Home |
Search |
Today's Posts |
#14
![]() |
|||
|
|||
![]()
On Aug 8, 1:13 pm, Roy Lewallen wrote:
Joel Koltner wrote: "Roy Lewallen" wrote in message streetonline... Not by a long shot! Here's a simple example from the EZNEC demo program, using example file Cardioid.EZ. It's a two element array of quarter wavelength vertical elements spaced a quarter wavelength apart and fed with equal currents in quadrature to produce a cardioid pattern. The impedance of a single isolated element is 36.7 + j1.2 ohms. In the array, the impedances are 21.0 - j18.7 and 51.6 + j20.9 ohms, and the elements require 29 and 71 percent of the applied power respectively in order to produce equal fields. The deviation is due to mutual coupling. That's a much, much greater difference than I would have guessed. Wow... Isn't the input impedance of one element affected not only by the relative position of the other element, but also how it's driven? I.e., element #1 "sees" element #2 and couples to it, but how much coupling occurs depends on whether the input of element #2 is coming from a 50 ohm generator vs. a 1 ohm power amplifier (close to a voltage source), etc.? (Essentially viewing the antennas as loosely coupled transformers, where the transformer terminations get reflected back to the "primary.") Not directly. What counts (considering the simple case of two elements) is the magnitude and phase of the current in the other element, and their spacing, orientation, and lengths. A good way to look at the effect of mutual coupling is as "mutual impedance", i.e., the amount of impedance change caused by mutual coupling. (Johnson/Jasik covers this concept well.) If you were to feed two elements with constant current sources (as in the Cardioid.EZ EZNEC example), mutual coupling doesn't change the element currents, but only the feedpoint impedances. With any other kind of feed system, the impedance change causes the currents to change, which in turn affects the impedances. So the feed method certainly does have an effect on the currents you get, which affects both mutual coupling and pattern. There's a lot more about this, and how to design feed systems which will effect the desired currents, in the _ARRL Antenna Book_. Thanks for the book links. Do you happen to have a copy of "Small Antenna Design" by Douglas Miron? And have an opinion about it? Or some other book on electrically small antennas? (Not phased arrays, though :-) -- more like octave bandwidth VHF or UHF antennas that are typically 1/10-1/40 lambda in physical size.) I just recently purchased Miron's book but haven't yet looked at it in any depth. It appears to be most interesting to anyone wanting a better understanding of method of moments numerical methods. If you can read German, you might be interested in _Kurze Antennen_ by Gerd Janzen. But your search for small, broadband antennas puts you bump-up against the principle "small - broadband - efficient, choose any two". They'll be inefficient, which will hurt you both receiving and transmitting at VHF and above. The book I'd go to for researching the possibilities would be Lo & Lee's _Antenna Handbook_. You might also get some ideas from Bailey, _TV and Other Receiving Antennas_, since TV antennas have to be pretty broadband. Roy Lewallen, W7EL Simply in an effort to provide a bit more insight, or perhaps I should better say to suggest a math tool that may lead you to more insight, consider what "mutual impedance" means. In a simple circuit where there's a current through an impedance, the voltage drop across it is given by V = Z * I. If you expand this idea to include mutual impedances, the Z becomes a matrix, and I and V are vectors. So in an antenna system with, say, four feedpoints, V becomes a vector of four voltages, one for each feedpoint, and I similarly is a vector of four currents, one for each feedpoint. Z is then a four-by-four matrix with self-impedances along the diagonal and mutual impedances off the diagonal. It is clear that if you know the four currents, you can find the voltages. Further, if you can invert the Z matrix, then you can calculate the currents if you know the voltages. That also suggests how to find the mutual impedances: if you excite one feedpoint with a known current and leave all the rest open, you can measure the voltages at each (including phase) and that immediately gives you the mutual impedance from the excited feedpoint to each of the others: your I vector has only one non-zero component. Repeat for each feedpoint. You can use the same sort of analysis with other systems which have interaction among components. For example, a system of inductors which share magnetic fields can easily be characterized by a matrix of self-inductances and mutual inductances. For a single inductor, V = L*di/dt; if you have two coupled inductors, V1 = L1 * di1/dt + M12 * di2/dt, and V2 = M21 * di1/dt + L2 * di2/dt -- or in matrix notation, V = L * d/dt(I). That can expand to as many inductors as you care to consider. (If this is confusing, it's probably best to just ignore this suggestion...) Cheers, Tom |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Central Electronics 20 A Phase shift question | Boatanchors | |||
1.2 GHZ collinear array | Antenna | |||
GAP & phased array | Antenna | |||
AX.25 parameter negotiation phase question | Digital |