Roy Lewallen wrote:
This is simply a diversion to deflect the discussion away from the
sticky questions about "electrical degrees" which his theory is unable
to resolve. Phase reference is another, and we can expect more.

There were no black boxes in the original example so the
black box was the original diversion. Coming back from that
diversion, can you calculate the current amplitude and phases
in the original example? I would be very surprised if you
could do it. I would be even more surprised if you did it
and published the results. Roy, here's your chance to nail
me to the wall. Simply prove that the phase shift between
Vfor1 and Vfor2 below is something other than 36.6 degrees.
(All of Roy's worshipers hold their breath for a response. :-)

This is not "my" theory - this is standard distributed
network reflection theory that I learned at Texas A&M
in the 50's. And the theory is certainly capable of
resolving the electrical degree problems.

Here's the original example again - no black box necessary.

--43.4 deg 600 ohm line--+--10 deg 100 ohm line--open
Vfor1--|--Vfor2

Assuming 100v at 0 deg incident upon the open at the
end of the stub, what is the phase shift between
Vfor1 and Vfor2?

Vfor2 = 100v at -10 deg
Vfor1 = 143.33v at -46.4 deg

The phase shift between Vfor1 and Vfor2 is 36.6 degrees just
as predicted originally. Roy, you are always advising me to
use voltages so I did. The results are easy to verify if you
know how. But I don't think you know how.

Everyone is invited to use any valid model you want to and
prove me either right or wrong.

I predict that Roy will be silent on this subject and rely
on his political power to try to suppress those results.
The emperor has no clothes. The emperor's worshipers have
no clothes.
--
73, Cecil http://www.w5dxp.com