Jim Kelley wrote:
Let me try this then: Do you still think that interference is what
moves ENERGY from one place to another?

To the best of my knowledge, I addressed all of your objections
in a revision to my energy article which was done many months
ago. The reasons for your objections don't even exist any more.

Note that the reason the author included the disclaimer about "power
flow" was because the term "power flow" had not been avoided by said
author in this newsgroup, in an argument which must have gone on for 6
weeks.

But that argument happened many, many years ago. You convinced
me that power doesn't flow. I respect the fact that it is a
commonly accepted concept defined in "The IEEE Dictionary",
rampant within every power company, and accepted by many
members of this newsgroup.

If you will check back over the years, you will find a posting
of mine where I said the dimensions of power flow would be
joules/sec/sec which doesn't make any physical sense.

But the fact that (V1+V2)^2 is equal to
V1^2 + V2^2 + 2V1*V2 doesn't depend in the least on whether
"interference has occurred", Cecil. That was the whole point of my
comment about it.

Yes, and you are still wrong according to Hecht. If the
interference term in the power equation is not zero,
(V1^2+V2^2) does not equal (V1+V2)^2. In the special case
where (V1^2+V2^2) = (V1+V2)^2, the interference
term is zero, i.e. zero interference.

Please reference page 388 in "Optics", by Hecht, 4th Edition.

Hecht
makes no such connection between 'power' and 'interference', Cecil.

But Hecht certainly makes a connection between 'power density' and
'interference'. It is a trivial matter to convert the power density
irradiance equation to the power equation by multiplying by the
cross-sectional area of a transmission line.

The units of irradiance (power density) are joules/sec/unit-area.

Multiply the irradiance equation by the unit-area of the coax,
e.g. 1 in^2, and you get joules/sec = power which is what a
Bird wattmeter indicates.

If you want, you can convert the Bird wattmeter reading to
irradiance by dividing by the cross-sectional area of the
coax.

'A' is the angle between the V1 and V2 voltage phasors.

...and NOT between the two 'powers'.

*Nobody* has ever said there is a phase angle between two powers
yet you persist in that false strawman implication.
--
73, Cecil http://www.w5dxp.com