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#1
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Phase array question
I've taken college classes in antennas and hence have a pretty good feel for
some of the mathematics behind it all, but I've found that at times I don't have good, intuitive explanations for various antenna behaviors -- and I'm not at all good at being able to look at some fancy antenna and start rattling off estimates of the directivity, front to back ratio, etc. -- so I wanted to ask a simple question on a two-element phased array: First, start with one antenna. Feed it 1W, and assume that in some "preferred" direction at some particular location the (electric) field strength is 1mV/m. Now, take two antennas, and space them and/or phase their feeds such that in the same preferred direction the individual antenna patterns add. I.e., we're expecting a 6dB gain over the single antenna (but only at that location). Since we start off by splitting the power to each antenna (1/2W to each), that initially seems impossible, since 1/2W+1/2W = 1W -- should imply the same 1mV/m field strength. But this is an incorrect analysis, in that powers don't add directly. Instead, the fields add... hence, each antenna alone will now produce 707uV/m (at the one particular location in question), so the two together produce 1.414mV/m which is the same as if the single antenna had been fed with 2W. Hence the 6dB gain we're after! (This analysis also implies there must be other locations that now receive 1mV/m in order to conserve energy.) Is that correct? "Powers don't add, field strengths do" is obvious enough, but definitely leads to some slightly non-intuitvely-obvious (to me) results. By extension of the above, though, it becomes obvious that (in theory) one can build an array with any desired amount of gain, the beamwidth just has to become narrower and narrower, of course. Thanks, ---Joel |
#2
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Phase array question
Joel Koltner wrote:
I've taken college classes in antennas and hence have a pretty good feel for some of the mathematics behind it all, but I've found that at times I don't have good, intuitive explanations for various antenna behaviors -- and I'm not at all good at being able to look at some fancy antenna and start rattling off estimates of the directivity, front to back ratio, etc. -- so I wanted to ask a simple question on a two-element phased array: First, start with one antenna. Feed it 1W, and assume that in some "preferred" direction at some particular location the (electric) field strength is 1mV/m. Now, take two antennas, and space them and/or phase their feeds such that in the same preferred direction the individual antenna patterns add. I.e., we're expecting a 6dB gain over the single antenna (but only at that location). Since we start off by splitting the power to each antenna (1/2W to each), that initially seems impossible, since 1/2W+1/2W = 1W -- should imply the same 1mV/m field strength. But this is an incorrect analysis, in that powers don't add directly. Instead, the fields add... hence, each antenna alone will now produce 707uV/m (at the one particular location in question), so the two together produce 1.414mV/m which is the same as if the single antenna had been fed with 2W. Hence the 6dB gain we're after! (This analysis also implies there must be other locations that now receive 1mV/m in order to conserve energy.) Is that correct? "Powers don't add, field strengths do" is obvious enough, but definitely leads to some slightly non-intuitvely-obvious (to me) results. By extension of the above, though, it becomes obvious that (in theory) one can build an array with any desired amount of gain, the beamwidth just has to become narrower and narrower, of course. There are two errors in your analysis. The first is that you've neglected mutual coupling between the elements. In some special cases, this will result in equal feedpoint impedances, so that equal powers will result in equal currents, which in turn result in equal field strengths. But that happens only in special cases and not by any means all cases. In the general case, splitting the power equally between elements won't result in equal fields from them. Moving on, let's assume that you've got a special case where the equal power split results in equal field strength. Your analysis is then correct up until you calculate the dB gain. Your correct value of 1.414 mV/m is correct, but it represents a 3, not 6, dB gain relative to a single element (which produced 1 mV/m). In the absence of mutual coupling, and if the elements are spaced and phased such that there's some direction in which the fields can completely reinforce, then the maximum pattern gain relative to a single element is 10 * log(N) where N is the number of elements, e.g., 3 dB for two elements, 6 dB for four elements, etc. For a much more detailed explanation of these phenomena, I recommend reading the treatment of phased arrays in Chapter 8 of the _ARRL Antenna Book_. I'm admittedly a bit partial to this particular treatment, since I wrote it. Roy Lewallen, W7EL |
#3
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Phase array question
"Joel Koltner" wrote in message ... I've taken college classes in antennas and hence have a pretty good feel for some of the mathematics behind it all, but I've found that at times I don't have good, intuitive explanations for various antenna behaviors -- and I'm not at all good at being able to look at some fancy antenna and start rattling off estimates of the directivity, front to back ratio, etc. -- so I wanted to ask a simple question on a two-element phased array: First, start with one antenna. Feed it 1W, and assume that in some "preferred" direction at some particular location the (electric) field strength is 1mV/m. Now, take two antennas, and space them and/or phase their feeds such that in the same preferred direction the individual antenna patterns add. I.e., we're expecting a 6dB gain over the single antenna (but only at that location). Since we start off by splitting the power to each antenna (1/2W to each), that initially seems impossible, since 1/2W+1/2W = 1W -- should imply the same 1mV/m field strength. But this is an incorrect analysis, in that powers don't add directly. Instead, the fields add... hence, each antenna alone will now produce 707uV/m (at the one particular location in question), so the two together produce 1.414mV/m which is the same as if the single antenna had been fed with 2W. Hence the 6dB gain we're after! (This analysis also implies there must be other locations that now receive 1mV/m in order to conserve energy.) Is that correct? "Powers don't add, field strengths do" is obvious enough, but definitely leads to some slightly non-intuitvely-obvious (to me) results. By extension of the above, though, it becomes obvious that (in theory) one can build an array with any desired amount of gain, the beamwidth just has to become narrower and narrower, of course. Thanks, ---Joel yes, all true. and that is where many of the arguments on here begin, trying to add powers instead of fields, voltages, or currents. and yes, theoretically you can keep making the beamwidth narrower and get more and more gain, that is one reason lasers are so intense with such low power, they have extremely narrow beamwidths. |
#4
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Phase array question
It's also 'true' that to get more gain in one direction you
typically have less gain in some other direction. You can't get something for nothing, so you are only redirecting what you've already got, so to speak (how directional antennas work). - 'Doc |
#5
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Phase array question
Joel Koltner wrote:
"Powers don't add, field strengths do" "Add" is a rather loosely defined term. A more technically precise statement would be: "Powers don't superpose, field strengths do." When fields superpose, they still must obey the conservation of energy principle, i.e. the total energy before the superposition must equal the total energy after the superposition. Given two RF waves in a transmission line and the phase angle, A, between the two electric fields, the following Power equation, published in QEX, gives us a valid method of "adding" two powers. Ptotal = P1 + P2 + 2*SQRT(P1*P2)*cos(A) Reference: "Wave Mechanics of Transmission Lines, Part 3", by Steven R. Best, VE9SRB, "QEX", Nov/Dec 2001, (Eq 13), page 4. The last term is known in optics as the "interference" term, positive for constructive interference and negative for destructive interference. Angle A, the phase angle between the two electric fields, determines the sign of the last term and thus whether interference is destructive or constructive. Reference: "Optics", by Hecht, 4th Edition: Chapter 7: The Superposition of Waves Chapter 9: Interference -- 73, Cecil http://www.w5dxp.com |
#6
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Phase array question
On Thu, 7 Aug 2008 17:55:29 -0700, "Joel Koltner"
wrote: I've taken college classes in antennas and hence have a pretty good feel for some of the mathematics behind it all, but I've found that at times I don't have good, intuitive explanations for various antenna behaviors -- and I'm not at all good at being able to look at some fancy antenna and start rattling off estimates of the directivity, front to back ratio, etc. -- so I wanted to ask a simple question on a two-element phased array: First, start with one antenna. Feed it 1W, and assume that in some "preferred" direction at some particular location the (electric) field strength is 1mV/m. Now, take two antennas, and space them and/or phase their feeds such that in the same preferred direction the individual antenna patterns add. I.e., we're expecting a 6dB gain over the single antenna (but only at that location). Since we start off by splitting the power to each antenna (1/2W to each), that initially seems impossible, since 1/2W+1/2W = 1W -- should imply the same 1mV/m field strength. But this is an incorrect analysis, in that powers don't add directly. Instead, the fields add... hence, each antenna alone will now produce 707uV/m (at the one particular location in question), so the two together produce 1.414mV/m which is the same as if the single antenna had been fed with 2W. Hence the 6dB gain we're after! (This analysis also implies there must be other locations that now receive 1mV/m in order to conserve energy.) Is that correct? "Powers don't add, field strengths do" is obvious enough, but definitely leads to some slightly non-intuitvely-obvious (to me) results. By extension of the above, though, it becomes obvious that (in theory) one can build an array with any desired amount of gain, the beamwidth just has to become narrower and narrower, of course. Thanks, ---Joel What Roy did not tell you is that his program has a free demo version (http://eznec.com/) that will will provide quick answers. The learning curve for EZNEC is pretty sharp for about 10 minutes and then it shallows out. John Ferrell W8CCW |
#7
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Phase array question
Hi Roy,
"Roy Lewallen" wrote in message treetonline... There are two errors in your analysis. The first is that you've neglected mutual coupling between the elements. Yes, I assumed it was negligible. When we analyzed arrays in class some years ago, the starting point was always, "assume each antenna has the pattern of a single dipole in isolation, is matched to the transmission lines, with input current 1A @ angle whatever." We did analyze the patterns for a couple of local Oregon TV & radio stations, BTW, including whichever radio? station it is up in Portland (very roughly) near you off of I-205 as you drive past Oregon City. But that happens only in special cases and not by any means all cases. The phased arrays I had in mind were those that were usually separated by a "significant" fraction of a wavelength, e.g., lambda/8 or more. That's probably not far enough apart to neglect coupling? Your correct value of 1.414 mV/m is correct, but it represents a 3, not 6, dB gain relative to a single element (which produced 1 mV/m). 6dB vs. 3dB is a rather embarassing outright brain fart on my part. :-) (The usual case of confusing "twice the power = 3dB" with "twice the voltage = 6dB"). For a much more detailed explanation of these phenomena, I recommend reading the treatment of phased arrays in Chapter 8 of the _ARRL Antenna Book_. I'm admittedly a bit partial to this particular treatment, since I wrote it. Thanks Roy, I'll take a look! ---Joel |
#8
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Phase array question
"Cecil Moore" wrote in message
... Ptotal = P1 + P2 + 2*SQRT(P1*P2)*cos(A) So... let's see... my two 1/2W antennas now, in the "preferred" location, get you... 0.5+0.5+2*sqrt(0.5*0.5)*cos(0) = 2W... yep, same as the field strength analysis. Cool! Presumably you could demonstrate all this with a "ripple tank" (the kind with water used back in high school physics) -- set things up so that, in a preferred direction, the wave height is 1.414 even though the wave height made by each "radiator" in isolation is 0.707. Thanks Cecil, ---Joel |
#9
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Phase array question
Joel Koltner wrote:
Hi Roy, "Roy Lewallen" wrote in message treetonline... There are two errors in your analysis. The first is that you've neglected mutual coupling between the elements. Yes, I assumed it was negligible. When we analyzed arrays in class some years ago, the starting point was always, "assume each antenna has the pattern of a single dipole in isolation, is matched to the transmission lines, with input current 1A @ angle whatever." We did analyze the patterns for a couple of local Oregon TV & radio stations, BTW, including whichever radio? station it is up in Portland (very roughly) near you off of I-205 as you drive past Oregon City. But that happens only in special cases and not by any means all cases. The phased arrays I had in mind were those that were usually separated by a "significant" fraction of a wavelength, e.g., lambda/8 or more. That's probably not far enough apart to neglect coupling? Not by a long shot! Here's a simple example from the EZNEC demo program, using example file Cardioid.EZ. It's a two element array of quarter wavelength vertical elements spaced a quarter wavelength apart and fed with equal currents in quadrature to produce a cardioid pattern. The impedance of a single isolated element is 36.7 + j1.2 ohms. In the array, the impedances are 21.0 - j18.7 and 51.6 + j20.9 ohms, and the elements require 29 and 71 percent of the applied power respectively in order to produce equal fields. The deviation is due to mutual coupling. This particular array is a special case of another kind -- there is no net effect of the mutual coupling on the array gain, so it has 3.0 dB gain over a single element. This isn't true in the general case, however. Neglecting the mutual coupling is convenient for the professors because it simplifies the problem and allows them to illustrate the simple addition of fields. The problem is that it leads some students to think they have the whole story. In very large arrays such as those used for radar, the vast majority of elements are in essentially the same environment relative to each other so the mutual coupling has the same effect on all except the outer few elements. But it simply can't be ignored in arrays of a few elements. Your correct value of 1.414 mV/m is correct, but it represents a 3, not 6, dB gain relative to a single element (which produced 1 mV/m). 6dB vs. 3dB is a rather embarassing outright brain fart on my part. :-) (The usual case of confusing "twice the power = 3dB" with "twice the voltage = 6dB"). For a much more detailed explanation of these phenomena, I recommend reading the treatment of phased arrays in Chapter 8 of the _ARRL Antenna Book_. I'm admittedly a bit partial to this particular treatment, since I wrote it. Thanks Roy, I'll take a look! Another source which has a good discussion of the topic is Johnson's _Antenna Engineering Handbook_, or earlier editions edited by Jasik. Be wary of amateur and hobbyist publications (other than the _ARRL Antenna Book_ -- very few authors understand the topic, and pass along their misconceptions. Roy Lewallen, W7EL |
#10
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Phase array question
"Roy Lewallen" wrote in message
treetonline... Not by a long shot! Here's a simple example from the EZNEC demo program, using example file Cardioid.EZ. It's a two element array of quarter wavelength vertical elements spaced a quarter wavelength apart and fed with equal currents in quadrature to produce a cardioid pattern. The impedance of a single isolated element is 36.7 + j1.2 ohms. In the array, the impedances are 21.0 - j18.7 and 51.6 + j20.9 ohms, and the elements require 29 and 71 percent of the applied power respectively in order to produce equal fields. The deviation is due to mutual coupling. That's a much, much greater difference than I would have guessed. Wow... Isn't the input impedance of one element affected not only by the relative position of the other element, but also how it's driven? I.e., element #1 "sees" element #2 and couples to it, but how much coupling occurs depends on whether the input of element #2 is coming from a 50 ohm generator vs. a 1 ohm power amplifier (close to a voltage source), etc.? (Essentially viewing the antennas as loosely coupled transformers, where the transformer terminations get reflected back to the "primary.") Thanks for the book links. Do you happen to have a copy of "Small Antenna Design" by Douglas Miron? And have an opinion about it? Or some other book on electrically small antennas? (Not phased arrays, though :-) -- more like octave bandwidth VHF or UHF antennas that are typically 1/10-1/40 lambda in physical size.) ---Joel |
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