John Smith I wrote:

[stuff]

In the previous post, 1 mm wire is #18 gauge AWG. (#12 = ~2 mm)

And, every 6 gauge decrease results in a doubling of the wires diameter,
every 3 gauge decrease results in a doubling of the wires cross
section--just as for db in signal levels ...

JS

John Smith I wrote:

Further, I meant to point out that 100% skin depth only occurs to
~17Khz. And, while #18 may be ok for a max of 16 amps when used in
chassis wiring, it is only rated at ~2.3 amps for power transmission ...

Anyone know how many amps commonly flow through a current node on a 1/4
or 1/2 wave ant? Now, that's the real question, isn't it? And, if all
that power is all concentrated in just the skin of the copper, wouldn't
there be a degradation of power handling directly related to frequency?

Regards,
JS

John Smith I wrote:
Anyone know how many amps commonly flow through a current node on a 1/4
or 1/2 wave ant? Now, that's the real question, isn't it?

John, you should be talking about the current anti-node,
i.e. the current maximum, not the current node (minimum).
For a 1/2WL center-fed dipole or a 1/4WL monopole, the
current is maximum at the feedpoint which is easy to
calculate, e.g. 1.414 amps for 100 watts into 50 ohms.
--
73, Cecil http://www.w5dxp.com

Cecil Moore wrote:

...
calculate, e.g. 1.414 amps for 100 watts into 50 ohms.

Cecil:

Then, since E = I*R, 70.7 volts ... thanks.

Still, I like my 1/4 copper tubing, silver would be better ...

Regards,
JS

Then, since E = I*R, 70.7 volts ... thanks.

But on the other ends where there could be 6000 ohms the current is
low (0.13 A) but the voltage is around 775 V.

Andrea
IZ2LSC

Andrea wrote:
Then, since E = I*R, 70.7 volts ... thanks.

But on the other ends where there could be 6000 ohms the current is
low (0.13 A) but the voltage is around 775 V.

Andrea
IZ2LSC


Exactly, tape a ne-2 bulb on the antenna, will light when you xmit ...

JS

Andrea wrote in news:1181394846.390221.30080
@c77g2000hse.googlegroups.com:


Then, since E = I*R, 70.7 volts ... thanks.

But on the other ends where there could be 6000 ohms the current is
low (0.13 A) but the voltage is around 775 V.

Something tells me we're going to end up with tapered wires here
pretty soon... ;^)

One more thing is not clear to me:
If I use a 1/4 wave wire, where are the 6000 ohms?
Near the feed point or on the far end?

Thanks

Andrea
IZ2LSC


On Jun 9, 11:44 pm, Mike Coslo wrote:
Andrea wrote in news:1181394846.390221.30080
@c77g2000hse.googlegroups.com:



Then, since E = I*R, 70.7 volts ... thanks.

But on the other ends where there could be 6000 ohms the current is
low (0.13 A) but the voltage is around 775 V.

Something tells me we're going to end up with tapered wires here
pretty soon... ;^)