Home |
Search |
Today's Posts |
#2
![]() |
|||
|
|||
![]()
On Apr 1, 2:38 pm, Owen Duffy wrote:
I am intrigued that many people have attempted to measure the equivalent source impedance of a transmitter with such varying results. On the one hand is the assertion that a transmitter adjusted for optimum operation is comparable with a linear source, and the source impedance must therefore be the conjugate of the load. .... I have a lot of trouble with that one, especially the "must therefore" part. What is "optimum operation"? Is it delivering the most power to the load, or is it delivering the RATED power to the load, at some particular efficiency and level of distortion? I'd claim it's the latter. There are lots of examples of "optimum" load NOT being "conjugate- matched" load. A typical stereo amplifier has an output impedance that's a fraction of an ohm, but the amplifier is optimized to deliver power to loads in the vicinity of 4 to 8 ohms, most often. The power lines delivering power to a home show a source impedance that's a tiny fraction of an ohm, but with everything in the house turned on, the net load might be as low an an ohm--in rare cases a bit less than an ohm. The load placed on a typical battery is similarly many times the battery's internal resistance, except in the case of a heavy load on a battery near the end of its charge. And lest you think that all sources are optimized for load resistances higher than the source resistance, I can change the feedback on that stereo amplifier without changing the power output stage design, so the amplifier is still best at delivering power to loads in the 4-8 ohm range, but now the output impedance with new feedback is around 100 ohms. So WHY should we expect a transmitter to represent a source impedance particularly close to the load impedance, or to its complex conjugate? I've gone through analyses similar to what you what you reported in the remainder of your posting, with an output network whose Q I varied (in the analysis), and come to similar conclusions. Just as you say, Owen, when I do that, it's all clear and not magical at all. And the source resistance can be made to be what I want through feedback, if I wish. In some of the work I do, it's important to have a virtual ZERO impedance at a particular node, but that's generally done using an AGC loop, so the very short term dynamic impedance at that node may be something considerably different from zero. But if you do power measurements with varying loads, it will appear that the impedance there is very close to zero. (Then you can put a 50 ohm resistor from that node to a precision 50 ohm line, and have a very good 50 ohm source; you can put another 50 ohm resistor from that node to another line and have two matched sources, for testing other circuits...part of a vector network analyzer.) Cheers, Tom |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
measuring impedance - I and V phase, or forward and reflectedsignal | Antenna | |||
measuring impedance - I and V phase, or forward and reflectedsignal | Antenna | |||
measuring impedance through a balun ? | Antenna | |||
Measuring RF output impedance | Homebrew | |||
Measuring RF output impedance | Homebrew |