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#11
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Efficiency of 200-ohm hairpin matching
"K7ITM" wrote in message ... On Apr 7, 8:36 am, "Antonio Vernucci" wrote: .................................................. .................. On the other hand, I'm surprised by the comment from the manufacturer about difficulties making a 1:1 balun. I have had good luck using ferrites and/or self-resonant coils of feedline and/or coils of feedline specifically resonated with additional capacitance. A 4:1 balun from a "hairpin" of 1/2 wave of coax, arranged symmetrically, is easy enough to make, but I would not rule out using a 1:1, if it has advantages for you. Cheers, Tom Also, I think the 4:1 , 1/2 wave would be a voltage balun. I am considering adding a ferrite 1:1 on the feedline side of the the coax balun. There is some feedline radiation right now. Tam/WB2TT |
#12
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Efficiency of 200-ohm hairpin matching
On 7 abr, 23:15, "Antonio Vernucci" wrote:
Hello Tom, First, the matching is being done essentially with an "L" network (or rather the balanced version of an "L" network), where there is a load resistance (the resistive part of the feedpoint impedance, which includes radiation resistance and element loss resistance reflected to the feedpoint), the series capacitive reactance of the feedpoing element, and a shunt inductive reactance, provided by the hairpin. Because shortening the driven element causes a decrease in resistance and an increase in capacitive reactance, it's possible to find a length that allows matching to any of a wide range of resistances. But the higher the resistance to which you match, the shorter you need to make the element and the lower the feedpoint resistance. The ratio of feedpoint resistance to matched resistance determines the loaded Q of the matching network; as you make the matched resistance higher, the loaded Q goes up rather quickly. If you know the loaded Q and the unloaded Q of the hairpin, you have a good handle on the amount lost to heat in the hairpin: if the hairpin Q is two times the loaded Q, half the power is dissipated in the hairpin, for example. However, unless you build an antenna with a very low feedpoint resistance at resonance, there almost certainly won't be an efficiency problem: the reactance changes quickly enough with changes in driven element length that the resistance won't drop much by the time you reach enough reactance to get a match to 200 ohms. It appears that the loaded Q of the match to 200 ohms for your case will be less than 4. I would think unless you really messed up badly, the hairpin unloaded Q should be well in excess of 100, and if that's the case, the power lost in the hairpin would correspond to well under 0.1dB signal level change. All OK. I however reckon that, due to the parasitic elements effect, the radiation resistance of the driven element (before shortening it) would be in the order of 20 ohm. So, impedance gets brought up by a factor of 10 or so. On the other hand, I'm surprised by the comment from the manufacturer about difficulties making a 1:1 balun. I have had good luck using ferrites and/or self-resonant coils of feedline and/or coils of feedline specifically resonated with additional capacitance. A 4:1 balun from a "hairpin" of 1/2 wave of coax, arranged symmetrically, is easy enough to make, but I would not rule out using a 1:1, if it has advantages for you. His argument is that, for high-power operation (say 1500W), it is more convenient for him to provide a quarter-wavelength 4:1 balun made of RG-142 teflon cable than a sealed box with a 1:1 coil on an ironpowder toroidal core. I mentioned him that, just using some extra length of RG-142 cable, he can easily build a 1:1 balun, and hence design the antenna matching system for 50 ohm instead of 200 ohm. I hope he will listen to me, because that antenna is really narrowband! 73 Tony I0JX Hello, Imagine 10 Ohms radiation resistance + capacitive component after shortening the open dipole radiator. When you convert that to 200 Ohms via a parallel inductance (hairpin), the Q factor of such a network is about 4.4. At 50 MHz that will result in a bandwidth (VSWR=2) of 8 MHz. A 200 Ohms to 50 Ohms coaxial balun will have a lower Q factor. So the combination of balun and L-network will certainly have a useful bandwidth 340 kHz. Maybe the radiation resistance is less (you can derive that from the hairpin inductance) and/or the antenna is by nature (very) narrow band. Best regards, Wim PA3DJS www.tetech.nl remove abc from the address. |
#13
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Efficiency of 200-ohm hairpin matching
On Apr 7, 4:02 pm, Wimpie wrote:
On 7 abr, 23:15, "Antonio Vernucci" wrote: Hello Tom, First, the matching is being done essentially with an "L" network (or rather the balanced version of an "L" network), where there is a load resistance (the resistive part of the feedpoint impedance, which includes radiation resistance and element loss resistance reflected to the feedpoint), the series capacitive reactance of the feedpoing element, and a shunt inductive reactance, provided by the hairpin. Because shortening the driven element causes a decrease in resistance and an increase in capacitive reactance, it's possible to find a length that allows matching to any of a wide range of resistances. But the higher the resistance to which you match, the shorter you need to make the element and the lower the feedpoint resistance. The ratio of feedpoint resistance to matched resistance determines the loaded Q of the matching network; as you make the matched resistance higher, the loaded Q goes up rather quickly. If you know the loaded Q and the unloaded Q of the hairpin, you have a good handle on the amount lost to heat in the hairpin: if the hairpin Q is two times the loaded Q, half the power is dissipated in the hairpin, for example. However, unless you build an antenna with a very low feedpoint resistance at resonance, there almost certainly won't be an efficiency problem: the reactance changes quickly enough with changes in driven element length that the resistance won't drop much by the time you reach enough reactance to get a match to 200 ohms. It appears that the loaded Q of the match to 200 ohms for your case will be less than 4. I would think unless you really messed up badly, the hairpin unloaded Q should be well in excess of 100, and if that's the case, the power lost in the hairpin would correspond to well under 0.1dB signal level change. All OK. I however reckon that, due to the parasitic elements effect, the radiation resistance of the driven element (before shortening it) would be in the order of 20 ohm. So, impedance gets brought up by a factor of 10 or so. On the other hand, I'm surprised by the comment from the manufacturer about difficulties making a 1:1 balun. I have had good luck using ferrites and/or self-resonant coils of feedline and/or coils of feedline specifically resonated with additional capacitance. A 4:1 balun from a "hairpin" of 1/2 wave of coax, arranged symmetrically, is easy enough to make, but I would not rule out using a 1:1, if it has advantages for you. His argument is that, for high-power operation (say 1500W), it is more convenient for him to provide a quarter-wavelength 4:1 balun made of RG-142 teflon cable than a sealed box with a 1:1 coil on an ironpowder toroidal core. I mentioned him that, just using some extra length of RG-142 cable, he can easily build a 1:1 balun, and hence design the antenna matching system for 50 ohm instead of 200 ohm. I hope he will listen to me, because that antenna is really narrowband! 73 Tony I0JX Hello, Imagine 10 Ohms radiation resistance + capacitive component after shortening the open dipole radiator. When you convert that to 200 Ohms via a parallel inductance (hairpin), the Q factor of such a network is about 4.4. At 50 MHz that will result in a bandwidth (VSWR=2) of 8 MHz. A 200 Ohms to 50 Ohms coaxial balun will have a lower Q factor. So the combination of balun and L-network will certainly have a useful bandwidth 340 kHz. Maybe the radiation resistance is less (you can derive that from the hairpin inductance) and/or the antenna is by nature (very) narrow band. Best regards, Wim PA3DJSwww.tetech.nl remove abc from the address. Yes, I had similar thoughts, but a bit different. First, I think it's safe to say that if, at resonance, the driven element presents about 20 ohms at the feedpoint, shortening the D.E. only a little will give enough capacitive reactance to allow the hairpin match to 200 ohms. Even if the D.E. looks like 5 ohms, the "L" network match still gives a 3dB bandwidth of 8MHz at a 50MHz center, or 3MHz 1.5:1 SWR bandwidth. I think we need to look somewhere else for the answer to the narrow bandwidth. My working hypothesis at the moment is that it's in the antenna, or perhaps rather in the combination of antenna and matching network. Note that the calc for the L match assumed a constant capacitance, but the antenna will not, in general, look anything like a constant C even over a fairly narrow frequency range. I just ran EZNEC on a frequency-scaled version of the 14MHz 5 element Yagi included in the sample files, with the D.E. slightly shortened to allow a decent hairpin match to 200 ohms at the design center frequency. I did a frequency sweep, 49 to 51 MHz, in 0.25MHz steps. Over that range, the equivalent series capacitance changes from 59pF at the low end to 138pF at the high end, and at least by NEC2's prediction, the impedance changes especially quickly around 51MHz-- both reactive and resistive parts. 50.75MHz: 10.3-j31.76; 51MHz: 3.91- j22.56, quite a large percentage change in 250kHz. Having the effective series capacitance change that quickly will cause the matching network to behave very differently than it would with a capacitance element that is fixed. Is it possible to lengthen the D.E., causing it to present an inductive reactance at the feedpoint, and match that (to 200 ohms, or to 50 ohms) with a shunt capacitance? That may work better, giving a broader SWR bandwidth. The resistive component should be higher, further lowering the Q, and I suspect the reactance won't change so quickly with frequency. I don't have time at the moment to compare the two, but may this evening. It may also be possible to raise the resistive part to 50 ohms and match to 50 with a series capacitance. Cheers, Tom |
#14
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Efficiency of 200-ohm hairpin matching
K7ITM wrote:
Is it possible to lengthen the D.E., causing it to present an inductive reactance at the feedpoint, and match that (to 200 ohms, or to 50 ohms) with a shunt capacitance? That may work better, giving a broader SWR bandwidth.... Good, constructive suggestion, Tom. Kudos for putting in a bit of design/analysis effort on this rather than just shooting from the hip. This is definitely a weird way of driving a yagi. It makes me yearn for the old TV-antenna schemes that used folded dipoles for the driven element, suitably split-up between upper and lower wires so as to give a 300-ohm terminal impedance even with the resistance-lowering effects of the reflector and directors. Jim, K7JEB |
#15
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Efficiency of 200-ohm hairpin matching
Over that range, the equivalent series capacitance changes from 59pF
at the low end to 138pF at the high end, and at least by NEC2's prediction, the impedance changes especially quickly around 51MHz-- both reactive and resistive parts. 50.75MHz: 10.3-j31.76; 51MHz: 3.91- j22.56, quite a large percentage change in 250kHz. Having the effective series capacitance change that quickly will cause the matching network to behave very differently than it would with a capacitance element that is fixed. That is exactly the point! It would not be correct to calculate bandwidth on the basis of the Q factor at resonance and assuming that the capacitive antenna reactance is equivalent to that of a fixed capacitor. Today I have discovered another shortcoming of that antenna. After raining cats and dogs, the antenna resonant frequency gets lowered by about 130 kHz due to the influence of the wet terrain. That is really a lot if you consider that, after making very accurate measurements with a Bird wattmeter, the antenna bandwidth is only 100 kHz at 1.4 SWR! I am considering to re-build the driven element for 50-ohm match, by using a longer driven element and a 1:1 balun. However it will not be easy to find the optimum situation because there are two variables to be adjusted, that is the driven element length and the hairpin length. Also, I am not too sure on to which extent using a longer driven element would influence the antenna radiation pattern. Any comment? 73 Tony I0JX |
#16
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Efficiency of 200-ohm hairpin matching
Over that range, the equivalent series capacitance changes from 59pF
at the low end to 138pF at the high end, and at least by NEC2's prediction, the impedance changes especially quickly around 51MHz-- both reactive and resistive parts. 50.75MHz: 10.3-j31.76; 51MHz: 3.91- j22.56, quite a large percentage change in 250kHz. Having the effective series capacitance change that quickly will cause the matching network to behave very differently than it would with a capacitance element that is fixed. That is exactly the point! It would not be correct to calculate bandwidth on the basis of the Q factor at resonance and assuming that the capacitive antenna reactance is equivalent to that of a fixed capacitor. Today I have discovered another shortcoming of that antenna. After raining cats and dogs, the antenna resonant frequency gets lowered by about 130 kHz due to the influence of the wet terrain. That is really a lot if you consider that, after making very accurate measurements with a Bird wattmeter, the antenna bandwidth is only 100 kHz at 1.4 SWR! I am considering to re-build the driven element for 50-ohm match, by using a longer driven element and a 1:1 balun. However it will not be easy to find the optimum situation because there are two variables to be adjusted, that is the driven element length and the hairpin length. Also, I am not too sure on to which extent using a longer driven element would influence the antenna radiation pattern. Any comment? 73 Tony I0JX |
#17
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Efficiency of 200-ohm hairpin matching
Over that range, the equivalent series capacitance changes from 59pF
at the low end to 138pF at the high end, and at least by NEC2's prediction, the impedance changes especially quickly around 51MHz-- both reactive and resistive parts. 50.75MHz: 10.3-j31.76; 51MHz: 3.91- j22.56, quite a large percentage change in 250kHz. Having the effective series capacitance change that quickly will cause the matching network to behave very differently than it would with a capacitance element that is fixed. That is exactly the point! It would not be correct to calculate bandwidth on the basis of the Q factor at resonance and assuming that the capacitive antenna reactance is equivalent to that of a fixed capacitor. Today I have discovered another shortcoming of that antenna. After raining cats and dogs, the antenna resonant frequency gets lowered by about 130 kHz due to the influence of the wet terrain. That is really a lot if you consider that, after making very accurate measurements with a Bird wattmeter, the antenna bandwidth is only 100 kHz at 1.4 SWR! I am considering to re-build the driven element for 50-ohm match, by using a longer driven element and a 1:1 balun. However it will not be easy to find the optimum situation because there are two variables to be adjusted, that is the driven element length and the hairpin length. Also, I am not too sure on to which extent using a longer driven element would influence the antenna radiation pattern. Any comment? 73 Tony I0JX |
#18
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Efficiency of 200-ohm hairpin matching
On Apr 8, 12:31 pm, "Antonio Vernucci" wrote:
Over that range, the equivalent series capacitance changes from 59pF at the low end to 138pF at the high end, and at least by NEC2's prediction, the impedance changes especially quickly around 51MHz-- both reactive and resistive parts. 50.75MHz: 10.3-j31.76; 51MHz: 3.91- j22.56, quite a large percentage change in 250kHz. Having the effective series capacitance change that quickly will cause the matching network to behave very differently than it would with a capacitance element that is fixed. That is exactly the point! It would not be correct to calculate bandwidth on the basis of the Q factor at resonance and assuming that the capacitive antenna reactance is equivalent to that of a fixed capacitor. Today I have discovered another shortcoming of that antenna. After raining cats and dogs, the antenna resonant frequency gets lowered by about 130 kHz due to the influence of the wet terrain. That is really a lot if you consider that, after making very accurate measurements with a Bird wattmeter, the antenna bandwidth is only 100 kHz at 1.4 SWR! I am considering to re-build the driven element for 50-ohm match, by using a longer driven element and a 1:1 balun. However it will not be easy to find the optimum situation because there are two variables to be adjusted, that is the driven element length and the hairpin length. Also, I am not too sure on to which extent using a longer driven element would influence the antenna radiation pattern. Any comment? 73 Tony I0JX Though the Q calculation doesn't give the right SWR bandwidth for the antenna/matching system, it does tell you that (with such a low loaded Q), it should not be difficult to make a hairpin or even standard helical coil inductor that has low enough loss that you can ignore the effect. I believe that the physical length of the driven element in a Yagi is much less important than the tuning and spacing of the parasitic elements. The question becomes something like this: what is the relative amplitude and phase of the current in each parasitic element, for some excitation of the driven element? A Yagi is a system of coupled resonators, like a system of coupled pendulums. If one of the pendulums is driven at a particular amplitude and frequency, even if it's not that pendulum's natural frequency, the rest of the pendulums will follow along pretty much the same as if the driven pendulum was tuned to have that natural frequency. In the antenna, the difference will only be in the coupling from the driven element to the others, and I believe that changes only slightly as the length of the driven element changes. But I may be wrong about that, and await my re-education. ;-) But I just ran EZNec on the example "NBS" 3-element 50.1MHz Yagi, varying the nominal 110 inch long D.E. by +/- 10 inches, and saw the expected fairly large variation in impedance, but only 0.02dB change in gain over that whole range, with similarly small variation in F/B ratio and beam width. The longest D.E. I ran was also the highest gain (by that tiny amount), and provided enough inductive reactance that the feedpoint could be tuned to resonance and present 200 ohms by shunting with about 55pF capacitance. Next to try: compare the SWR bandwidths of the hairpin (inductive) shunt of a shortened D.E. and the capacitive shunt of a lengthened D.E.. Unless someone offers a better test case, I'll use the NBS 3 element Yagi... Cheers, Tom |
#19
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Efficiency of 200-ohm hairpin matching
I believe that the physical length of the driven element in a Yagi is much less important than the tuning and spacing of the parasitic elements. The question becomes something like this: what is the relative amplitude and phase of the current in each parasitic element, for some excitation of the driven element? A Yagi is a system of coupled resonators, like a system of coupled pendulums. If one of the pendulums is driven at a particular amplitude and frequency, even if it's not that pendulum's natural frequency, the rest of the pendulums will follow along pretty much the same as if the driven pendulum was tuned to have that natural frequency. In the antenna, the difference will only be in the coupling from the driven element to the others, and I believe that changes only slightly as the length of the driven element changes. But I may be wrong about that, and await my re-education. ;-) But I just ran EZNec on the example "NBS" 3-element 50.1MHz Yagi, varying the nominal 110 inch long D.E. by +/- 10 inches, and saw the expected fairly large variation in impedance, but only 0.02dB change in gain over that whole range, with similarly small variation in F/B ratio and beam width. The longest D.E. I ran was also the highest gain (by that tiny amount), and provided enough inductive reactance that the feedpoint could be tuned to resonance and present 200 ohms by shunting with about 55pF capacitance. Next to try: compare the SWR bandwidths of the hairpin (inductive) shunt of a shortened D.E. and the capacitive shunt of a lengthened D.E.. Unless someone offers a better test case, I'll use the NBS 3 element Yagi... Cheers, Tom Hi Tom, the results you got on EZNEC are encouraging. Nevertheless I would not like to try using a lengthened element in conjunction with a capacitor, as the difference between that configuration and the original configuration would be the maximum (although it would be much easier to adjust a capacitor than the inductance of an hairpin). What puzzles me is that the antenna manufacturer reported me having sold several hundreds of those antennas, and no one has reported him the bandwidth being too narrow or the exagerated wet terrain influence. I am not sure on what I am going to do, also because I am not 100% sure on whether the bandwidth problem is only due to the matching system, or it is also due to the particular antenna design. My original intention was to compare this 50-MHz long Yagi antenna (32-foot boom) against a smaller antenna (11-foot boom) I have on another tower, so as to determine how much a bigger antenna really helps during multiple-hop sporadic openings to US and Japan. Probably for the forecoming sporadic-E season (May-August) I will leave things as they are, and just try to assess the practical advantages of the bigger antenna. After that I will see what I shall do. Thanks very much for the useful discussion. 73 Tony I0JX |
#20
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Efficiency of 200-ohm hairpin matching
On 8 abr, 18:52, K7ITM wrote:
On Apr 7, 4:02 pm, Wimpie wrote: On 7 abr, 23:15, "Antonio Vernucci" wrote: Hello Tom, First, the matching is being done essentially with an "L" network (or rather the balanced version of an "L" network), where there is a load resistance (the resistive part of the feedpoint impedance, which includes radiation resistance and element loss resistance reflected to the feedpoint), the series capacitive reactance of the feedpoing element, and a shunt inductive reactance, provided by the hairpin. Because shortening the driven element causes a decrease in resistance and an increase in capacitive reactance, it's possible to find a length that allows matching to any of a wide range of resistances. But the higher the resistance to which you match, the shorter you need to make the element and the lower the feedpoint resistance. The ratio of feedpoint resistance to matched resistance determines the loaded Q of the matching network; as you make the matched resistance higher, the loaded Q goes up rather quickly. If you know the loaded Q and the unloaded Q of the hairpin, you have a good handle on the amount lost to heat in the hairpin: if the hairpin Q is two times the loaded Q, half the power is dissipated in the hairpin, for example. However, unless you build an antenna with a very low feedpoint resistance at resonance, there almost certainly won't be an efficiency problem: the reactance changes quickly enough with changes in driven element length that the resistance won't drop much by the time you reach enough reactance to get a match to 200 ohms. It appears that the loaded Q of the match to 200 ohms for your case will be less than 4. I would think unless you really messed up badly, the hairpin unloaded Q should be well in excess of 100, and if that's the case, the power lost in the hairpin would correspond to well under 0.1dB signal level change. All OK. I however reckon that, due to the parasitic elements effect, the radiation resistance of the driven element (before shortening it) would be in the order of 20 ohm. So, impedance gets brought up by a factor of 10 or so. On the other hand, I'm surprised by the comment from the manufacturer about difficulties making a 1:1 balun. I have had good luck using ferrites and/or self-resonant coils of feedline and/or coils of feedline specifically resonated with additional capacitance. A 4:1 balun from a "hairpin" of 1/2 wave of coax, arranged symmetrically, is easy enough to make, but I would not rule out using a 1:1, if it has advantages for you. His argument is that, for high-power operation (say 1500W), it is more convenient for him to provide a quarter-wavelength 4:1 balun made of RG-142 teflon cable than a sealed box with a 1:1 coil on an ironpowder toroidal core. I mentioned him that, just using some extra length of RG-142 cable, he can easily build a 1:1 balun, and hence design the antenna matching system for 50 ohm instead of 200 ohm. I hope he will listen to me, because that antenna is really narrowband! 73 Tony I0JX Hello, Imagine 10 Ohms radiation resistance + capacitive component after shortening the open dipole radiator. When you convert that to 200 Ohms via a parallel inductance (hairpin), the Q factor of such a network is about 4.4. At 50 MHz that will result in a bandwidth (VSWR=2) of 8 MHz. A 200 Ohms to 50 Ohms coaxial balun will have a lower Q factor. So the combination of balun and L-network will certainly have a useful bandwidth 340 kHz. Maybe the radiation resistance is less (you can derive that from the hairpin inductance) and/or the antenna is by nature (very) narrow band. Best regards, Wim PA3DJSwww.tetech.nl remove abc from the address. Yes, I had similar thoughts, but a bit different. First, I think it's safe to say that if, at resonance, the driven element presents about 20 ohms at the feedpoint, shortening the D.E. only a little will give enough capacitive reactance to allow the hairpin match to 200 ohms. Even if the D.E. looks like 5 ohms, the "L" network match still gives a 3dB bandwidth of 8MHz at a 50MHz center, or 3MHz 1.5:1 SWR bandwidth. Hello Tom, Fully agree with you. I gave the values for a 20 to 200 Ohms match to show that the problem is not in the matching, but in the antenna. Even matching from 20 to 50 Ohms will not give sufficient bandwidth, because actual BW is far below the BW of the matching network (with 20 Ohms termination). I think we need to look somewhere else for the answer to the narrow bandwidth. My working hypothesis at the moment is that it's in the antenna, or perhaps rather in the combination of antenna and matching network. Note that the calc for the L match assumed a constant capacitance, but the antenna will not, in general, look anything like a constant C even over a fairly narrow frequency range. That rapid Im(Zant) change is the reason for the narrow BW. I just ran EZNEC on a frequency-scaled version of the 14MHz 5 element Yagi included in the sample files, with the D.E. slightly shortened to allow a decent hairpin match to 200 ohms at the design center frequency. Did you also scale the thickness of the elements? I did a frequency sweep, 49 to 51 MHz, in 0.25MHz steps. Over that range, the equivalent series capacitance changes from 59pF at the low end to 138pF at the high end, and at least by NEC2's prediction, the impedance changes especially quickly around 51MHz-- both reactive and resistive parts. 50.75MHz: 10.3-j31.76; 51MHz: 3.91- j22.56, quite a large percentage change in 250kHz. Having the effective series capacitance change that quickly will cause the matching network to behave very differently than it would with a capacitance element that is fixed. Is it possible to lengthen the D.E., causing it to present an inductive reactance at the feedpoint, and match that (to 200 ohms, or to 50 ohms) with a shunt capacitance? That may work better, giving a broader SWR bandwidth. The resistive component should be higher, further lowering the Q, and I suspect the reactance won't change so quickly with frequency. I don't have time at the moment to compare the two, but may this evening. It may also be possible to raise the resistive part to 50 ohms and match to 50 with a series capacitance. I did use length extension for very thick mesh dipoles for VHF air band. Their resonant impedance is less then 50 Ohms (because they become short). Some additional length gives some inductance to use a parallel capacitor match and (most important) bandwidth increase. I don't know whether this will give sufficient BW improvement for the Yagi as the Q is also determined by the reflector en directors. I am looking forward to your simulation results. Cheers, Tom Wim PA3DJS www.tetech.nl Please remove abc from the address. |
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