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#1
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Cecil Moore wrote in news
![]() @newssvr21.news.prodigy.net: So does the Superposition Principle give us permission Cecil, would you state the superposition principle as you know it? Owen |
#2
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Owen Duffy wrote:
Cecil, would you state the superposition principle as you know it? I'll just quote Hecht on that. He gives the three dimensional differential wave equation and follows it up with a linear combination of individual waves in an equation that cannot be reproduced here and says, "Known as the *Principle of Superposition*, this property suggests that the resultant disturbance at any point in a medium is the algebraic sum of the separate constituent waves." The unreproducible equation essentially says that the total wave function is equal to the algebraic sum of the individual wave functions. Hecht goes on to treat the forward wave and reflected wave as the "separate constituent waves", something that we have been told by the "reflected waves don't exist" gurus on this newsgroup, is an invalid thing to do. It seems to me that the superposition principle gives us permission to consider the forward and reflected waves separately and "algebraically sum" the results. That is exactly what the S-Paramater analysis is based upon. The S-Parameter analysis considers a1 to be the incident forward wave and a2 to be the incident reflected wave. They are treated separately and then "algebraically summed". -- 73, Cecil http://www.w5dxp.com |
#3
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Cecil Moore wrote in news
![]() @newssvr29.news.prodigy.net: Owen Duffy wrote: Cecil, would you state the superposition principle as you know it? I'll just quote Hecht on that. He gives the three dimensional differential wave equation and follows it up with a linear combination of individual waves in an equation that cannot be reproduced here and says, "Known as the *Principle of Superposition*, this property suggests that the resultant disturbance at any point in a medium is the algebraic sum of the separate constituent waves." The unreproducible equation essentially says that the total wave function is equal to the algebraic sum of the individual wave functions. Hecht goes on to treat the forward wave and reflected wave as the "separate constituent waves", something that we have been told by the "reflected waves don't exist" gurus on this newsgroup, is an invalid thing to do. It seems to me that the superposition principle gives us permission to consider the forward and reflected waves separately and "algebraically sum" the results. That is exactly what the S-Paramater analysis is based upon. The S-Parameter analysis considers a1 to be the incident forward wave and a2 to be the incident reflected wave. They are treated separately and then "algebraically summed" Cecil, this is not a complete definition, and you have not related it to the subject under discussion, tranmission lines, and the quantities that are being discussed. To my mind, there is nothing in YOUR definition above (it is not Hecht's, it is your partical quote and elaboration) that states that it is valid to sum energy waves or power waves (whatever those terms mean) as you seem to want to do, or to treat them independently if that is what 'separately' means as you use it, or the specifics of what quantities are summed. Several people have been freely writing expressions that take the algebraic sum of phasor quantities Vf and Vr, and If and Ir. You are citing and partially quoting obscure sources not directly relevant to the subject to justify your summation of energy waves or power waves or whatever you are calling them today. Sit down and write a complete definition of your knowledge of the "Superposition Principle" as you understand it using quantities encountered in a transmission line analysis, like voltage, current, power. Owen |
#4
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Owen Duffy wrote:
To my mind, there is nothing in YOUR definition above (it is not Hecht's, it is your partical quote and elaboration) that states that it is valid to sum energy waves or power waves (whatever those terms mean) as you seem to want to do, or to treat them independently if that is what 'separately' means as you use it, or the specifics of what quantities are summed. Here is the way one sums the power in two energy waves. This is one of the things that Dr. Best, ve9srb, got right in his Nov/Dec 2001 QEX article, "Wave Mechanics of Transmission Lines, Part 3: Power Delivery and Impedance Matching". This article is what got me to thinking along my present lines. Ptotal = P1 + P2 + 2*SQRT(P1*P2)cos(A) where A is the phase angle between the two energy waves. This is the same as the irradiance equation from the field of optics and applies perfectly to transmission lines. The first time I saw the equation was in Dr. Best's QEX article so I certainly cannot take credit for it. All this information has been available on my web page for years. -- 73, Cecil http://www.w5dxp.com |
#5
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On Mar 30, 9:40 pm, Cecil Moore wrote:
Here is the way one sums the power in two energy waves. This is one of the things that Dr. Best, ve9srb, got right in his Nov/Dec 2001 QEX article, "Wave Mechanics of Transmission Lines, Part 3: Power Delivery and Impedance Matching". This article is what got me to thinking along my present lines. Ptotal = P1 + P2 + 2*SQRT(P1*P2)cos(A) Curiosity question: Which of the two possible values for the square root did you use? Elaborate on the reasons for your choice? ....Keith |
#6
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Owen Duffy wrote in
: .... Hecht's, it is your partical quote and elaboration) that states that How did that 'c' get in there? Should have been: Hecht's, it is your partial quote and elaboration) that states that |
#7
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On Mar 30, 3:44 pm, Cecil Moore wrote:
So does the Superposition Principle give us permission to analyze the forward wave and the reflected wave separately, or not? It would appear from the many posts that the consensus is that superposition is alive and well. It works for voltages and currents. It does not work for power. But then I have two questions. Firstly, in another thread, the solution for the problem presented required knowing the impedance that the generator presented to the reflected wave. This is exactly the sort of question that superposition handles easily: The impedance encountered by the reflected wave at the generator is the same as the generator's source impedance. I am curious as to why you don't want to use superposition to facilitate solving this problem? Secondly, the "directional wattmeter" uses superposition to compute Vf and Vr from which it computes Pf and Pr. You, like many others seem willing to subtract Pr from Pf to obtain Pnet. But this would only seem to be valid if superposition works for power. So why are people who accept that superposition does not work for power, prepared to accept that Pnet = Pf - Pr? ....Keith |
#8
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Keith Dysart wrote:
The impedance encountered by the reflected wave at the generator is the same as the generator's source impedance. No, the generator's source impedance is *NOT* the impedance encountered by the reflected wave. Please reference w2du's article again. http://www.w2du.com/r3ch19a.pdf Forget about the conjugate match and concentrate on the non-dissipative source resistance being different from what you are calling the generator's source impedance. An *active* source creates a source impedance looking back into the source that is *different* from what you are calling the generator impedance. Secondly, the "directional wattmeter" uses superposition to compute Vf and Vr from which it computes Pf and Pr. You, like many others seem willing to subtract Pr from Pf to obtain Pnet. One can directly add and subtract powers under certain conditions. One condition is if two waves are not coherent. Another condition is if two coherent waves have no effect on each other. Since the forward wave and the reflected wave have no effect on each other (except in the human mind) reflected power can simply be subtracted from from forward power to obtain power delivered to the load but that is NOT superposition of powers. It is a simple addition/subtraction of scalars based on the conservation of energy principle. But this would only seem to be valid if superposition works for power. So why are people who accept that superposition does not work for power, prepared to accept that Pnet = Pf - Pr? You seem to have forgotten the definition and rules of superposition. Superposition applies to fields and waves. Superposition doesn't apply to scalars. Power is a scalar. Or another way to express it is: V1 + V2 = V3 (vectors or phasors) (V1 + V2)^2 = V3^2 (scalars) V1^2 + V2^2 V3^2 (scalars) It's a pretty simple principle of mathematics. The square of the sum is NOT equal to the sum of the squares. -- 73, Cecil http://www.w5dxp.com |
#9
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Cecil Moore wrote:
V1 + V2 = V3 (vectors or phasors) (V1 + V2)^2 = V3^2 (scalars) In fact, the irradiance (power) equation falls out directly from the above valid equation. Continuing the process: V1^2 + 2(V1)(V2) + V2^2 = V3^2 V1^2 + 2*SQRT(V1^2)*SQRT(V2^2) + V2^2 = V3^2 V1^2 + V2^2 + 2*SQRT(V1^2*V2^2) = V3^2 Dividing both sides of the equation by Z0 yields: P1 + P2 + 2*SQRT(P1*P2) = P3 There you have it. The mathematical derivation of the irradiance (power) equation. -- 73, Cecil http://www.w5dxp.com |
#10
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Cecil Moore wrote:
P1 + P2 + 2*SQRT(P1*P2) = P3 There you have it. The mathematical derivation of the irradiance (power) equation. This is, of course, for the condition where V1 and V2 are in phase. -- 73, Cecil http://www.w5dxp.com |
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