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On Mar 25, 10:28 am, Cecil Moore wrote:
Keith Dysart wrote: Read it as Pr.correction(t) to emphasize that it is not average power of which I am writing. Then it is not interference. That statement makes it obvious that you don't understand interference. When instantaneous values are being used, if [V1(t)^2 + V2(t)^2] NOT= [V1(t) + V2(t)]^2, then interference is present. Did you miss Physics 201? Let us build a slightly better example that complies with your "NOT =" expression above. +-----------------------------------+ | | Vs1(t) = 141.4cos(wt) \ | = 100 Vrms Rload / | 50 ohms \ Vs2(t) = 70.7cos(wt) / | = 50 Vrms | +-----------------------------------+ Using superposition the contribution from source 1 is Vload.s1 = 100 Vrms Iload.s1 = 2 Arms and from source 2 is Vload.s2 = 50 Vrms Iload.s2 = 1 Arms combining Vload = 150 Vrms Iload = 3 Arms From Pload = Vload * Iload = 150 * 3 = 450 Waverage As can be seen, this example satisfies your requirement for interference: [V1(t)^2 + V2(t)^2] NOT= [V1(t) + V2(t)]^2 Computing the imputed powers for the waves from each source we have Pload.s1 = 100 * 2 = 200 Waverage Pload.s2 = 50 * 1 = 50 Waverage To obtain the power in the load from these imputed powers we need to use Pload = Pload.s1 + Pload.s2 + Pload.correction 450 = 200 + 50 + Pload.correction 200 = Pload.correction From previous analysis Pcorrection = 2 * sqrt(P1 * P2)cos(theta) (the cos(theta) term is appropriate here because these are average powers being used) Pcorrection = 2 * sqrt(10000) * 1 = 200 as required from above. So according to your energy analsysis, the power in the load comes from the wave from source 1 = 200 W the wave from source 2 = 50 W "interference energy" = 200 W for a total of 450 W as required. Now if the 200 W from the wave from source 1 and the 50 W from the wave from source 2 represent actual energy flows, then the "interference energy" must also be an actual energy flow to satisfy conservation of energy. What element provides the energy for this "interference energy" flow? Note that in this analysis, this energy is an average energy flow, so it can not be saved during part of the cycle and returned during another part. In other posts, you have suggested that this would be a constructive interference energy and that there would be an equal destructive interference energy to provide it. If you still claim this, where is this destructive interference happening? ....Keith |
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Gene Fuller wrote:
In any case, you answered my question. "Wave reflection model" means nothing beyond ordinary electromagnetic theory. Big deal. It is a big deal when someone asserts that there is no energy in a reflected EM wave or that the energy in a reflected EM wave doesn't have to be conserved or that a reflected wave doesn't obey the rules of the wave reflection model. -- 73, Cecil http://www.w5dxp.com |
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"Jim, K7JEB" wrote in message ... ....This source was used in optical processors for synthetic-aperture imagery back in the 50's.... That should have read "synthetic-aperture radar imagery"... Just trying to not let my mind outrun my typing speed. K7JEB |
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Cecil Moore wrote:
Gene Fuller wrote: I did a little bit of the cheap modern day replacement for research by Googling "wave reflection model". Some 455 references came back. That's strange. When I did the identical thing, 1,970,000 references came back. Wonder what is wrong with your computer? I used the quote marks around the words and got 266 references. Few of them, other than yours, relate to electronics at all, much less radio. Dave K8MN |
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Keith Dysart wrote:
You should consider that perhaps your inability to identify the element and its energy function really calls into question your concept of "interference energy" being stored and returned later. I have previously multiple times identified the element as the network reactance and pointed you to a reference. If you were asking me to teach you the English language on r.r.a.a, you would get the same response. I suppose, if you want to rename superposition as interference. But none of my basic circuit theory books use the word interference when discussing superposition. I'm not renaming superposition. I'm using the definition of "interference" provided by Hecht in "Optics". Superposition can occur with or without interference. The present discussion is about superposition with interference present. Interference is just a word which identifies the special case of superposition that is under discussion. If the powers imputed to the constituent voltages of superposition did represent actual energy flows, then you would be able to simply add them to get the total flow, since energy can not be created or destroyed. There you go again, confusing power and energy. There is *NO* conservation of power principle. Until you give up on superposing powers, you are doomed to failure. There is absolutely nothing wrong with storing energy and turning it into power later in time. Do you think that backup storage batteries are a violation of the conservation of energy principle? The fact that a correction needs to be applied when adding them is proof that they can not be actual energy flows. There is *NO CORRECTION TO THE ENERGY COMPONENTS*. There is only a correction to the power components to account for the time the energy is being stored before it is dissipated. You really need to learn the difference between energy and power. You should take this as a reason to call into question the whole idea that this "interference energy" is an actual energy flow. Your argument is not with me - it is with experts like Eugene Hecht. Please read his *57 page* Chapter 9 on "Interference" and then get back to us. With 57 pages devoted to the subject, Hecht doesn't seem to share your problems with it. If *your* "wave reflection model" includes the idea that Pref always represents an actual energy flow, then *your* "wave reflection model" is wrong. When you can prove that reflected traveling waves contain zero energy, i.e. that ExH=0, I will accept your assertion but not before. Exactly how does a TDR detect zero energy? In fact, the thing you need to do is forget the transmission line and deal with light waves encountering boundaries with different indexes of refraction. The problem is identical, but dealing with light out in the open prohibits you from pushing your mashed-potatoes energy religion. -- 73, Cecil http://www.w5dxp.com |
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Keith Dysart wrote:
What element provides the energy for this "interference energy" flow? Note that in this analysis, this energy is an average energy flow, so it can not be saved during part of the cycle and returned during another part. Already answered a few postings ago. Sorry you missed it. Here it is again: Here are the basic principles: When destructive interference occurs, there is "extra" energy left over from that isolated event. That energy must go somewhere. Here are the possibilities in a typical lossless RF transmitting system. 1. The source can throttle back on its energy output to compensate for the destructive interference energy. 2. Reactive components can store the destructive interference energy and return it to the network at a later time. 3. In the absence of (1) and (2) above, an RF energy wave is launched in a direction that allows the "extra" energy to leave the destructive event area. When constructive interference occurs, there is "missing" energy needed to be supplied into that isolated event. That energy must come from somewhere. Here are the possibilities in a typical lossless RF transmitting system. 1. The source can simply supply the energy needed by the constructive interference event. 2. Reactive components can return stored energy to the network. 3. In the absence of (1) and (2) above, constructive interference energy *must* be supplied in real time by destructive interference between two other waves. -- 73, Cecil http://www.w5dxp.com |
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Keith Dysart wrote:
Now if the 200 W from the wave from source 1 and the 50 W from the wave from source 2 represent actual energy flows, then the "interference energy" must also be an actual energy flow to satisfy conservation of energy. One other observation: Although the interference model will work for a lumped circuit example, there is no reason to use it as it complicates the computations and adds nothing to the solution. The wave reflection model also works for circuits but there is simply no good reason to use it for lumped circuit analysis. Where interference becomes a useful tool is when it happens away from any compensating source. An analysis of the interference of two EM light waves in free space far removed from any source leaves us with two constant sources of energy, the total energy of which has to go somewhere. The following two web pages tell us exactly where the energy goes. http://www.mellesgriot.com/products/optics/oc_2_1.htm http://micro.magnet.fsu.edu/primer/j...ons/index.html Your theory seems to require that the EM waves must know beforehand whether to carry energy or not from a star light years away. You apparently have invented a rather curious "smart wave theory". The question is: How did those two interfering waves from Alpha Centauri know whether to arrive at the planet Earth ten years later carrying ExH energy or not carrying ExH energy? -- 73, Cecil http://www.w5dxp.com |
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Keith Dysart wrote:
Let us build a slightly better example that complies with your "NOT =" expression above. Your constant voltage sources are NOT a better example and not even a good example. To confront the subject being discussed, you should use constant power sources. The reason is obvious. A constant steady-state EM wave is a constant average power source, not a constant voltage source. Constant voltage source examples just won't do. Try your example with constant power sources and see what happens. -- 73, Cecil http://www.w5dxp.com |
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On Mar 26, 11:43*am, Cecil Moore wrote:
Keith Dysart wrote: You should consider that perhaps your inability to identify the element and its energy function really calls into question your concept of "interference energy" being stored and returned later. I have previously multiple times identified the element as the network reactance and pointed you to a reference. Indeed you have, but you have not answered the second clause in the question. Until you can provide the energy flow function of the element you claim is storing the energy there is no reason to believe that it is the element. Can it be that hard to provide the function? Or perhaps the element you have identified does not have the appropriate energy flow function? (It doesn't.) I suppose, if you want to rename superposition as interference. But none of my basic circuit theory books use the word interference when discussing superposition. I'm not renaming superposition. I'm using the definition of "interference" provided by Hecht in "Optics". Superposition can occur with or without interference. The present discussion is about superposition with interference present. Interference is just a word which identifies the special case of superposition that is under discussion. Sure. OK. If the powers imputed to the constituent voltages of superposition did represent actual energy flows, then you would be able to simply add them to get the total flow, since energy can not be created or destroyed. There you go again, confusing power and energy. There is *NO* conservation of power principle. Conservation of energy arises from the inability to create or destroy energy. Energy can only flow from one element to another. This requires that the sum of the flows out of the elements providing energy equals the sum of the flows into the elements receiving the energy. Choose whatever name you want for it, but this is the reason that Ps(t) must equal Prs(t) + Pg(t) And it is just as powerful a concept as conservation of energy since it follows directly from that principle. The fact that a correction needs to be applied when adding them is proof that they can not be actual energy flows. There is *NO CORRECTION TO THE ENERGY COMPONENTS*. There is only a correction to the power components to account for the time the energy is being stored before it is dissipated. You really need to learn the difference between energy and power. And we are still waiting for the energy flow function for the element that you claim is doing the storing of the energy. You should take this as a reason to call into question the whole idea that this "interference energy" is an actual energy flow. Your argument is not with me - it is with experts like Eugene Hecht. Please read his *57 page* Chapter 9 on "Interference" and then get back to us. With 57 pages devoted to the subject, Hecht doesn't seem to share your problems with it. Actually, we are debating *your* interpretation. If *your* "wave reflection model" includes the idea that Pref always represents an actual energy flow, then *your* "wave reflection model" is wrong. When you can prove that reflected traveling waves contain zero energy, i.e. that ExH=0, I will accept your assertion but not before. You see. There you go again. Refusing to set aside an assumption, even temporarily. It does make it difficult to explore alternate explanations if you stop before you start. Exactly how does a TDR detect zero energy? Does it detect energy? Are you sure? Or is it voltage that it detects? Or current? In fact, the thing you need to do is forget the transmission line and deal with light waves encountering boundaries with different indexes of refraction. The problem is identical, but dealing with light out in the open prohibits you from pushing your mashed-potatoes energy religion. No. Light, in a 3 dimensional space and at such high frequency makes the math and measurements so complicated that it is extremely difficult to follow the energy. Much better to learn from a one-dimensional transmission line and then see if the solutions also apply to light. Which they do. But the analysis is tractable in a transmission line. ...Keith |
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On Mar 26, 11:49*am, Cecil Moore wrote:
Keith Dysart wrote: What element provides the energy for this "interference energy" flow? Note that in this analysis, this energy is an average energy flow, so it can not be saved during part of the cycle and returned during another part. Already answered a few postings ago. Sorry you missed it. Here it is again: Since there was no destructive interference in the example, the rest of your post is snipped as being a non-sequitor. ...Keith |
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