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On Thu, 08 Nov 2007 00:40:50 +0000, MRW wrote:
I'm not sure where else to ask this question, but I guess since this group deals with antennas then maybe you guys are familiar with this. This is regarding HDTV broadcast: "Because of the 6 MHz. channel bandwidth allocated, each channel will only support a data rate of 19.2 Mb/sec." How is 19.2Mb/sec calculated? Thanks! I would guess that with the 8vsb modulation schema that was selected, they took the maximum cymbal rate that would fit into a 6Mhz channel, then selected a FEC rate that would sustain a reliability link budget. This dictated the bitrate of 19392659bps http://www.broadcast.net/~sbe1/8vsb/8vsb.htm http://en.wikipedia.org/wiki/8VSB#Bi...ission_systems Other modulation schemes exists that would fit into a 6Mhz channel such as 256QAM but theory dictates that the higher the bitrate, the more energy per bit that is required at the receive end to make a usable signal. |
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