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#20
May 10th 07, 08:30 PM
posted to rec.radio.amateur.antenna
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Electron ratio to form a radiation field
Particels of what?
On May 9, 6:44 pm, art wrote: On 9 May, 17:37, Cecil Moore wrote: art wrote: What is the ratio of magnetic electrons emitted from a radiator compared with with the number of electrons emmitted due to current flow? Art, emitted electrons are corona discharges. What is emitted from an antenna is primarily photons. Each photon has both electric and magnetic properties and the ratio is 377 ohms in the far field. -- 73, Cecil http://www.w5dxp.com Cecil, When power is supplied there are two vectors formed by particles that are emitted from the radiator. I am looking for the ratio of particals emitted. You can call them photons, electrons, particles or what ever is fine by me. The second question is related to the flow or movement of these particles from the enclosed surface to the outside of the surface ( I will call this an arbitary boundary unless there is cries of disagreement). The passage of the two types of particles thru the boundary allows for the combination of their individual energies to form a radiated field. Thus I was asking what the ratio of one type of particle to the other type of particle is required to do that. Obviously if the combination is created by collision it would appear that the ratio is 1:1 but I do not know personally how the combination occurrs. I understand that the electrons change wavelength to break away from the gravitational field (equilibrium) at the parting point and then change back to the originating wavelength at or before the formation of the radiating field. If this is correct then the number of electrons if any that do NOT escape from the enclosed surface have to be accounted for UNLESS ALL ESCAPE which would infer an equal ratio of electron emmissionfor the formation of a radiative field. If the initial ratio is not equal then obviously the rest will return to the initial gravitational field possibly to form a skin depth since the velocity of return is the same as the initiating velocity. Hopefully the above will apply a clue as to where I am comming from. Regards Art |
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