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#1
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The point I was trying to make on the "Rotational Speed"
thread got lost in semantics so here goes again. Given - a 75m dipole modeled by EZNEC with 90 segments in each leg of the dipole. 90 segments was chosen to correspond to the number of degrees from the feedpoint. Illustrating 1/2 of the dipole with 0 ohm loads at the following segments: FP--------23--------46--------68--------90 EZNEC reports the following results: Feedpoint current: 1 amp at 0 deg Current at seg 23: 0.9281 amp at -1.06 deg Current at seg 46: 0.7154 amp at -1.78 deg Current at seg 68: 0.4049 amp at -2.31 deg Current at seg 90: 0.0122 amp at -2.76 deg Since the segment numbers correspond to the number of degrees, it's obvious that the segment numbers correspond to the expected phase shift in the traveling waves. Question: Assuming the current reported by EZNEC is a ~cosine function, how does one use that current to determine the traveling wave phase shift in the wire? -- 73, Cecil http://www.w5dxp.com |
#2
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![]() "Cecil Moore" wrote in message ... The point I was trying to make on the "Rotational Speed" thread got lost in semantics so here goes again. Given - a 75m dipole modeled by EZNEC with 90 segments in each leg of the dipole. 90 segments was chosen to correspond to the number of degrees from the feedpoint. Illustrating 1/2 of the dipole with 0 ohm loads at the following segments: FP--------23--------46--------68--------90 EZNEC reports the following results: Feedpoint current: 1 amp at 0 deg Current at seg 23: 0.9281 amp at -1.06 deg Current at seg 46: 0.7154 amp at -1.78 deg Current at seg 68: 0.4049 amp at -2.31 deg Current at seg 90: 0.0122 amp at -2.76 deg Since the segment numbers correspond to the number of degrees, it's obvious that the segment numbers correspond to the expected phase shift in the traveling waves. Question: Assuming the current reported by EZNEC is a ~cosine function, how does one use that current to determine the traveling wave phase shift in the wire? -- 73, Cecil http://www.w5dxp.com What is the current phase relative to. The feedpoint , the voltage in that segment? As I have read this thread there seems to be some confusion on this point. |
#3
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Jimmie D wrote:
"Cecil Moore" wrote in message ... The point I was trying to make on the "Rotational Speed" thread got lost in semantics so here goes again. Given - a 75m dipole modeled by EZNEC with 90 segments in each leg of the dipole. 90 segments was chosen to correspond to the number of degrees from the feedpoint. Illustrating 1/2 of the dipole with 0 ohm loads at the following segments: FP--------23--------46--------68--------90 EZNEC reports the following results: Feedpoint current: 1 amp at 0 deg Current at seg 23: 0.9281 amp at -1.06 deg Current at seg 46: 0.7154 amp at -1.78 deg Current at seg 68: 0.4049 amp at -2.31 deg Current at seg 90: 0.0122 amp at -2.76 deg Since the segment numbers correspond to the number of degrees, it's obvious that the segment numbers correspond to the expected phase shift in the traveling waves. Question: Assuming the current reported by EZNEC is a ~cosine function, how does one use that current to determine the traveling wave phase shift in the wire? What is the current phase relative to. The feedpoint , the voltage in that segment? As I have read this thread there seems to be some confusion on this point. I believe that EZNEC references net current to the source current of 1A at 0 degrees. I consider it to be a *snapshot* of conditions when the source current is 1A at 0 degrees. This is what I have been assuming in all of my postings. I believe that is also what Kraus does in his graphs. -- 73, Cecil http://www.w5dxp.com |
#4
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On Apr 28, 9:36 am, Cecil Moore wrote:
Question: Assuming the current reported by EZNEC is a ~cosine function, how does one use that current to determine the traveling wave phase shift in the wire? Why is the answer to this question important? Is it not the actual currents and voltages that are responsible for radiation? If I understand correctly, you are not disputing that the actual currents in the wire show a small phase shift as you move down the wire? ....Keith |
#5
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Keith Dysart wrote:
On Apr 28, 9:36 am, Cecil Moore wrote: Question: Assuming the current reported by EZNEC is a ~cosine function, how does one use that current to determine the traveling wave phase shift in the wire? Why is the answer to this question important? Because it holds the key to determining the phase delay through a 75m mobile loading coil. -- 73, Cecil http://www.w5dxp.com |
#6
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Cecil Moore wrote:
The point I was trying to make on the "Rotational Speed" thread got lost in semantics so here goes again. Given - a 75m dipole modeled by EZNEC with 90 segments in each leg of the dipole. 90 segments was chosen to correspond to the number of degrees from the feedpoint. Illustrating 1/2 of the dipole with 0 ohm loads at the following segments: FP--------23--------46--------68--------90 EZNEC reports the following results: Feedpoint current: 1 amp at 0 deg Current at seg 23: 0.9281 amp at -1.06 deg Current at seg 46: 0.7154 amp at -1.78 deg Current at seg 68: 0.4049 amp at -2.31 deg Current at seg 90: 0.0122 amp at -2.76 deg Since the segment numbers correspond to the number of degrees, it's obvious that the segment numbers correspond to the expected phase shift in the traveling waves. Question: Assuming the current reported by EZNEC is a ~cosine function, how does one use that current to determine the traveling wave phase shift in the wire? Cecil, So soon we forget. In a standing wave antenna the phase is gone, kaput. I believe you have even quoted me on occasion when it was convenient for the purpose you had at the moment. Since the traveling wave phase exists only in your imagination, just pick a number that supports whatever you are trying to "prove" now. 73, Gene W4SZ |
#7
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Gene Fuller wrote:
So soon we forget. In a standing wave antenna the phase is gone, kaput. I believe you have even quoted me on occasion when it was convenient for the purpose you had at the moment. And it is again convenient to quote you: The only "phase" remaining is the cos (kz) term, which is really an amplitude description, not a phase. You also have said that all the phase information is still there, that superposition doesn't destroy any information. I believe you. The standing wave current is a cosine function. The arc-cosine of the amplitude yields the phase of the component waves. Since the traveling wave phase exists only in your imagination, just pick a number that supports whatever you are trying to "prove" now. The point is that this is the very current that Roy used to "measure" the phase shift through a loading coil. I agree with you that standing wave current cannot be used to measure the phase shift through a loading coil. Now if you will tell that technical fact to Roy, he can withdraw his previous assertions. It seems that you are contradicting yourself by saying that all the information in the component waves is still there after superposition yet you say the phase is gone. Both statements cannot be true. -- 73, Cecil http://www.w5dxp.com |
#8
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Cecil Moore wrote:
It seems that you are contradicting yourself by saying that all the information in the component waves is still there after superposition yet you say the phase is gone. Both statements cannot be true. Cecil, Both statements are true. Superposition does not favor one description over the other. If there is no phase information remaining in the superposed result (the standing wave) then there is no phase information remaining at all, regardless of your mathematical manipulations. There are no hidden variables. Someone else recently pointed out that Mother Nature does not care what models we use; the underlying physical reality will be the same. You continue to try to get around that fundamental principle, but it won't work. 73, Gene W4SZ |
#9
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Gene Fuller wrote:
Cecil Moore wrote: It seems that you are contradicting yourself by saying that all the information in the component waves is still there after superposition yet you say the phase is gone. Both statements cannot be true. Both statements are true. Superposition does not favor one description over the other. If there is no phase information remaining in the superposed result (the standing wave) then there is no phase information remaining at all, regardless of your mathematical manipulations. There are no hidden variables. But you said (and for some unknown reason trimmed): The only "phase" remaining is the cos (kz) term, which is really an amplitude description, not a phase. I agree with you. The phase of the underlying forward and reflected traveling waves can be deduced from the *amplitude* of the standing wave. Here is a graphic excerpted from the recently available PDF 1st edition of "Antennas" by Kraus. EZNEC can also be used with the same results. http://www.w5dxp.com/krausdip.jpg As you can see, the current amplitude is a ~cosine function. The phase of the forward traveling wave relative to a source wave of 1.0 amp at 0 degrees (EZNEC standard) is an ARC-COSINE function of the current amplitude. For instance, at 45 degrees away from the feedpoint, the current is ~0.707 amps. ARC-COSINE of 0.707 is 45 degrees. You were correct when you said that the information in the forward and reflected waves is preserved in the standing waves. Kraus' graphic proves it. But it has yet to be explained how Roy (and Tom R.) could use the essentially unchanging *phase* of the standing wave current to "measure" the phase shift through a loading coil - since the phase of the standing wave current cannot even be used to determine the phase shift through a wire. This question has been asked many times. The absence of an answer stands out like a sore thumb. Roy said: What I measured was a 3.1% reduction in magnitude from input to output, with no discernible phase shift. Of course there was no discernible phase shift as can be seen from Kraus' graphic above. But Kraus' graph gives us a way to deduce the phase shift from the amplitudes. Assuming a reference amplitude of 1.0 amp at the bottom of the coil, a 3.1% reduction would give us 0.969 amps at the top of the coil. ARC-COSINE(0.969) = 14.3 deg. That's a close approximation of the phase shift through the coil being undergone by the forward current and reflected current. If the forward current at the bottom of the coil is 0.55A @ 0 deg, and the reflected current at the bottom of the coil is 0.45A @ 0 deg, the total current at the bottom of the coil is 1.0A @ 0 deg. With a 14.3 degree phase shift through the coil, the forward current at the top of the coil would be 0.55A @ -14.3 deg and the reflected current would be 0.45A @ +14.3 deg. Adding those two phasors together yields 0.55A*cos(-14.3) + 0.45A*cos(+ 14.3) = 0.533A + 0.436A = 0.969A at the top of the coil. 0.969A is 3.1% lower than the 1.0 amp at the bottom of the coil. Everything is perfectly consistent with a 14.3 degree phase shift through the coil for the two traveling waves. -- 73, Cecil http://www.w5dxp.com |
#10
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Cecil Moore wrote:
But it has yet to be explained how Roy (and Tom R.) Cecil, I don't post under an alias. My name is neither Tom nor Roy. I have never attempted to measure the phase shift in a loading coil. See you the next time you try to practice physics without a license. 8-) 73, Gene W4SZ |
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