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Derivation of Reflection Coefficient vs SWR
"JOHN PASSANEAU" wrote in message ... There is no such thing as DC! How's that you say? You have to turn it on sometime and someday you may turn it off. There for, DC is just very low frequency AC. John Passaneau W3JXP That's false reasoning OM! Alternating current is not the same as discontinuous current. In the example you provide, a DC supply is either off or on; it does not reverse polarity! You do not make AC by switching on and off DC, even at 50 Hz (or your 60 Hz) |
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Derivation of Reflection Coefficient vs SWR
Suzy wrote:
"You do not make AC by switching on and off DC, even at 50 Hz (or your 60 Hz)" Not without inductance to provide the missing half cycle. Remember vibrator supplies and their solid-state equivalents? Best regards, Richard Harrison, KB5WZI |
#3
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Derivation of Reflection Coefficient vs SWR
Suzy wrote:
"JOHN PASSANEAU" wrote in message ... There is no such thing as DC! How's that you say? You have to turn it on sometime and someday you may turn it off. There for, DC is just very low frequency AC. John Passaneau W3JXP That's false reasoning OM! Alternating current is not the same as discontinuous current. In the example you provide, a DC supply is either off or on; it does not reverse polarity! You do not make AC by switching on and off DC, even at 50 Hz (or your 60 Hz) But through the techniques of linear circuit analysis, we can split the pulsed DC into two components, a pure steady DC component and a symmetrical AC component. We can do two separate analyses with the two (AC and DC) excitations, and sum the results. The answer will be exactly the same as if we had done the calculations directly. One can then reasonably claim that the switched DC is the sum of an AC waveform and a pure DC component. Roy Lewallen, W7EL |
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