John Smith wrote:
Cecil Moore wrote:

---43.4 deg 600 ohm line---+---10 deg 100 ohm line---open

---43.4 deg 300 ohm line---+---10 deg 50 ohm line---open

So how long does the 600 ohm line have to be in the following
example for the stub to exhibit 1/4WL of electrical length?

---??? deg 600 ohm line---+---10 deg 50 ohm line---open

Strange, for the 600/100/10 degree I get:

Arctan(100\600)*(1/tan(10)) = 53.6635

for 300/50/10 degree:

Arctan(50\300)*(1/tan(10)) = 53.6635

and for 600/50/10 degree:

Arctan(50\600)*(1/tan(10)) = 27.0160

What am I missing here?

Your calculator is not missing anything. Hard to
tell what you are missing. :-)

Arctan(50\600)*(tan(80)) still equ 27.0160

Don't tell me the calc is on the fritz!

Nope, but your brain seems to be. Everything
above is correct.
--
73, Cecil http://www.w5dxp.com

Cecil Moore wrote:

...
Nope, but your brain seems to be. Everything
above is correct.

Cecil:

Oh gesus, that ain't the half of it, I won't bore you with details!

Thanks for the double check ... between the smith chart and attempting
to apply Ryeburns' input and attempting to work out maths' to figure
loading coil impedances in a useful way(s) ... well, I just ain't a guru.

When you are rich and famous and have full fledged Guru status--remember
us little guys ... ;-)

Regards,
JS