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On Mar 26, 9:35*pm, Cecil Moore wrote:
Keith Dysart wrote: Or perhaps the element you have identified does not have the appropriate energy flow function? (It doesn't.) Please prove your assertion. So you are having difficulty doing the math to justify your hypothesis. This requires that the sum of the flows out of the elements providing energy equals the sum of the flows into the elements receiving the energy. True for energy. Not true for power. Ummmmm. Conservation of energy requires that the total quantity of energy in the system not change. This requires that the sum of the changes of the quantity of energy in each element be zero. A change in energy quantity is a flow. The energy flows must sum to zero. Energy flow is power. The powers must sum to 0 to satisfy conservation of energy. And we are still waiting for the energy flow function for the element that you claim is doing the storing of the energy. If you cannot understand the reference I gave you, I don't know what to tell you. You could simply do the derivation for an example that demonstrates your hypothesis. Does it detect energy? Are you sure? Or is it voltage that it detects? Or current? Please provide proof that voltage or current can exist without energy. I realize now that you were probably thinking of a TDR that sent a pulse (I was thinking of one that sent a step). My assertion is that when Ptotal = Pfor - Pref the idea that Pfor and Pref describe actual energy flows is very dubious. Ptotal always describes an energy flow. When Pfor is 0, then Pref is equal to Ptotal and since Ptotal is always describing an energy flow, Pref does in this case as well. Similarly when Pref is 0. ------- And now, since you are having trouble computing the energy flows into the various elements here they are again, for the circuit in the example of Fig 1-1, 100 Vrms sinusoidal source, 50 ohm source resistor, 45 degrees of 50 ohm line, 12.5 ohm load, after the reflection returns... The power flow into the line is Pg(t) = 32 + 68cos(2wt) and along with Ps(t) = 100 + 116.6190379cos(2wt-30.96375653) Prs(t) = 68 + 68cos(2wt-61.92751306) energy is nicely conserved because Ps(t) = Prs(t) + Pg(t) The load presented by the line has a resistive and a reactive component, so we can separate the power into two parts Pg.resis(t) = 32 + 32cos(2wt-61.92751306) Pg.react(t) = 0 + 60cos(2wt+28.07248694) which, for confirmation, nicely sums to Pg(t) above. Now as I recall, your claim was that the total power dissipated in the source resistor would be the power dissipated before the reflection returned plus the power imputed to be in the reflected wave plus the power stored in and returned from some other element in the circuit. Prs(t) = 50 + 50cos(2wt) + Pr.g(t) + Pstorage = 50 + 50cos(2wt) + 18 - 18cos(2wt) + Pstorage Pstorage = 68 + 68cos(2wt-61.92751306) - 50 - 50cos(2wt) - 18 + 18cos(2wt) = 0 + 36cos(2wt-90) which is not the power function of the reactive component of the line input impedance, Pg.reac(t), computed above. So the energy is not being stored in the reactive component of the line input impedance. ...Keith |
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On Mar 26, 9:51*pm, Cecil Moore wrote:
Keith Dysart wrote: In other posts, you have suggested that this would be a constructive interference energy and that there would be an equal destructive interference energy to provide it. If you still claim this, where is this destructive interference happening? I have said a source can match any destructive interference by supplying less power and match any constructive interference by supplying more power. If you have to falsify what I have said to try to win the argument, you have already lost. Since you have ample sources available in your example, my assertion about interference far removed from any source doesn't apply - but you know that. I had not realized that you had these alternate sources for the interference energies, not having seen that in your papers. But it is one way to sidestep the issue; different rules for the expectations of superposition and interference in different scenarios. I am surprised then, for the example of Fig 1-1 with 12.5 ohms, that you don't just say "There is a source nearby, that *must* be where the unaccounted energy comes from", and leave it at that. ...Keith |
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On Thu, 27 Mar 2008 11:49:03 GMT
Cecil Moore wrote: Roger Sparks wrote: The bottom line in a nutshell? I'll try. Thanks Roger, good stuff and much appreciated. My digesting of your spread sheets is about to be interrupted by surgery. Thanks for the kind words. Sorry to hear about your surgery. I hope it goes well and you have a quick recovery. During those times, the power applied to the transmission line is much HIGHER because the reflected wave reflects from the load and source, and merges/adds to the forward wave from the source.) May I suggest that you use the word "redistributed" instead of "reflected" as does the FSU web page at: http://micro.magnet.fsu.edu/primer/j...ons/index.html Clip I think "redistributed" would be the word if the discontinuity included a resistance. "Reflection" is the historical word for wave reversal and implies a "mirror image", which is not the same as the forward image. I hope the surgery does not take you away from the discussion for long. -- 73, Roger, W7WKB |
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Keith Dysart wrote:
So you are having difficulty doing the math to justify your hypothesis. Actually no, the math is not difficult. I'm pre- occupied with something else and think it's just time to agree with Hecht that instantaneous power is "of limited utility". Have you taken a look at Roger's spreadsheets? Conservation of energy requires that the total quantity of energy in the system not change. :-) Isn't the whole purpose of a transmitting antenna to radiate energy away from the antenna system? And that radiation continues to be "lost" from the system space for some time after the source power is removed? Wouldn't you have to define the "system" as the entire universe for your statement to be true? The powers must sum to 0 to satisfy conservation of energy. That may be true, but there's still no conservation of instantaneous power principle. A hot resistor continues to radiate heat long after any power source is removed. You could simply do the derivation for an example that demonstrates your hypothesis. Already done on my web page. My only actual hypothesis concerns average power. I've wasted too much time bantering about something that Hecht says is "of limited utility". the idea that Pfor and Pref describe actual energy flows is very dubious. Again, look yourself in the mirror and tell yourself that what you are seeing contains no energy. The theory that some EM waves contain energy and some do not is not new to you. Dr. Best was the first to theorize that canceled waves continue to propagate forever devoid of energy. Someone else asserted that canceled waves never contained any energy to start with. I strongly suspect that what you are seeing in the mirror are the waves that didn't cancel and that do contain energy. :-) So the energy is not being stored in the reactive component of the line input impedance. Assuming you have not made an error, so what? Energy stored in the reactance is only one of the possibilities that I listed earlier. As I said in an earlier posting which you declared a non-sequitor (sic), one or more of the following is true: 1. The source adjusts to the energy requirements. 2. The reactance stores and delivers energy. 3. Wave energy is redistributed during superposition. 4. Something I haven't thought of. The ExH reflected wave energy exists and cannot be destroyed. It goes somewhere and its average value is dissipated in the source resistor in my special case example. You are attempting to destroy the reflected wave energy using words and math presumably knowing all along that reflected wave energy cannot be destroyed. -- 73, Cecil http://www.w5dxp.com |
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Keith Dysart wrote:
I had not realized that you had these alternate sources for the interference energies, not having seen that in your papers. I only posted it three times here and you chose to ignore all of those postings. I have published only one paper with three more to go. The special case Part 1 contains zero average interference so there is no alternate source for average interference and indeed, none is needed for Part 1. But it is one way to sidestep the issue; different rules for the expectations of superposition and interference in different scenarios. That's why I have four parts only one of which has been published. The rules are not different but the conditions within the examples are different. Part 2 will be an example with the condition of average destructive interference existing at the source resistor. Although there are no ordinary reflections because the reflection coefficient is 0.0, there will exist something that looks a lot like a reflection caused by superposition/interference. The FSU web page calls it a "redistribution", not a "reflection". I am satisfied with FSU's word "redistribution" for the results of coherent wave interaction. I am surprised then, for the example of Fig 1-1 with 12.5 ohms, that you don't just say "There is a source nearby, that *must* be where the unaccounted energy comes from", and leave it at that. Since my special case example contains zero average interference, the average power output of the source is constant and unaffected by zero interference. There is zero average energy unaccounted for. Part 2 will illustrate the source adjusting its power output to compensate for destructive interference. -- 73, Cecil http://www.w5dxp.com |
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Roger Sparks wrote:
I think "redistributed" would be the word if the discontinuity included a resistance. "Reflection" is the historical word for wave reversal and implies a "mirror image", which is not the same as the forward image. What I am suggesting is that "redistribution" be used instead of "reflection" for cases where there exists no discontinuity. If the source resistor matches the Z0 of the feedline, there is no discontinuity and therefore no conventional reflection, yet there are cases where reflected energy is redistributed back toward the load. That reversal appears to be a reflection but is actually the result of superposition along with destructive interference between *two* waves. That is what causes the disparity between the physical reflection coefficient, (Z1-Z2)/(Z1+Z2), and the virtual reflection coefficient, SQRT(Pref/Pfor). I hope the surgery does not take you away from the discussion for long. At the least, I should still have one good eye left. ;-) -- 73, Cecil http://www.w5dxp.com |
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Cecil Moore wrote:
What I am suggesting is that "redistribution" be used instead of "reflection" for cases where there exists no discontinuity. This is sad. But I suppose that if you are going to invent new science you might as well invent new terminology as well. 8-) Yes, I know that the now-famous FSU web page uses "redistribution". Did you happen to notice that the page was created by a lab tech and a Java programmer? Do you suppose Hecht, Born and Wolf, and all of the other acknowledged experts would support dumping "reflection"? 73, Gene W4SZ |
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Gene Fuller wrote:
Yes, I know that the now-famous FSU web page uses "redistribution". Do you suppose Hecht, Born and Wolf, and all of the other acknowledged experts would support dumping "reflection"? I would guess the answer is "yes" when the physical reflection coefficient is zero - in order to avoid a logical contradiction. How does a "reflection" occur when the physical reflection coefficient is zero, in violation of the wave reflection model? Why is there often a difference between the physical reflection coefficient and the virtual reflection coefficient? Which one is wrong? The convention that I have adopted is that the word "reflection" is reserved for single wave events. For multiple wave events where interference exists, something besides a simple "reflection" takes place. The intricate color patterns on the surface of a thin film of oil floating on a puddle of water are not simple reflections but instead an interaction of multiple reflected waves. The resulting image bears absolutely no resemblance to the incident image. Following the FSU web page usage, the word "redistribution" is used for multiple wave interaction events like wave cancellation. (The words we choose to use to describe the phenomena have zero effect on the phenomena.) "A rose by any other name would smell as sweet." -- 73, Cecil http://www.w5dxp.com |
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Gene Fuller wrote:
Did you happen to notice that the page was created by a lab tech and a Java programmer? Gene, if a tech asserts a fact and an expert asserts a falsehood, who are you going to choose to believe? -- 73, Cecil http://www.w5dxp.com |
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On Mar 27, 6:44*pm, Cecil Moore wrote:
Gene Fuller wrote: Did you happen to notice that the page was created by a lab tech and a Java programmer? Gene, if a tech asserts a fact and an expert asserts a falsehood, who are you going to choose to believe? The simulator at that web site does seem to have its issues. Ask it to simulate 700 nm + 680 nm at the same amplitude and see if the result represents reality. ...Keith PS. The result should look like a 689.8 nm sine wave of continuously varying amplitude. |
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