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Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
Cecil Moore wrote: Poynting vector = ExH = E*H*sin(A) Incorrect. The Poynting vector is defined as E x H*. The vector directions are critically important. Those who don't remember what the cross product is, please reference: http://en.wikipedia.org/wiki/Cross_product Another name for the cross product is the vector product. Quoting "Fields and Waves ..." by Ramo & Whinnery: Poynting vector = ExH These are, of course, vectors. Quoting "Reference Data for Radio Engineers": ExH is called the Poynting vector. Again, vectors. The average Poynting vector is defined as Re(E x H*)/2 in my references. So your "Incorrect." assertion above is proven to be incorrect. The Poynting vector for a pure standing wave = 0. Says who? Perhaps the time and space averages or "net", whatever that means, but not the local instantaneous Poynting vector. Let's deal with the average Poynting vector. The real power in the fields is equal to the magnitude of the average Poynting vector. There is zero real power in the standing waves. Therefore, the average Poynting vector is zero at every point on a line containing pure standing waves. So, using Occam's razor, here's the same question for you stated in a different way. If E and H* are both non-zero, how can the following equation be equal to zero all up and down the line as we know it is for standing waves? Pav = Re(E x H*)/2 = 0 where E 0 H* It is always zero even when both E and H are not zero. Nonsense. It is E x H* at every point. If E or H is zero then the Poynting vector is zero. Otherwise it will not be zero. True for a uniform plane wave. But I have already proved that a standing wave is not a uniform plane wave. Pav = Re(E x H*)/2 = zero for a standing wave. I hope you don't question that fact of physics. The answer is that you have started with incorrect equations. The answer is exactly what you have been missing. Please solve the updated problem above. It is obvious that if V*I*cos(A) = 0, then Re(E x H*)/2 must also be zero even when E and H* are not zero. How do you explain that fact? -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
The phasor has nothing to do with spatial direction of the field vector. The E-field and H-field of an EM wave can certainly be represented as an exponential function when the EM wave is normal to the reference plane. Think about it. Hecht used that feature in his book. -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
On Jan 17, 2:13*pm, art wrote:
On 17 Jan, 09:51, Cecil Moore wrote: art wrote: How can one focus so long on travelling and standing waves when the radiation portion of the subject has not been explained? If waves is the subject it cannot be discussed coherently if you cannot describe the mechanism of radiation, ... The mechanism of radiation is pretty simple from a quantum electrodynamic standpoint. Accelerated electrons emit photons. Some of the photons escape the antenna. The energy lost by the escaping photons must be replaced by the source. QED. :-) Art, if you would replace electrons with photons in your blast-off theory, you will be closer to the facts. -- 73, Cecil *http://www.w5dxp.com If it concentrated on say, a simple parallel circuit, a very simple circuit then the absolute physics of what is being discussed would be an immense help in explaining this wave discussion.ARRL states that an antenna is a simple parallel circuit Here is my civil response: For this discussion there is little benefit in using lumped component theory. The standing wave stores energy in an antenna in a manner similar to energy stored in an inductor and a capacitor in a resonant component circuit but it is not very useful to use lumped components when explaining why a standing wave cannot be used to measure delay in a coil, for example. Further questions that challenge your (and the ARRL's) simplified model: Is the resonant circuit dependent on the capacitance and inductance of the antenna or its length? If your answer is "both", (which it is), why does it happen to be both? Why does 1/4WL of the length of the antenna just happen to be a resonant point of the capacitance (in x _farads) and inductance (in y- henries) of the antenna? Why physically is that so? Nature is telling you something there. You should understand that concept well before you get to the radiation of particles (and they WILL be photons). AI4QJ but this concentration on antenna workings is blind siding every body as well as providing a means for twisting the discussion because the makings of radiation is not known. Why not illustrate waves in a simple parallel circuit so that observers can partake in this discussion which, if it ever comes to closure, could then be used to demonstrate their effect on radiation? Onlookers are more than willing to partake in the discussion but presently they are on the side lines because as presented it is limited to only those whose intent is to argue without obtaining closure and their feeding habits are insatiable as you are finding out. Best regards Art Unwin KB9MZ......XG- Hide quoted text - - Show quoted text - |
Standing morphing to travelling waves, and other stupid notions
On 17 Jan, 12:14, Cecil Moore wrote:
art wrote: Why not illustrate waves in a simple parallel circuit so that observers can partake in this discussion which, if it ever comes to closure, could then be used to demonstrate their effect on radiation? This discussion, to a large extent, is concerned with the nature of RF waves. There are no RF waves in a simple parallel circuit. I posted a list of characteristics of an EM plane wave. A parallel circuit doesn't match those characteristics. -- 73, Cecil *http://www.w5dxp.com Cecil But I am not sure they understand one bit of what you are proposing! With respect to your remark on my radiation attempts. When this group did not understand the relevance of Gaussian equation with those of Maxwell I decided to dumb it down and refer only to particles. Later I was forced to move up to electrons because of counter posting. If I was to move now up to protons when the group does not understand electrons or even the common parallel circuit I think I would then parallel your situation where you refuse to dummy down to reflect the audience. Thisd would then mean a continuum of postings that would only go around in circles becaus of their past cessation in learning. Best regards Art |
Standing morphing to travelling waves, and other stupid notions
art wrote:
I decided to dumb it down and refer only to particles. Later I was forced to move up to electrons because of counter posting. If I was to move now up to protons when the group does not understand electrons or even the common parallel circuit I think I would then parallel your situation where you refuse to dummy down to reflect the audience. There are a host of applications that simply cannot be dummied down to the lumped circuit level. I am unable to teach my dog to look at the clock and tell whether it is dinnertime or not. Is that my fault or hers? The answer is more complicated than one might think at first glance. -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
On 17 Jan, 13:30, wrote:
On Jan 17, 2:13*pm, art wrote: On 17 Jan, 09:51, Cecil Moore wrote: art wrote: How can one focus so long on travelling and standing waves when the radiation portion of the subject has not been explained? If waves is the subject it cannot be discussed coherently if you cannot describe the mechanism of radiation, ... The mechanism of radiation is pretty simple from a quantum electrodynamic standpoint. Accelerated electrons emit photons. Some of the photons escape the antenna. The energy lost by the escaping photons must be replaced by the source. QED. :-) Art, if you would replace electrons with photons in your blast-off theory, you will be closer to the facts. -- 73, Cecil *http://www.w5dxp.com If it concentrated on say, a simple parallel circuit, a very simple circuit then the absolute physics of what is being discussed would be an immense help in explaining this wave discussion.ARRL states that an antenna is a simple parallel circuit Here is my civil response: For this discussion there is little benefit in using lumped component theory. The standing wave stores energy in an antenna in a manner similar to energy stored in an inductor and a capacitor in a resonant component circuit but it is not very useful to use lumped components when explaining why a standing wave cannot be used to measure delay in a coil, for example. Further questions that challenge your (and the ARRL's) simplified model: Is the resonant circuit dependent on the capacitance and inductance of the antenna or its length? If your answer is "both", (which it is), why does it happen to be both? Why does 1/4WL of the length of the antenna just happen to be a resonant point of the capacitance (in x _farads) and inductance (in y- henries) of the antenna? Why physically is that so? Nature is telling you something there. You should understand that concept well before you get to the radiation of particles (and they WILL be photons). AI4QJ but this concentration on antenna workings is blind siding every body as well as providing a means for twisting the discussion because the makings of radiation is not known. Why not illustrate waves in a simple parallel circuit so that observers can partake in this discussion which, if it ever comes to closure, could then be used to demonstrate their effect on radiation? Onlookers are more than willing to partake in the discussion but presently they are on the side lines because as presented it is limited to only those whose intent is to argue without obtaining closure and their feeding habits are insatiable as you are finding out. Best regards Art Unwin KB9MZ......XG- Hide quoted text - - Show quoted text -- Hide quoted text - - Show quoted text -- Hide quoted text - - Show quoted text - Your whole posting is just silly. First you accuse me of lieing now you want to provoke me with stupidity. You need to upgrade to a understanding of a tank circuit.Yes, it is used in your transmitter. Google it and study it. Free speech is great but it also reveals your mentality. And you are just bull ****ing in the absence of knoweledge. |
Standing morphing to travelling waves, and other stupid notions
On 17 Jan, 15:31, Cecil Moore wrote:
art wrote: I decided to dumb it down and refer only to particles. Later I was forced to move up to electrons because of counter posting. If I was to move now up to protons when the group does not understand electrons or even the common parallel circuit I think I would then parallel your situation where you refuse to dummy down to reflect the audience. There are a host of applications that simply cannot be dummied down to the lumped circuit level. I am unable to teach my dog to look at the clock and tell whether it is dinnertime or not. Is that my fault or hers? The answer is more complicated than one might think at first glance. -- 73, Cecil *http://www.w5dxp.com Cecil, I respectfully do not agree with that.I would suggest that the antenna mechanics what I am preaching is directly applicable to complex circuitry.If antenna theory can't apply to such then the theory is in error.Antenna radiation came to a halt in understanding some 50+ years ago.Since then science have tried a lot of new sciences that even tho they do not solve the mystery of radiation provides a whole new stream of old wives tales.And hams are sucking every thing up without question. Nature has simple habits , it is humans that try to make it complicated. My best regards Art Unwin KB9MZ...XG (uk) |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote:
Gene Fuller wrote: Cecil Moore wrote: Poynting vector = ExH = E*H*sin(A) Incorrect. The Poynting vector is defined as E x H*. The vector directions are critically important. Those who don't remember what the cross product is, please reference: http://en.wikipedia.org/wiki/Cross_product Another name for the cross product is the vector product. Quoting "Fields and Waves ..." by Ramo & Whinnery: Poynting vector = ExH These are, of course, vectors. Quoting "Reference Data for Radio Engineers": ExH is called the Poynting vector. Again, vectors. The average Poynting vector is defined as Re(E x H*)/2 in my references. So your "Incorrect." assertion above is proven to be incorrect. I am glad to see you agree with me. However, your long exposition above is not what you said previously, E*H*sin(A). Therefore, your proof that my "Incorrect" assertion is incorrect is itself incorrect. 73, Gene W4SZ |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote:
Gene Fuller wrote: The phasor has nothing to do with spatial direction of the field vector. The E-field and H-field of an EM wave can certainly be represented as an exponential function when the EM wave is normal to the reference plane. Think about it. Hecht used that feature in his book. Totally ducking the issue, as usual. |
Standing morphing to travelling waves, and other stupid notions
On 17 Jan, 18:25, "AI4QJ" wrote:
"art" wrote in message ... your whole posting is just silly. First you accuse me of lieing now you want to provoke me with stupidity. You need to upgrade to a understanding of a tank circuit.Yes, it is used in your transmitter. Google it and study it. Free speech is great but it also reveals your mentality. *And you are just bull ****ing in the absence of knoweledge." OK art, I notice a great improvement in your having only 3 spelling errors in 5 sentences. You are a fool. If your postings could ever be elevated to the level of mere stupidity, then it might be possible to correct your misconceptions. However, one cannot deal with true insanity by any rational approach such as that. You do not drive me to use Google; you drive me to dictionary.com so I can find the words appropriate to describe the idiocy of your ravings. However, it isn't worth the effort so I will leave you mired in your intellectual wasteland, reading your postings from time to time for the entertainment value of comic relief. For the sake of *the hobby I will continue point out the fairy-tale nature of your postings lest the casual reader of this newsgroup ever get the wrong impression of what the typical ham radio operator thinks is antenna "theory". AI4QJ For entertainment value look for where the photon term came from.....Quantum theory which has not been proven. If a particle os in a magnetic field it can take on some of the properties of that field. To be propelled requires mass as does a mechanical vibration of a radiator. Yes mechanical laws equate with electrical laws.The object that was repelled is a mass with anti gravitational tendencies which allows it to have straight line trajectory. That straight line trajectory is of a partical that now has potential energy received from a magnetic field. That energy becomes Kinetic energy on impact with a receiving antenna which thus is instrumental with a multitude of other particles in applying a mechanical force whose reaction is supplied by the receiving radiator in the form of vibration. When you are talking radio you are talking MHz which translates into millions of particles or samples taken by the receiving antenna, a lot more than your ear can accomplish. The proton idea was thought up by Einstein in an effort to understand what radiation is and he died without solving that puzzle. Einstein made a tremendous amounts of errors in his life time and this is just one of them. Ham's look for resonance has the salvation of all but this is just a ham's point of view. Like a quadratic equation there are two answers to choose from, but only one that satisfies Newtons requirement for equilibrium. Ham's choose to recognise just resonance because it is self serving for amateur operation,but science will always follow the requirement for equilibrium just as all the masters did.So many new sciences were invented in an effort to identify radiation that were not required because the simplicity Of Gaussian law reflected the true nature of radiation. You have called me a liar and a fool but are not willing to raise a few thousand dollars to prove that I do not have a 160M antenna on the top of my tower, that I am a fool and a liar Money is waiting for you and your backers just by y showing I do not have a 160M antenna sitting on my tower. You have some gall to call me names and then backslide when asked to prove your point. No, I am not going to insult you, your own actions show what manner of man you are. Art Unwin...KB9MZ....xg(uk) |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote:
... There are a host of applications that simply cannot be dummied down to the lumped circuit level. I am unable to teach my dog to look at the clock and tell whether it is dinnertime or not. Is that my fault or hers? The answer is more complicated than one might think at first glance. Well, sure. But you are bragging about the intelligence of your dog--you are not likely to find that in a ng--often. ROFLOL Regards, JS |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
Therefore, your proof that my "Incorrect" assertion is incorrect is itself incorrect. Please answer the question. It is known that Re(ExH*)/2 = 0 for pure standing waves all up and down the line. If E and H* are both non-zero, how can Re(ExH*)/2 be zero? -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
Cecil Moore wrote: The E-field and H-field of an EM wave can certainly be represented as an exponential function when the EM wave is normal to the reference plane. Think about it. Hecht used that feature in his book. Totally ducking the issue, as usual. No, I'm waiting for an answer from you. It is known that Re(ExH*)/2=0 for pure standing waves all up and down the line. Since E and H* are not zero all up and down the line, how is that possible? -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
art wrote:
You have called me a liar and a fool but are not willing to raise a few thousand dollars to prove that I do not have a 160M antenna on the top of my tower, that I am a fool and a liar Money is waiting for you and your backers just by y showing I do not have a 160M antenna sitting on my tower. You have some gall to call me names and then backslide when asked to prove your point. No, I am not going to insult you, your own actions show what manner of man you are. Art Unwin...KB9MZ....xg(uk) Art, I've asked you to provide information on your 160m antenna twice previously. You referred me to an eham tower of babel after the first and responded something about not operating on 160 for the second. I'll ask you for the third time: Would you explain your 160m antenna for us? Do you believe it to be as good or better than a full-sized inverted L over an extensive radial field? Have I wasted time, effort and money in installing my inverted L when an 18 foot antenna would have done the same job? Dave K8MN |
Standing morphing to travelling waves, and other stupid notions
On 17 Jan, 20:43, Dave Heil wrote:
art wrote: You have called me a liar and a fool but are not willing to raise a few thousand dollars to prove that I do not have a 160M antenna on the top of my tower, that I am a fool and a liar Money is waiting for you and your backers just by y showing I do not have a 160M antenna sitting on my tower. You have some gall to call me names and then backslide when asked to prove your point. No, I am not going to insult you, your own actions show what manner of man you are. Art Unwin...KB9MZ....xg(uk) Art, I've asked you to provide information on your 160m antenna twice previously. *You referred me to an eham tower of babel after the first and responded something about not operating on 160 for the second. I'll ask you for the third time: *Would you explain your 160m antenna for us? *Do you believe it to be as good or better than a full-sized inverted L over an extensive radial field? *Have I wasted time, effort and money in installing my inverted L when an 18 foot antenna would have done the same job? Dave K8MN Dave, Over the years many have asked that same question and I have answered it many times. When ever a newbie comes along they always ask the same question without looking back at my past posts since they want to argue. Now it is you who is starting the post with a caustic comment regarding the "tower of Babel" but at no time have you or any newbie initiated a discussion before making a insult to follow the crowd. What do you think I should do when you call my writing "babel"? Now the computor programs state that a tilted element provides more horizontal gain than a horizontal element. This was followed up independently on this newsgroup.No debate regarding the coroberation So should we all dump the antenna computor programs? Many hams say they did this or did that and produced better than sliced bread. Hams respond that you didn't measure on the range properly so give me the math. I started off with the math which was corroberated by a doctor working for a space agency. Guess what? He got plastered for "poor" mathematics. This group cannot debate any thing which is why only a few dominate the group now. Past experts have left!So I ask you"how should this group be run"? Art |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
The phasor has nothing to do with spatial direction of the field vector. Sorry, but The IEEE Dictionary disagrees with you. In the description of the Poynting vector, it says: "E and H are the electric and magnetic field vectors in phasor notation ..." I have prepared a graph of a snapshot in time of a forward wave and reflected wave of equal magnitudes. When the waves are superposed at the reference plane, the total E-field and total H-field are 180 degrees out of phase. The graph is at: http://www.w5dxp.com/EHSuper.JPG -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
On 17 Jan, 20:44, "AI4QJ" wrote:
"art" wrote in message ... On 17 Jan, 18:25, "AI4QJ" wrote: "art" wrote in message ... your whole posting is just silly. First you accuse me of lieing now you want to provoke me with stupidity. You need to upgrade to a understanding of a tank circuit.Yes, it is used in your transmitter. Google it and study it. Free speech is great but it also reveals your mentality. And you are just bull ****ing in the absence of knoweledge." OK art, I notice a great improvement in your having only 3 spelling errors in 5 sentences. You are a fool. If your postings could ever be elevated to the level of mere stupidity, then it might be possible to correct your misconceptions. However, one cannot deal with true insanity by any rational approach such as that. You do not drive me to use Google; you drive me to dictionary.com so I can find the words appropriate to describe the idiocy of your ravings. However, it isn't worth the effort so I will leave you mired in your intellectual wasteland, reading your postings from time to time for the entertainment value of comic relief. For the sake of the hobby I will continue point out the fairy-tale nature of your postings lest the casual reader of this newsgroup ever get the wrong impression of what the typical ham radio operator thinks is antenna "theory". AI4QJ :No, I am not going to insult you, I'm sure you have had you fill of hurling insults at me tonite. Just part of the entertainment. :your own actions show what manner of: :man you are. Pot Kettle Black Tell me how a 1/4W tank circuit in my transmitter works, art. AI4QJ- Hide quoted text - - Show quoted text - You have one in your transmitter and you don't know how it works so you ask me. Why? You can ask KB9..... or the MI5. If you cross post they will get back to you. I promise.They miss you. Maybe one of the above is actually you! |
Standing morphing to travelling waves, and other stupid notions
art wrote:
... Dave, Over the years many have asked that same question and I have answered it many times. Yeah Art, I have notice the exact same thing. I think he is one of those "special people." Most likely, took "special classes" when he was in school. We should probable just ignore this fact--indeed, we should, most likely, just ignore him ... When ever a newbie comes along they always ask the same question without looking back at my past posts since they want to argue. Now it is you who is starting the post with a caustic comment regarding the "tower of Babel" but at no time have you or any newbie initiated a discussion before making a insult to follow the crowd. What do you think I should do when you call my writing "babel"? Now the computor programs state that a tilted element provides more horizontal gain than a horizontal element. This was followed up independently on this newsgroup.No debate regarding the coroberation So should we all dump the antenna computor programs? Many hams say they did this or did that and produced better than sliced bread. Hams respond that you didn't measure on the range properly so give me the math. I started off with the math which was corroberated by a doctor working for a space agency. Guess what? He got plastered for "poor" mathematics. This group cannot debate any thing which is why only a few dominate the group now. Past experts have left!So I ask you"how should this group be run"? Art Yes, but all that is probably just a factor/side-effect of the special classes he which he was "initiated" with. You'd be better looking for more "intellectual fields" to plant your ideas in ... Warm regards, JS |
Standing morphing to travelling waves, and other stupid notions
On 17 Jan, 13:30, wrote:
On Jan 17, 2:13*pm, art wrote: On 17 Jan, 09:51, Cecil Moore wrote: art wrote: How can one focus so long on travelling and standing waves when the radiation portion of the subject has not been explained? If waves is the subject it cannot be discussed coherently if you cannot describe the mechanism of radiation, ... The mechanism of radiation is pretty simple from a quantum electrodynamic standpoint. Accelerated electrons emit photons. Some of the photons escape the antenna. The energy lost by the escaping photons must be replaced by the source. QED. :-) Art, if you would replace electrons with photons in your blast-off theory, you will be closer to the facts. -- 73, Cecil *http://www.w5dxp.com If it concentrated on say, a simple parallel circuit, a very simple circuit then the absolute physics of what is being discussed would be an immense help in explaining this wave discussion.ARRL states that an antenna is a simple parallel circuit Here is my civil response: For this discussion there is little benefit in using lumped component theory. The standing wave stores energy in an antenna in a manner similar to energy stored in an inductor and a capacitor in a resonant component circuit but it is not very useful to use lumped components when explaining why a standing wave cannot be used to measure delay in a coil, for example. Further questions that challenge your (and the ARRL's) simplified model: Is the resonant circuit dependent on the capacitance and inductance of the antenna or its length? If your answer is "both", (which it is), why does it happen to be both? Why does 1/4WL of the length of the antenna just happen to be a resonant point of the capacitance (in x _farads) and inductance (in y- henries) of the antenna? Why physically is that so? Nature is telling you something there. You should understand that concept well before you get to the radiation of particles (and they WILL be photons). AI4QJ but this concentration on antenna workings is blind siding every body as well as providing a means for twisting the discussion because the makings of radiation is not known. Why not illustrate waves in a simple parallel circuit so that observers can partake in this discussion which, if it ever comes to closure, could then be used to demonstrate their effect on radiation? Onlookers are more than willing to partake in the discussion but presently they are on the side lines because as presented it is limited to only those whose intent is to argue without obtaining closure and their feeding habits are insatiable as you are finding out. Best regards Art Unwin KB9MZ......XG- Hide quoted text - - Show quoted text -- Hide quoted text - - Show quoted text -- Hide quoted text - - Show quoted text - Why are you asking me all these questions? Can't you read a book? Why not ask an expert on Eham and then come back armed for an arguement. At the moment you are un armed and defenceless. By the way the money is still out there. It is not such a large amount but it will pay for lunch while you crow about proving me a liar or you could be crying about how you were dethroned instead. T'was you who made that foolish statement in the first place. Somebody stated that they had a 160M antenna on the top of their tower which isaparently is rediculous. Now a small amount of money is being mentioned and now you have second thoughts. A 160M antenna is crazy for those who believe all is known about antennas and you perceive yourself as an expert.What are you waiting for,chicken wings? |
Energy and Work
On Wed, 16 Jan 2008 10:17:44 -0800, Richard Clark
wrote: Feynman is not generally available, but he is certainly held by many of those stumbling over the terms of their own invention. Thanks for the response, Richard. I had consulted Feynman's Volumes I and II prior to posting and saw nothing there to support the idea that an EM wave performs work in moving through a region of free space. Hence, my original post. 73, Chuck NT3G ----== Posted via Newsfeeds.Com - Unlimited-Unrestricted-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
... your long exposition above is not what you said previously, E*H*sin(A). I think you know that I meant the magnitudes only, but to be entirely technically correct it should have been: Poynting vector = ExH = |E|*|H|*sin(A) The same question remains: When E and H are both not zero, how can the Poynting vector be zero? -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote:
Gene Fuller wrote: Therefore, your proof that my "Incorrect" assertion is incorrect is itself incorrect. Please answer the question. It is known that Re(ExH*)/2 = 0 for pure standing waves all up and down the line. If E and H* are both non-zero, how can Re(ExH*)/2 be zero? Known by whom? If you are talking about time and/or spatial averages then yes, the Poynting vector will be zero. If you are talking about instantaneous calculations at any point and time, then no, the Poynting vector will not be zero all up and down the line. Once again you have misinterpreted something you read in a book. 73, Gene W4SZ |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote:
Gene Fuller wrote: Cecil Moore wrote: The E-field and H-field of an EM wave can certainly be represented as an exponential function when the EM wave is normal to the reference plane. Think about it. Hecht used that feature in his book. Totally ducking the issue, as usual. No, I'm waiting for an answer from you. It is known that Re(ExH*)/2=0 for pure standing waves all up and down the line. Since E and H* are not zero all up and down the line, how is that possible? Anything is possible in your Fractured Fairytale Physics. |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote:
Gene Fuller wrote: The phasor has nothing to do with spatial direction of the field vector. Sorry, but The IEEE Dictionary disagrees with you. In the description of the Poynting vector, it says: "E and H are the electric and magnetic field vectors in phasor notation ..." I have prepared a graph of a snapshot in time of a forward wave and reflected wave of equal magnitudes. When the waves are superposed at the reference plane, the total E-field and total H-field are 180 degrees out of phase. The graph is at: http://www.w5dxp.com/EHSuper.JPG The graph is complete nonsense. There is no rotation of the fields when they undergo reflection. Any ordinary text on E&M or optics will show you the equations and the correct sketches. You are obviously still confusing phasors and fields. More FFP. 73, Gene W4SZ |
Energy and Work
On Fri, 18 Jan 2008 07:22:48 -0500, Chuck
wrote: Thanks for the response, Richard. Hi Chuck, You're welcome. I had consulted Feynman's Volumes I and II prior to posting and saw nothing there to support the idea that an EM wave performs work in moving through a region of free space. Hence, my original post. It is also noteworthy that electrons don't exhibit much friction either. (Feynman is particularly interesting in regard to friction too.) 73's Richard Clark, KB7QHC |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
Once again you have misinterpreted something you read in a book. Once again, you have refused to answer a simple question. If E and H are not zero, how can ExH be zero? -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote:
Gene Fuller wrote: Once again you have misinterpreted something you read in a book. Once again, you have refused to answer a simple question. If E and H are not zero, how can ExH be zero? What is this? The RRAA version of "When did you stop beating your wife?" |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote: Jim Kelley wrote: Cecil Moore wrote: Since the standing wave energy is being used to transform impedances, it cannot also be used for radiation purposes - like the energy in a standing wave on a transmission line cannot be used both to transform impedances and to heat up a load. Would you care to elaborate on the idea that "energy is being used to transform impedances"? If reflections are nonexistent, no transformation takes place, i.e. there is no SWR circle, just a point at the center of the Smith Chart and the system is flat. If reflections exist, then the superposition of the forward wave and reflected wave transforms the load impedance to some other impedance on the SWR circle. A 1/4WL transformer, for instance, will not transform unless there are reflections present. |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote: Jim Kelley wrote: Cecil Moore wrote: Since the standing wave energy is being used to transform impedances, it cannot also be used for radiation purposes - like the energy in a standing wave on a transmission line cannot be used both to transform impedances and to heat up a load. Would you care to elaborate on the idea that "energy is being used to transform impedances"? If reflections are nonexistent, no transformation takes place, i.e. there is no SWR circle, just a point at the center of the Smith Chart and the system is flat. If reflections exist, then the superposition of the forward wave and reflected wave transforms the load impedance to some other impedance on the SWR circle. A 1/4WL transformer, for instance, will not transform unless there are reflections present. You fail to explain how any of that makes energy unavailable for "radiation purposes". ac6xg |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
The graph is complete nonsense. There is no rotation of the fields when they undergo reflection. Any ordinary text on E&M or optics will show you the equations and the correct sketches. Good grief, Gene. There is a 360 degree rotation in the fields every wavelength. The direction of rotation is associated with the direction of travel of the wave and is displayed by EZNEC when the current phase option is turned on. All you have to do to see the rotation of the traveling wave is to download http://www.w5dxp.com/rhombicT.EZ Those simplified sketches are making you simple-minded. Assuming you are a member of the IEEE, look up this paper: "Rotation in electromagnetic field equations". Or Google "Rotation and the Electromagnetic Field". "Optics", by Hecht, is one of your ordinary texts. That is where the material for that graph comes from. The IEEE Dictionary says: "E and H are the electric and magnetic field vectors in phasor notation". If that graph is nonsense to you, it is your fault, not mine. Hecht says "Optics", 4th edition, page 289, about standing waves: "The composite disturbance is then: E = Eo[sin(kx+wt) + sin(kx-wt)] Applying the identity: sin A + sin B = 2 sin 1/2(A+B)*cos 1/2(A-B) yields: E(x,t) = 2*Eo*sin(kx)*cos(wt)" "This is the equation for a STANDING or STATIONARY WAVE, as opposed to a traveling wave. Its profile does not move through space; it is clearly not of the form Func(x +/- vt)." "... a phasor rotating counterclockwise at a rate omega is equivalent to a wave traveling to the left (decreasing x), and similarly, one rotating clockwise corresponds to a wave traveling to the right (increasing x)." Hecht uses phasors to represent EM waves all through his book. He explains the standing wave E-field based on the two traveling waves, E1-field and E2-field, thusly: "The resultant phasor is E1 + E2 = E ... Keeping the two [traveling wave] phasors tip-to-tail and having E1 rotate counterclockwise as E2 rotates (at the same rate) clockwise, generates E [total] as a function of 't'." [Standing wave phase] "doesn't rotate at all, and the resultant wave it represents doesn't progress through space - its a standing wave." Traveling wave phase rotates. Standing wave phase doesn't. Speaking of "... net transfer of energy, for the pure standing wave there is none." The forward wave and reflected wave E-field and H-field vectors are represented by phasors just as indicated in the IEEE Dictionary. One is rotating clockwise and the other is rotating counterclockwise. The Poynting vector for a pure standing wave is equal to zero just as illustrated in my graph at: http://www.w5dxp.com/EHSuper.JPG Given those boundary conditions and solving for the angle between the standing wave E-field and H-field yields 0 or 180 degrees. Are you really more interested in presenting false information and saving face than you are in valid technical facts? -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
Cecil Moore wrote: Once again, you have refused to answer a simple question. If E and H are not zero, how can ExH be zero? What is this? The RRAA version of "When did you stop beating your wife?" No, this is the RRAA version of someone unwilling to accept technical facts. Your name is Legion. -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Jim Kelley wrote:
You fail to explain how any of that makes energy unavailable for "radiation purposes". This is not rocket science. If the energy is being used to transform impedances, it is obviously unavailable to be lost as radiation. If all the forward energy is radiated by the antenna, there exists no impedance transformation in the transmission line. A highly technical quote must be needed: "You can't have your energy cake and eat it too." :-) -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote:
Gene Fuller wrote: The graph is complete nonsense. There is no rotation of the fields when they undergo reflection. Any ordinary text on E&M or optics will show you the equations and the correct sketches. Good grief, Gene. There is a 360 degree rotation in the fields every wavelength. The direction of rotation is associated with the direction of travel of the wave and is displayed by EZNEC when the current phase option is turned on. All you have to do to see the rotation of the traveling wave is to download http://www.w5dxp.com/rhombicT.EZ Those simplified sketches are making you simple-minded. Assuming you are a member of the IEEE, look up this paper: "Rotation in electromagnetic field equations". Or Google "Rotation and the Electromagnetic Field". "Optics", by Hecht, is one of your ordinary texts. That is where the material for that graph comes from. The IEEE Dictionary says: "E and H are the electric and magnetic field vectors in phasor notation". If that graph is nonsense to you, it is your fault, not mine. Hecht says "Optics", 4th edition, page 289, about standing waves: "The composite disturbance is then: E = Eo[sin(kx+wt) + sin(kx-wt)] Applying the identity: sin A + sin B = 2 sin 1/2(A+B)*cos 1/2(A-B) yields: E(x,t) = 2*Eo*sin(kx)*cos(wt)" "This is the equation for a STANDING or STATIONARY WAVE, as opposed to a traveling wave. Its profile does not move through space; it is clearly not of the form Func(x +/- vt)." "... a phasor rotating counterclockwise at a rate omega is equivalent to a wave traveling to the left (decreasing x), and similarly, one rotating clockwise corresponds to a wave traveling to the right (increasing x)." Hecht uses phasors to represent EM waves all through his book. He explains the standing wave E-field based on the two traveling waves, E1-field and E2-field, thusly: "The resultant phasor is E1 + E2 = E ... Keeping the two [traveling wave] phasors tip-to-tail and having E1 rotate counterclockwise as E2 rotates (at the same rate) clockwise, generates E [total] as a function of 't'." [Standing wave phase] "doesn't rotate at all, and the resultant wave it represents doesn't progress through space - its a standing wave." Traveling wave phase rotates. Standing wave phase doesn't. Speaking of "... net transfer of energy, for the pure standing wave there is none." The forward wave and reflected wave E-field and H-field vectors are represented by phasors just as indicated in the IEEE Dictionary. One is rotating clockwise and the other is rotating counterclockwise. The Poynting vector for a pure standing wave is equal to zero just as illustrated in my graph at: http://www.w5dxp.com/EHSuper.JPG Given those boundary conditions and solving for the angle between the standing wave E-field and H-field yields 0 or 180 degrees. Are you really more interested in presenting false information and saving face than you are in valid technical facts? Cecil, This is truly sad. I thought you had finally begun to understand this stuff, but you have regressed back into the same old nonsense. You are still totally confusing phasors with field vectors. They are utterly, totally, and absolutely unrelated. Get help. Call me what you like. Bye. 73, Gene W4SZ |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
Any ordinary text on E&M or optics will show you the equations and the correct sketches. Please stop staring at your simple-minded sketches and stare at this diagram of an EM wave for awhile. Maybe you are due for an epiphany. http://www.w5dxp.com/EHWave.JPG -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote: Jim Kelley wrote: You fail to explain how any of that makes energy unavailable for "radiation purposes". This is not rocket science. Or any other kind of science for that matter. If the energy is being used to transform impedances, it is obviously unavailable to be lost as radiation. Sure, assuming energy is being "used" to perform an operation in which no work is done. You'll need to prove the first part of the sentence in order to show the second part to be true. ac6xg |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
This is truly sad. I thought you had finally begun to understand this stuff, but you have regressed back into the same old nonsense. You are still totally confusing phasors with field vectors. They are utterly, totally, and absolutely unrelated. Saying that doesn't make it true, Gene, although it may hoodwink some of the uninitiated into believing your old wives' tales. I just posted a more sophisticated diagram of an EM wave for you at: http://www.w5dxp.com/EHWave.JPG Have those simple-minded sketches that you have been staring at made you simple-minded or are you capable of something else? -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
On 18 Jan, 10:52, Cecil Moore wrote:
Gene Fuller wrote: The graph is complete nonsense. There is no rotation of the fields when they undergo reflection. Any ordinary text on E&M or optics will show you the equations and the correct sketches. Good grief, Gene. There is a 360 degree rotation in the fields every wavelength. The direction of rotation is associated with the direction of travel of the wave and is displayed by EZNEC when the current phase option is turned on. All you have to do to see the rotation of the traveling wave is to downloadhttp://www.w5dxp.com/rhombicT.EZ Those simplified sketches are making you simple-minded. Assuming you are a member of the IEEE, look up this paper: "Rotation in electromagnetic field equations". Or Google "Rotation and the Electromagnetic Field". "Optics", by Hecht, is one of your ordinary texts. That is where the material for that graph comes from. The IEEE Dictionary says: "E and H are the electric and magnetic field vectors in phasor notation". If that graph is nonsense to you, it is your fault, not mine. Hecht says "Optics", 4th edition, page 289, about standing waves: "The composite disturbance is then: E = Eo[sin(kx+wt) + sin(kx-wt)] Applying the identity: sin A + sin B = 2 sin 1/2(A+B)*cos 1/2(A-B) yields: E(x,t) = 2*Eo*sin(kx)*cos(wt)" "This is the equation for a STANDING or STATIONARY WAVE, as opposed to a traveling wave. Its profile does not move through space; it is clearly not of the form Func(x +/- vt)." "... a phasor rotating counterclockwise at a rate omega is equivalent to a wave traveling to the left (decreasing x), and similarly, one rotating clockwise corresponds to a wave traveling to the right (increasing x)." Hecht uses phasors to represent EM waves all through his book. He explains the standing wave E-field based on the two traveling waves, E1-field and E2-field, thusly: "The resultant phasor is E1 + E2 = E *... Keeping the two [traveling wave] phasors tip-to-tail and having E1 rotate counterclockwise as E2 rotates (at the same rate) clockwise, generates E [total] as a function of 't'." [Standing wave phase] "doesn't rotate at all, and the resultant wave it represents doesn't progress through space - its a standing wave." Traveling wave phase rotates. Standing wave phase doesn't. Speaking of "... net transfer of energy, for the pure standing wave there is none." The forward wave and reflected wave E-field and H-field vectors are represented by phasors just as indicated in the IEEE Dictionary. One is rotating clockwise and the other is rotating counterclockwise. The Poynting vector for a pure standing wave is equal to zero just as illustrated in my graph at:http://www.w5dxp.com/EHSuper.JPG Given those boundary conditions and solving for the angle between the standing wave E-field and H-field yields 0 or 180 degrees. Are you really more interested in presenting false information and saving face than you are in valid technical facts? -- 73, Cecil *http://www.w5dxp.com Cecil, Just a small question. Do you include in your analysis of E and H waves the effect of the field produced by a diamagnetic field produced by current flow in the material, where the field has a tendency to be at right angles? This is what PROF Hately was looking to do on his EH invention without understanding the importance of the material used in generating the fields in question. Best regards Art Unwin KB9MZ...xg |
Standing morphing to travelling waves, and other stupid notions
art wrote:
Do you include in your analysis of E and H waves the effect of the field produced by a diamagnetic field produced by current flow in the material, ... Nope, I tend to ignore effects that I judge to be secondary. Of course, I don't even pretend to exercise perfect judgment. -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
On 18 Jan, 12:15, Cecil Moore wrote:
art wrote: Do you include in your analysis of E and H waves the effect of the field produced by a diamagnetic field produced by current flow in the material, ... Nope, I tend to ignore effects that I judge to be secondary. Of course, I don't even pretend to exercise perfect judgment. -- 73, Cecil *http://www.w5dxp.com But when adding vectors as I see it there is no secondary vectors, which in this case says both vectors are in phase no less.I thought I would probe a bit in this long thread to ascertain where the controversy is. To understand that alone in the face of thousand postings is a very difficult task indeed.Even more so for a mechanical engineer Very best regards Art |
Standing morphing to travelling waves, and other stupid notions
On Jan 18, 12:44*am, art wrote:
On 17 Jan, 20:44, "AI4QJ" wrote: "art" wrote in message ... On 17 Jan, 18:25, "AI4QJ" wrote: "art" wrote in message .... your whole posting is just silly. First you accuse me of lieing now you want to provoke me with stupidity. You need to upgrade to a understanding of a tank circuit.Yes, it is used in your transmitter. Google it and study it. Free speech is great but it also reveals your mentality. And you are just bull ****ing in the absence of knoweledge.." OK art, I notice a great improvement in your having only 3 spelling errors in 5 sentences. You are a fool. If your postings could ever be elevated to the level of mere stupidity, then it might be possible to correct your misconceptions. However, one cannot deal with true insanity by any rational approach such as that. You do not drive me to use Google; you drive me to dictionary.com so I can find the words appropriate to describe the idiocy of your ravings. However, it isn't worth the effort so I will leave you mired in your intellectual wasteland, reading your postings from time to time for the entertainment value of comic relief. For the sake of the hobby I will continue point out the fairy-tale nature of your postings lest the casual reader of this newsgroup ever get the wrong impression of what the typical ham radio operator thinks is antenna "theory". AI4QJ :No, I am not going to insult you, I'm sure you have had you fill of hurling insults at me tonite. Just part of the entertainment. :your own actions show what manner of: :man you are. Pot Kettle Black Tell me how a 1/4W tank circuit in my transmitter works, art. AI4QJ- Hide quoted text - - Show quoted text - You have one in your transmitter and you don't know how it works so you ask me. Why? You can ask KB9..... or the MI5. If you cross post they will get back to you. I promise.They miss you. Maybe one of the above is actually you!- Hide quoted text - - Show quoted text - So you found out that I have a 1/4 wave tank circuit in my transmitter. Only the MI5 could have known that. Hmmm... |
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