole?
Buck wrote:
Ok, I have seen that. It isn't that the antenna isn't tuned, it is tuned with the twin-lead instead of a conventional tuner. It has a tuned feeder instead of a conventional tuner. -- 73, Cecil http://www.w5dxp.com |
#29
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18:1 all band dipole?
On Fri, 30 Mar 2007 12:37:53 GMT, Cecil Moore
wrote: Buck wrote: Ok, I have seen that. It isn't that the antenna isn't tuned, it is tuned with the twin-lead instead of a conventional tuner. It has a tuned feeder instead of a conventional tuner. I am curious to know, have you measured the power both at the antenna and the radio to see what loss there might be? I wouldn't expect very much, personally. On a G5RV, it is taught that the twin-feedline is also part of the antenna itself, is that true in your model as well? thanks Buck -- 73 for now Buck, N4PGW www.lumpuckeroo.com |
#30
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All HF Band Feeline Tuned antenna
http://www.w5dxp.com/notuner.htm Cecil, Looking more at your antenna, I am making several observations. I posted the URL at the top for other readers to know what we are talking about. I kind of wish you would change the name of the antenna and not call it 'no-tuner' because I feel let down every time I look at it and see the feed-line tuner. I realize it isn't a conventional tuner. Don't get me wrong, I think it is a GREAT idea and I like it very much and would like to try it myself. However, I feel it is a little deceptive in the name. I have a few questions about the system. I may have asked some already in another thread, so please bear with me. This is a better place to discuss it rather than hijacking another thread. I see you use 450 ohm ladder line (or window-line as some call it.) I am wondering if the concept will also work with other impedance feedline such as 600, 300 or 75 ohm twin-line or even possibly with coax. **** **** I just looked over your program. I see that you have it setup to allow 300 or 450 ohm ladder line. I wonder if you have LLWL available for 600 and 75 ohm.... I will try to put this in XL. (I don't have a basic program.) OK, I just found the compiled program. I am interested in making one, but I only have 300 ohm. Does the feedline act as part of the antenna? I am sure it will, at least up to the 'no-tuner' if it acts like a G5RV, but do you know if the feedline radiates? Have you measured the power at both sides of the 'no-tuner' to see what loss there might be? I doubt there would be much considering that you are using window-line. I see a couple of the frequencies are above 1.5:1, which I am not comfortable going over with solid state rigs. Do you think that could be fine-tuned with the addition of a 1/2 foot section or maybe with that and a 1/4 foot section? Would it be safe to assume that I can create a mono-band dipole, maybe even multi-band - if I am lucky, by fixing the length of the dipole and the feedline such that the increment gives me the imax at the balun for the desired frequency(s)? Finally, you have a 1:1 choke at the feeder. I see that the better quality coax, the more toroids are needed. Would there be a problem with using a foot of RG-58 with the fewer toroids and then connect that to the high-quality line? I suspect that by then the common-mode currents will be gone and there would be minimum loss in such a short strand of lower-grade coax for HF. I doubt there would be a noticeable signal loss. Does the 'no-tuner' feedline need to be spread out. I see from the photo that your 16 foot section is one large loop, I figure it must be close to a four-foot diameter loop. Is there a similar system that would work with a vertical? Thank you, I appreciate your taking time to answer this. I hope many of us can learn from it. Buck N4PGW -- 73 for now Buck, N4PGW www.lumpuckeroo.com |
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