Home |
Search |
Today's Posts |
|
#1
![]() |
|||
|
|||
![]() Francesco, before you go, may I ask what is the purpose of the filter? Is it to prevent the local FM stations interfering with reception? Or is it to stop any unexpected transmitter spurious signals from being transmitted in the FM band? It is to prevent desensing from strong local FM stations. Noise can go up to S7 when beaming the local transmitters. An LC filter could be easily made but that would need to be switched out when in TX (or made to pass a few hundred watts), I just thougth a couple of stubs could be easier to made. I think I was wrong. 73 Francesco IZ8DWF Francesco, You can build a notch filter with two stubs, and get a good match, and rejection. The velocity factor of Cellflex 1/2" is 0.82, as per: http://www2.rfsworld.com/RFS_Edition...able_30-46.pdf The lengths of the shunt, open stubs, are reasonably critical within +/- 1cm. I have used a Genesys optimization program with the physical parameters of the Cellflex coax. The open shunt stub lengths are 63 cm. The series stub is 41.3 cm. The insertion loss at 70 MHz is 0.4 db. The return loss at 70 MHz is 20 db. Rejection over the whole FM band is 20 db. Using the Smith Chart to design a filter is tricky, since you are dealing with multiple frequencies, and three variables. Let me know if you would like to see my results, will be glad to e-mail them as JPEGs. 73, Frank (VE6CB) |
#2
![]() |
|||
|
|||
![]()
On 23 Lug, 02:50, "Frank" wrote:
Francesco, You can build a notch filter with two stubs, and get a good match, and rejection. The velocity factor of Cellflex 1/2" is 0.82, as per:http://www2.rfsworld.com/RFS_Edition...able_30-46.pdf The lengths of the shunt, open stubs, are reasonably critical within +/- 1cm. I have used a Genesys optimization program with the physical parameters of the Cellflex coax. The open shunt stub lengths are 63 cm. The series stub is 41.3 cm. The insertion loss at 70 MHz is 0.4 db. The return loss at 70 MHz is 20 db. Rejection over the whole FM band is 20 db. ok, with cut and try arrived at similar results, shunts are 64 cm and series is 47 cm, the antenna analyzer is happy, I'm not so happy because I don't understand where's my original error. Using the Smith Chart to design a filter is tricky, since you are dealing with multiple frequencies, and three variables. well, yes, but actually the design started with the shorts at 98 MHz which are easy, then the only unknown variable becomes the series stub that gives a 50 ohm match at 70 MHz, I still don't get why the matching section appear to be 3/8 wl on a smith chart and actually is 1/8 like if I inverted the sense of load/generator (yes, I worked with admittances for shunt stubs). Let me know if you would like to see my results, will be glad to e-mail them as JPEGs. sure, my email address is valid, thank you very much. 73 Francesco IZ8DWF |
#3
![]() |
|||
|
|||
![]()
well, yes, but actually the design started with the shorts at 98 MHz
which are easy, then the only unknown variable becomes the series stub that gives a 50 ohm match at 70 MHz, I still don't get why the matching section appear to be 3/8 wl on a smith chart and actually is 1/8 like if I inverted the sense of load/generator (yes, I worked with admittances for shunt stubs). Let me know if you would like to see my results, will be glad to e-mail them as JPEGs. sure, my email address is valid, thank you very much. 73 Francesco IZ8DWF Francesco, I will be e-mailing my results for your interest. We seem to have arrived at the same conclusions. I think I understand where you are confused. Initially, starting at the center of the Smith Chart, the shunt open stub moves down, along the constant conductance circle (0.2S). At 0.175 WL at 70 MHz (0.25 WL at 98 MHz) - 62 cm, the input impedance is 10 - j 20 ohms. Next; the series section of transmission line moves clockwise along the 10 ohm resistance circle. At 0.125 WL (70 MHz) - 44 cm, the impedance reaches 10 + j 20. The final shunt section then moves the impedance to the center of the Smith Chart along the 0.2 S circle. 73, Frank (VE6CB) |
#4
![]() |
|||
|
|||
![]() "Frank" wrote in message news:HMKhk.1277$nu6.889@edtnps83... well, yes, but actually the design started with the shorts at 98 MHz which are easy, then the only unknown variable becomes the series stub that gives a 50 ohm match at 70 MHz, I still don't get why the matching section appear to be 3/8 wl on a smith chart and actually is 1/8 like if I inverted the sense of load/generator (yes, I worked with admittances for shunt stubs). Let me know if you would like to see my results, will be glad to e-mail them as JPEGs. sure, my email address is valid, thank you very much. 73 Francesco IZ8DWF Francesco, I will be e-mailing my results for your interest. We seem to have arrived at the same conclusions. I think I understand where you are confused. Initially, starting at the center of the Smith Chart, the shunt open stub moves down, along the constant conductance circle (0.2S). At 0.175 WL at 70 MHz (0.25 WL at 98 MHz) - 62 cm, the input impedance is 10 - j 20 ohms. Next; the series section of transmission line moves clockwise along the 10 ohm resistance circle. At 0.125 WL (70 MHz) - 44 cm, the impedance reaches 10 + j 20. The final shunt section then moves the impedance to the center of the Smith Chart along the 0.2 S circle. 73, Frank (VE6CB) Hi Frank When describing the path on the Smith Chart from the "load" Z to the "rig" Z, you write "along the 10 ohm resistance circle". I would have refered to that circle as the circle of constant VSWR. Jerry KD6JDJ |
#5
![]() |
|||
|
|||
![]()
Hi Frank
When describing the path on the Smith Chart from the "load" Z to the "rig" Z, you write "along the 10 ohm resistance circle". I would have refered to that circle as the circle of constant VSWR. Jerry KD6JDJ Of course you are correct Jerry. I realized what I had done after I posted the comments. Frank, VE6CB |
#6
![]() |
|||
|
|||
![]() "Frank" wrote in message news:RH1ik.1379$%b7.1159@edtnps82... Hi Frank When describing the path on the Smith Chart from the "load" Z to the "rig" Z, you write "along the 10 ohm resistance circle". I would have refered to that circle as the circle of constant VSWR. Jerry KD6JDJ Of course you are correct Jerry. I realized what I had done after I posted the comments. Frank, VE6CB Hi Frank My reply was delayed because I had anticipated that someone might ask you for clarification on Smith Chart use. I was sure you'd clear up the confusion. I even thought I might learn something new. Smith Chart use is so valuable to my thinking that I just couldnt let this thread finish without checking in with you. Jerry KD6JDJ |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Desert Rat Dilemma | Homebrew | |||
G5RVh COAX feeder lengths dilemma ? Help please | Antenna | |||
Folded monopole dilemma | Antenna | |||
What might be an interesting dilemma... | General | |||
Desktop Radio Dilemma | Shortwave |