Home |
Search |
Today's Posts |
#141
![]() |
|||
|
|||
![]() |
#142
![]() |
|||
|
|||
![]()
On Sep 2, 10:43*pm, John Smith wrote:
wrote: ... I disagree. There is no choking, there is merely a polarity and phase shift between the "primary" and "secondary" of the 1:1 balun "transformer". The best way I can easily express this is to consider a 1:1 240V 60 Hz isolation transformer (yes, the balun acts theoretically in the same manner). ... No. *But you have focused on your error in thinking/logic/function. *An RF Transformers does what you state, lengths of transmission line carrying RF behave in a different "mode." (uh, I hate that word ...) Now, if you do some research, you can correct your error(s) ... Regards, JS -- It is like a nightmare where the public servants are the people which the police are supposed to protect us from! A 1:1 balun IS an RF transformer. Lengths of transmission line wound an air core can function as a 1:1 RF transformer. Does this in any way show you the error you are making? Transformers operate in the same way whether at 60Hz or RF. So much for your "No" statement which seems to demonstrate a certain confidence masked in senility. |
#143
![]() |
|||
|
|||
![]()
On Sep 3, 7:18*am, Cecil Moore wrote:
wrote: For a balanced transmission line, the characteristic impedance is not expressed in differential mode terms, it IS common mode so I do not know why you ask about differential mode characteristic impedance. Well, there's your problem. In a properly functioning transmission line, whether balanced or unbalanced, the currents in the two conductors are differential, not common-mode. The two currents are equal in magnitude and 180 degrees out of phase and their fields tend to cancel which minimizes radiation. Common-mode currents only occur when the two currents are not perfectly differential, i.e. not equal amplitudes and/or not 180 degrees out of phase. -- 73, Cecil *http://www.w5dxp.com Nope. The CM choke works precisely because the common mode currents are mirror images, 180 degrees out of phase. If they weren't, the CM choke could not act to cancel them and you would need differential mode chokes to get rid of them. On your balanced feedline, the voltage at any point is delta between the amplitude of line 1 and 2. |
#144
![]() |
|||
|
|||
![]()
On Sep 3, 7:44*am, Cecil Moore wrote:
wrote: By the way, I have seen so many articles about baluns written by other hams and they tend to repeat the same mistakes and assumptions. Most hams do not understand how a balun works. Your following statement puts you in that category. Inserting a balun does not "choke" the current in the shield, it merely shifts the output phases so that the current (voltage) is directed towards the dipole at all times (see my other post in this thread). This applies to a W2DU balun. Why would you want differential current fields to be introduced into the #77 ferrite beads? Their entire purpose is to provide a large choking impedance and dissipate common-mode power. -- 73, Cecil *http://www.w5dxp.com OK, next time I specify an EMC filter for a switching power supply, I will ensure that the CM choke impedance matches the impedances of the network and the loads so that I can most efficiently conduct RFI from the source to the power line, from common mode at the load to unbalanced load of the power line source. This will ensure maximum interference is imparted on the phase conductor. In fact, I think I will change my nomenclature by refering to the "choke" as a "balun" (they are one and the same; the source doesn't know the difference!) and promptly fail my next FCC submittal. Then I will be invited to retire and of course I will have much more time to be re- educated on rec.radio.amareur.antenna. |
#145
![]() |
|||
|
|||
![]()
On Sep 3, 8:04*am, Cecil Moore wrote:
wrote: Many US amateurs do not understand how a balun works. Quoting "The ARRL Antenna Book" re a w2du balun: "Maxwell made a test balun by slipping 300 #73 beads over a piece of RG-303 coaxial cable. The impedance of the outer conductor of the cable measured 4500+j3800 at 4.0 MHz." The differential current emerging from the inside of the coax braid encounters, e.g. 30 ohms, looking toward the antenna. It encounters 4500+j3800 = 5890 ohms looking back down the outside of the coax. Ohm's law does the rest. Without the beads, that differential current might see an impedance lower than 30 ohms looking back down the outside of the coax for certain unfortunate lengths of coax. The common-mode choking impedance forces ~equal currents in each dipole leg at the BALanced antenna to UNbalanced coax junction. That common-mode choking impedance causes the balun function to occur. -- 73, Cecil *http://www.w5dxp.com Because the input and the out windings of the balun must be isolated at least at RF of interest, OF COURSE there should be a high impedance between the ballanced current flow and the unbalanced current flow. However, the impedance of the source looking into the impedance from the souurce should match source impedance and the impedance of the load looking in the output winding of the balun should match the load impedance (say 70 ohms, or 600 ohms or whatever your antenna or trnasmission line impedance is. The impedence at frequency of interest between input winding and output winding should be infinity for isolation purposes (obviously you do not want to mix the unbalanced input and balanced output currents. |
#146
![]() |
|||
|
|||
![]()
On Sep 3, 2:10*pm, Cecil Moore wrote:
Richard Clark wrote: wrote: Many US amateurs do not understand how a balun works. How true - not even fundamental terminology. http://en.wikipedia.org/wiki/Balun(see 1st photo) "This is a simple RF *choke* which works as a *balun* by preventing signals passing along the outside of the braid." *From "The IEEE Dictionary": "balun (1) A network for the transformation from an unbalanced line or system to a balanced line or system, or vice versa." *From an Unabridged Webster's: "balun - a device for converting a balanced line into an unbalanced line and vice versa." 10 PRINT "A W2DU balun is both a choke and a balun!" 20 Goto 10 -- 73, Cecil *http://www.w5dxp.com I agree that a balun operating at 14 MHz would be a choke when operating at 70MHz. |
#148
![]() |
|||
|
|||
![]()
On Sep 3, 3:59*pm, Richard Clark wrote:
On Mon, 1 Sep 2008 09:26:26 -0700 (PDT), wrote: In a perfect situation, with a balanced feedline, the only kind of current and voltage you have IS common mode! This statement above contains a serious error of perception while trying to inhabit the debate over BalUns - and it probably corrupts that topic too. First - a circuit has at a minimum two conductors extending from a source. *A circuit by its nature is circular: for every charge carrier that enters it, one must exit it. *Continuity is a necessary condition for a circuit. *No continuity, no conduction, hence an "Open Circuit." Second - those two conductors, if viewed at a remote point where they are joined, have equal and opposite paths of current conduction - to and from that point. *This is from Kirchoff's law of currents. Third - this is called Differential Mode current in anticipation of a common modality. Fourth - if that remote point of connection is replaced with a load, there is a voltage across that load characterized by both the unaltered directions of current, and its now altered magnitude of current. Fifth - this is called Differential Mode voltage in anticipation of a common modality. This completes the discussion of the Differential Mode. If we expand upon this simple model of a source, two wires, and a load and put it into the context of life as we know it; then the circuit operates in the proximity of ground. *By convention, ground is called Common. Ground, by convention is an infinite sink of charge of infinite extent. *Hence as a conductor, it is available everywhere - Common. This ground may have either deliberate or accidental conductive relationships to the Differential Circuit. First - the linkage of ground to the differential circuit can be through an Ohmic path, or by an inductive path, or by a capacitive path. *To support conduction, the circuit must contain two conductive paths to ground through any combination of these linkages, and that path must be complete. *The apparent source driving conduction through that path will be a combination of the differential source and the differential load as each will have some relationship to ground. * Second - *those two conductive paths, if viewed at a remote point where they are joined, have equal and opposite paths of current conduction - to and from that point. *This is from Kirchoff's law of currents. * Third - this is called Common Mode current. Fourth - as the differential circuit is original and establishes both the source and the load; then through the introduction of ground, this Common Mode current is mixed with the original Differential Current and analysis must be performed by substitutions to separate them. Fifth - the apparent source presents the Common Mode voltage. This completes the discussion of Common Mode. The applications of a choke to either circuit is commonplace to control each mode's current. *It would appear through the context of discussion in other threads that there is some confusion in what is being choked, and how a choke is properly applied is confounded by that confusion. It follows that if the transmission line from the source to load suffers from Common Mode currents, that this must be due to a Common Mode voltage gradient extending from the source to the load. *If either lead of that transmission line pair were choked, this would disrupt the Differential Mode. *If both leads of the transmission line pair were independently choked, this would only double the disruption. However, if both leads were choked in parallel (both lines either coiled as a pair rather than individually, or both lines penetrate a lossy core) then their fields would be contained between them in the Differential Mode, but their Common Mode path (they both share equal conduction in the same direction due to the Common Mode voltage gradient) will be snubbed. Some BalUns employ these techniques - some don't. *BalUns fail by the degree that they don't when Common Mode, as a problem, is injected into the circuit through imbalances. *As balance in the proximity of earth and many confounding nearby structures is a forgone failure, choking is a practical necessity for correct BalUn performance. *Any issues of BalUn heatings are proof of this choking necessity, and further proof of the demand for additional choking at that point (and frequently elsewhere at wavelength relationships along the affected line). 73's Richard Clark, KB7QHC Let me put it this way (again very simplifed): How do you explain a residential 208V power source where you have 120 V from line 1 and line 2 to ground but 240V with respect to each other. You 240V household appliances operate this way. Ecept for the fact that the lines are 120 degrees out of phase phase (insread of 180 because we use a delta system instead of Y, but this is not that important for this discussion) this is nearly a BALANCED feed, where lines 1 and 2 degrees out of phase at 60 Hz and the voltage of interest is the summation of the two lines. Nearly every home in the USA operates this way. In Europe, 240 V is usually obtained by the voltage difference between line 1 (240V) and earth (0V). That is an unbalanced feed. You can insert a 1:1 isolation transformer using the European system at the input and create the balanced USA system at the output by drawing +120 and -120 at from the output windings assigning imaginary isolated earth at centertap. The isolated ground CANNOT conduct tio real ground if the winding to winding impedance is infinity. Basically, hams' 1:1 baluns do much the same thing: They isolate the real ground as such and prevent currents from flowing down the input ground shield. On this ng in a short space I cannot think of a simpler way to express this although I expect to see many statements (you can't equate 60Hz to RF!). Yes you can; a transformer operates as a transformer in the same wayat any frequency providing you design it properly for the frequency of interest. This subject is not nearly so complicated as some in this group makes it out to be and the topic certainly does not rate articles in amateur publications any more than basic application of ohm's law does. |
#149
![]() |
|||
|
|||
![]()
On Sep 3, 7:12*pm, Cecil Moore wrote:
wrote: Nope. The CM choke works precisely because the common mode currents are mirror images, 180 degrees out of phase. You are 100% wrong. From "The IEEE Dictionary": "common-mode (1)(general) The instantaneous algebraic average of two signals applied to a balanced circuit, both signals referred to a common reference." The "instantaneous algebraic average of two signals" 180 degrees out of phase is ZERO. -- 73, Cecil *http://www.w5dxp.com So that means I get 0 volts when I touch one side of the 120V in my electrical service to the 120V other side? I was afraid I might see 240V. |
#150
![]() |
|||
|
|||
![]()
wrote:
I agree that a balun operating at 14 MHz would be a choke when operating at 70MHz. You would do well to agree that a well-designed W2DU balun operating at 14 MHz is choking the heck out of the 14 MHz common-mode current in order to achieve the balun function. You seem to have the IEEE definitions of differential signals and common-mode signals exactly reversed. Because of that misconception, might you be the one who doesn't understand how baluns work? -- 73, Cecil http://www.w5dxp.com |