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#1
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On Mar 31, 8:43*am, Cecil Moore wrote:
Keith Dysart wrote: But the meaning of the disclaimer is not clear to the reader. You really need to restate your hypothesis to remove the possibility of misleading the reader. What is it about "Please note that any power referred to in this paper is an AVERAGE POWER. Instantaneous power is irrelevant to the following discussion." that you do not understand? After many posts and back and forth, I understand. But the poor first reader will miss the implications: that the imputed energy in the reflected wave is not dissipated in the source resistor. Why not save the reader the challenge and just state it clearly? I would suggest ... I would suggest that you write your own article. Mine stands as written in the *stated context* of zero interference and average powers. I am not interested in attempting a unified theory of everything. Except that you have now indicated that there is interference in the circuit of Fig 1-1. I personally don't think that anyone else cares about instantaneous powers. I am sure some do not. But anyone interested in a full understanding does. Anyone interested in a *full* understanding would take the discussion down to the quantum level which, interestingly enough, you have chosen to ignore. Yes. I have stopped at the level that disproves that the imputed energy in the reflected wave is dissipated in the source resistor. That is sufficient for me. I do not think that deeper analysis will show this to be wrong, but you are invited to do so. On the other hand, average analysis can be shown to produce misleading results by applying instantaneous analysis. You should be interested because it disproves that the imputed energy in the reflected wave is dissipated in the source resistor. It is convenient when you just ignore the analysis that disproves your hypothesis. But it does not make the hypothesis more correct. If you think your unethical innuendo, out-of-context quotes, and straw man arguments disprove anything, I feel sorry for you. Once again, the context of my Part 1 assertions is *ZERO INTERFERENCE* and *AVERAGE POWERS*. You have disproved nothing so far. You were even taken aback when it was true at the instantaneous level in the context of zero instantaneous interference. I was? If so, I have now moved beyond. Especially since you now assert that the circuit does exhibit interference, the hypothesis becomes moot. ...Keith |
#2
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Keith Dysart wrote:
After many posts and back and forth, I understand. Do you understand that you need to go out and buy some ethics? -- 73, Cecil http://www.w5dxp.com |
#3
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Keith Dysart wrote:
After many posts and back and forth, I understand. But the poor first reader will miss the implications: that the imputed energy in the reflected wave is not dissipated in the source resistor. You have yet to provide an example of zero interference where the reflected power is not dissipated in the source resistor. Until you do that, you are just waving your hands. Examples containing interference will be covered in Parts 2 & 3 but the poor first reader will not get to read them until you cease your present unethical behavior. -- 73, Cecil http://www.w5dxp.com |
#4
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On Apr 1, 12:39*am, Cecil Moore wrote:
Keith Dysart wrote: After many posts and back and forth, I understand. But the poor first reader will miss the implications: that the imputed energy in the reflected wave is not dissipated in the source resistor. You have yet to provide an example of zero interference where the reflected power is not dissipated in the source resistor. Until you do that, you are just waving your hands. You misunderstand. I am not attempting to do that. Though somewhat bizzarre, I have, for the purposes of this discussion, accepted your definition of interference. And using your definition, that there is no interference when (V1**2 + V2**2) = (V1+V2)**2, it can be seen that for the circuit at hand, your Fig 1-1, there is zero interference in the terms you wish to add, four times in each cycle. From this one might conclude that the imputed reflected power is dissipated in the source resistor at four instances during the cycle. For the remainder of the cycle, again using your definition of interference, there is interference and hence the imputed reflected power is not all dissipated in the source resistor. Thus any unqualified assertion that the imputed reflected power is dissipated in the source resistor is somewhat disingenuous. Examples containing interference will be covered in Parts 2 & 3 but the poor first reader will not get to read them until you cease your present unethical behavior. But you have been claiming that the circuit of Part 1 already exhibits interference. ...Keith |
#5
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Keith Dysart wrote:
And using your definition, that there is no interference when (V1**2 + V2**2) = (V1+V2)**2, it can be seen that for the circuit at hand, your Fig 1-1, there is zero interference in the terms you wish to add, four times in each cycle. Correction for omitted word above: And using my definition, that there is no *average* interference when (V1**2 + V2**2) = (V1+V2)**2," Those are average (RMS) values of voltage. The test for zero *instantaneous* interference is: [V1(t)^2 + V2(t)^2] NOT= [V1(t)^2+V2(t)^2] Those are instantaneous values of voltage. Please correct your confusion about what I have said. It is also clear that you don't understand when interference exists and when it doesn't. The instantaneous destructive interference equals the instantaneous constructive interference 90 degrees later. That's why the interference averages out to zero. I believe, although I have not taken the time to prove it, that the instantaneous interference is zero only at the zero-crossings of the source voltage and reflected voltage. Again, the existence and magnitude of the instantaneous interference is irrelevant to the assertions in my Part 1 article. It is obvious that the interference averages out to zero over each cycle for the example presented. -- 73, Cecil http://www.w5dxp.com |
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