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#1
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![]() "Cecil Moore" wrote in message ... Dave wrote: you don't even need reflections. a properly terminated piece of wire has a different current at every point along the wire. That's true but the attenuation factor in one foot of wire might be hard to measure. Introduce reflections and even a lossless wire will vary the current from max to min every few inches at GHz frequencies. -- 73, Cecil http://www.w5dxp.com you don't need any loss either. a properly matched lossless line will have different current at each point along the line. |
#2
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Dave wrote:
you don't need any loss either. a properly matched lossless line will have different current at each point along the line. Different RMS current? -- 73, Cecil http://www.w5dxp.com |
#3
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Dave wrote:
"You don`t even need reflections. A properly terminated piece of wire has a different current at every point along the wire." Instantaneous values, of course. But, proper termination means no reflection. The only source of variation along a line other than attenuation is reflection. In a uniform line, attenuation causes a steady decline of energy as energy travels. With a lossless line, properly terminated, variation of rnergy along a line is only the phase produced instantaneois values along the line. These are resolved during the period of a cycle by the root mean square calculation. Best regards, Richard Harrison, KB5WZI |
#4
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![]() "Richard Harrison" wrote in message ... Dave wrote: "You don`t even need reflections. A properly terminated piece of wire has a different current at every point along the wire." Instantaneous values, of course. But, proper termination means no reflection. The only source of variation along a line other than attenuation is reflection. In a uniform line, attenuation causes a steady decline of energy as energy travels. With a lossless line, properly terminated, variation of rnergy along a line is only the phase produced instantaneois values along the line. These are resolved during the period of a cycle by the root mean square calculation. Best regards, Richard Harrison, KB5WZI and what is wrong with instantaneous values? lacking a requirement to talk in peak, phasor, rms, or some other averaging method it is perfectly valid to assume instantaneous measurements. and if I remember right we were talking of measuring current, not energy. and time is a valid parameter when measuring current, just hook up your o-scope and measure away... measure that current on each end of a wire, or coil, or coax, with a dual trace scope and see the difference! throw away that silly-wire-reader thing and get back to the basics. get a pulse generator and build yourself a reflectometer and make use of those reflections! |
#5
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Dave wrote:
and what is wrong with instantaneous values? Nothing if presented as part of the context, confusing if not since most people would assume the context is RMS. Do I have 110v AC in my house? You can argue that the answer is "no" but you would need to state the context. -- 73, Cecil http://www.w5dxp.com |
#6
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![]() Richard Harrison wrote: Dave wrote: "You don`t even need reflections. A properly terminated piece of wire has a different current at every point along the wire." Instantaneous values, of course. But, proper termination means no reflection. The only source of variation along a line other than attenuation is reflection. The only electromagnetic currents 'flowing' on a transmission line are the currents which result from the reflected and/or the forward electromagnetic waves. Neither of these currents varies periodically along the line (except as noted, instantaneously). 73, ac6xg |
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