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#1
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On Jan 25, 5:31*pm, Cecil Moore wrote:
Keith Dysart wrote: Check your answer by trying 100 kHz sinusoidal steady-state excitation. Good grief, Keith, get real. I guess I forgot to say the assertion was for an integer multiple of MHz. Yes, so it would seem. And that would seem to narrow the applicability of the original assertion rather severely. ...Keith |
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#2
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Keith Dysart wrote:
And that would seem to narrow the applicability of the original assertion rather severely. What do you know? It narrows it to amateur radio, the subject of this newsgroup. To be entirely technically correct, since my assertion was about average powers, the example transmission line must be an integer multiple of 1/4 wavelength. -- 73, Cecil http://www.w5dxp.com |
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#3
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On Jan 26, 9:12*am, Cecil Moore wrote:
Keith Dysart wrote: And that would seem to narrow the applicability of the original assertion rather severely. What do you know? It narrows it to amateur radio, the subject of this newsgroup. I was unaware that all Amateur transmission lines were a multiple of 1 wavelength long. Are you sure? To be entirely technically correct, since my assertion was about average powers, the example transmission line must be an integer multiple of 1/4 wavelength. I would suggest 1/2 wavelength. For an intuitive proof, consider a line with only forward power. Then think of a quarter wave section with a voltage peak in the middle. Then consider when the voltage 0 is in the middle. Lots more energy in the former than the latter. At 1/2 wavelength, the total energy in the line section is constant. ...Keith ...Keith |
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