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Phase array question
Cecil Moore wrote:
Joel Koltner wrote: "Powers don't add, field strengths do" "Add" is a rather loosely defined term. A more technically precise statement would be: "Powers don't superpose, field strengths do." Fields superpose, numbers add, and power is the rate of change in energy. When fields superpose, they still must obey the conservation of energy principle, i.e. the total energy before the superposition must equal the total energy after the superposition. It's almost as if you think that if you don't always point it out, energy won't be conserved! :-) Given two RF waves in a transmission line and the phase angle, A, between the two electric fields, the following Power equation, published in QEX, gives us a valid method of "adding" two powers. Ptotal = P1 + P2 + 2*SQRT(P1*P2)*cos(A) According to fig. 7.1 in Born and Wolf, that's useful for showing how light intensity varies as a function of phase, and hence position. It's just that there's no valid way to multiply by the cosine of the angle between two scalars. Maybe wave problems are best solved using waves. The last term is known in optics as the "interference" term, positive for constructive interference and negative for destructive interference. Angle A, the phase angle between the two electric fields, determines the sign of the last term and thus whether interference is destructive or constructive. (A+B)*(A+B) = A^2 + B^2 + 2AB Must the first order term (2AB) in such equations always be referred to as "The Interference Term", Cecil? Doing so seems to impart a greater level of importance to it than to the other, unnamed terms in the equation. The factored form must then be least important of all. Beats, interference, and modulation are fundamentally the same phenomenon. There's no need to get all worked up about one of them in deference to the others, just as there's no need to worry about there being a node for every antinode. 73, ac6xg |
#2
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Phase array question
Jim Kelley wrote:
Cecil Moore wrote: Ptotal = P1 + P2 + 2*SQRT(P1*P2)*cos(A) According to fig. 7.1 in Born and Wolf, that's useful for showing how light intensity varies as a function of phase, and hence position. It's just that there's no valid way to multiply by the cosine of the angle between two scalars. You are pretty confused. The angle is between the electric field intensities of the two waves being superposed. Must the first order term (2AB) in such equations always be referred to as "The Interference Term", Cecil? From "Optics", by Hecht, 4th Edition, page 387 & 388: "I12 = 2E1*E2 ... and is known as the interference term." E1 and E2 are electric field intensities. * is the dot product. indicates a time average value. "The interference term becomes I12 = 2*SQRT(I1*I2)cos(delta)" Hecht calls it the "interference term" and I am only quoting him. -- 73, Cecil http://www.w5dxp.com |
#3
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Phase array question
Cecil Moore wrote:
Jim Kelley wrote: Cecil Moore wrote: Ptotal = P1 + P2 + 2*SQRT(P1*P2)*cos(A) According to fig. 7.1 in Born and Wolf, that's useful for showing how light intensity varies as a function of phase, and hence position. It's just that there's no valid way to multiply by the cosine of the angle between two scalars. You are pretty confused. I think you know that I'm just pointing out the problem inherent in using a valid equation in the way you describe without considering the many assumptions being made. It led you, for example, to write that there is a 4th mechanism of reflection - even in violation of Maxwell's equations! Do you still believe that interference actually moves power from one place to another? It is that kind of nonsense that amateur radio would be better off without. Hecht calls it the "interference term" and I am only quoting him. I'll bet he'd prefer that you didn't. :-) 73, ac6xg |
#4
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Phase array question
Jim Kelley wrote:
I think you know that I'm just pointing out the problem inherent in using a valid equation in the way you describe without considering the many assumptions being made. It led you, for example, to write that there is a 4th mechanism of reflection - Here's a quote from my energy article: "Note that the author previously used the word "reflection" for both actions involving a single wave and the interaction between two waves. Now the word "reflected" is being used only for single waves and the word "redistributed" is being used for the two wave interference scenario." Nowhere in my present article do I say there is a 4th mechanism of reflection. Why do you continue to incessantly harp on past semantic blunders that were corrected years ago? Do you still believe that interference actually moves power from one place to another? Do you ever stop beating dead horses? :-) Since I stated in my article that power doesn't flow, you are just once more bearing false witness. Maybe you should have that burr under your blanket looked at by a competent veterinarian. :-) I said that the redistribution of energy, which necessarily obeys the conservation of energy principle, is associated with a wave cancellation interference event. I never uttered your false statement that "interference moves power". Here's what I said: "The term "power flow" has been avoided in favor of "energy flow". Power is a measure of that energy flow per unit time through a plane. Likewise, the EM fields in the waves do the interfering. Powers, treated as scalars, are incapable of interference." Yet, a couple of times a year just like clockwork, you accuse me of saying that power moves (which I have never said). One wonders what drives your never-ending vendetta obsession. Here is the definition that I am using for RF "interference" adopted from "Optics", by Hecht: RF wave interference corresponds to the interaction of two (or more) RF waves yielding a resultant power density for the total wave that deviates from the sum of the two power densities in the superposed component waves. It is simple physics to realize that (V1+V2)^2 is not usually equal to (V1^2 + V2^2). When they are not equal, interference has occurred. Why do you have such a problem with such a simple concept? In a transmission line, the power equation indicates exactly by how much the resultant power deviates from the sum of the component powers. The magnitude of that deviation from the sum of the component powers is called the "interference term" according to Hecht. Ptotal = P1 + P2 + 2*SQRT(P1*P2)cos(A) 'A' is the angle between the V1 and V2 voltage phasors. -- 73, Cecil http://www.w5dxp.com |
#5
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Phase array question
Jim Kelley wrote:
Cecil Moore wrote: Ptotal = P1 + P2 + 2*SQRT(P1*P2)*cos(A) According to fig. 7.1 in Born and Wolf, that's useful for showing how light intensity varies as a function of phase, and hence position. It's just that there's no valid way to multiply by the cosine of the angle between two scalars. I suspect you knew if I ever found my Born and Wolf after my move, you would be in trouble - and you are. You previously said that Born and Wolf did not agree with Hecht, but they do, contrary to your assertions. Their equation for irradiance (intensity) agrees with Hecht. Itot = I1 + I2 + J12 where J12 = 2E1*E2 = 2*SQRT(I1*I2)*cos(A) On page 258 of "Principles of Optics", by Born and Wolf, 4th edition, they label J12 as the *interference term*, contrary to your assertions. (Hecht labels that term I12) -- 73, Cecil http://www.w5dxp.com |
#6
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Phase array question
Cecil Moore wrote:
Jim Kelley wrote: Cecil Moore wrote: Ptotal = P1 + P2 + 2*SQRT(P1*P2)*cos(A) According to fig. 7.1 in Born and Wolf, that's useful for showing how light intensity varies as a function of phase, and hence position. It's just that there's no valid way to multiply by the cosine of the angle between two scalars. I suspect you knew if I ever found my Born and Wolf after my move, you would be in trouble - and you are. No. I assumed you could find fig 7.1 and see it for yourself. The plot has phase on the X-axis and intensity on the Y-axis. The caption reads Interference of two beams of equal intensity; variation of intensity with phase difference. " At the top of the page: "Let us consider the distribution of intensity resulting from the superposition of two waves which are propagated in the z-direction...." The relation is useful for precisely the reason I indicated. That is why Heckt also includes it in his book. I deleted the rhetorical blithering from your post. And again, please quote my remarks directly whenever you wish to discuss them. 73, ac6xg |
#7
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Phase array question
Jim Kelley wrote:
The relation is useful for precisely the reason I indicated. That is why Heckt also includes it in his book. Your Freudian slip concerning your feelings about Hecht is more than apparent, i.e. "To Heck with Hecht"! :-) One wonders why you said something to the effect that Hecht had been discredited in favor of Born and Wolf. When I recommended the 57 page chapter on interference in "Optics", by Hecht, you said something to the effect that interference is unimportant, yet Born and Wolf's chapter on interference is 113 pages long and mostly agrees with Hecht's writings. -- 73, Cecil http://www.w5dxp.com |
#8
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Phase array question
On Thu, 7 Aug 2008 17:55:29 -0700, "Joel Koltner"
wrote: I've taken college classes in antennas and hence have a pretty good feel for some of the mathematics behind it all, but I've found that at times I don't have good, intuitive explanations for various antenna behaviors -- and I'm not at all good at being able to look at some fancy antenna and start rattling off estimates of the directivity, front to back ratio, etc. -- so I wanted to ask a simple question on a two-element phased array: First, start with one antenna. Feed it 1W, and assume that in some "preferred" direction at some particular location the (electric) field strength is 1mV/m. Now, take two antennas, and space them and/or phase their feeds such that in the same preferred direction the individual antenna patterns add. I.e., we're expecting a 6dB gain over the single antenna (but only at that location). Since we start off by splitting the power to each antenna (1/2W to each), that initially seems impossible, since 1/2W+1/2W = 1W -- should imply the same 1mV/m field strength. But this is an incorrect analysis, in that powers don't add directly. Instead, the fields add... hence, each antenna alone will now produce 707uV/m (at the one particular location in question), so the two together produce 1.414mV/m which is the same as if the single antenna had been fed with 2W. Hence the 6dB gain we're after! (This analysis also implies there must be other locations that now receive 1mV/m in order to conserve energy.) Is that correct? "Powers don't add, field strengths do" is obvious enough, but definitely leads to some slightly non-intuitvely-obvious (to me) results. By extension of the above, though, it becomes obvious that (in theory) one can build an array with any desired amount of gain, the beamwidth just has to become narrower and narrower, of course. Thanks, ---Joel What Roy did not tell you is that his program has a free demo version (http://eznec.com/) that will will provide quick answers. The learning curve for EZNEC is pretty sharp for about 10 minutes and then it shallows out. John Ferrell W8CCW |
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