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#1
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Reg Edwards wrote:
Cec, I don't doubt your experimental results. It's your extrapolated imagination and logic which worries me. ;o) I didn't imagine those experimental results, Reg, and all I did was report those results. My logic tells me that there is a grain of valid circumstantial evidence in there somewhere. What you need to do to prove your point is present an antenna where the high-current portion is prohibited from radiating yet still yields a high field strength. Example #1: The top half of an electrical 1/4WL antenna is prohibited from radiating by a balanced top hat. Field strength results are similar to a 1/4WL monopole. This has already been presented. Example #2: The bottom half of an electrical 1/4WL antenna is prohibited from radiating by _________________. Fill in the blank and prove that field strength results are similar to a 1/4WL monopole. That's all you need to do to make a believer (instead of a doubter) out of me. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#2
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Its the voltage parts of the antenna which do the radiating.
That is proved by cutting off the top part of the antenna and replacing it with a top hat which has a much larger capacitance so it radiates the power harder. --- Reg. |
#3
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![]() Cecil Moore wrote: Reg, we have a clear example of where the high voltage part of the antenna is not allowed to radiate (much). That would be a balanced top hat. Not allowing the high voltage part of the antenna to radiate leaves the high current part to do most of the radiating. Cecil, Reg makes a good point. We know that the same amplitude (less ohmic losses) of current travels the entire length of the antenna in both directions. The relative phase of forward and reverse currents simply makes the superposition of the two currents greater at one end than another. We might measure the standing wave current with an ammeter, but it is the traveling wave currents which radiate. 73, Jim AC6XG |
#4
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Jim Kelley wrote:
Reg makes a good point. We know that the same amplitude (less ohmic losses) of current travels the entire length of the antenna in both directions. The relative phase of forward and reverse currents simply makes the superposition of the two currents greater at one end than another. We might measure the standing wave current with an ammeter, but it is the traveling wave currents which radiate. A balanced top hat doesn't radiate much because the currents in the opposing elements are 180 degrees out of phase with each other. It doesn't matter if they are traveling waves or standing waves. If they are 180 degrees out of phase with each other, they are more like a transmission line than they are like an antenna. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#5
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Cecil Moore wrote:
Reg, we have a clear example of where the high voltage part of the antenna is not allowed to radiate (much). That would be a balanced top hat. Not allowing the high voltage part of the antenna to radiate leaves the high current part to do most of the radiating. Cecil, Reg makes a good point. We know that the same amplitude (less ohmic losses) of current travels the entire length of the antenna in both directions. The relative phase of forward and reverse currents simply makes the superposition of the two currents greater at one end than another. We might measure the standing wave current with an ammeter, but it is the traveling wave currents which radiate. 73, Jim AC6XG ============================ Jim, are you one of the crackpots who think that it's the voltage parts of the antenna which do the radiating which is proved by replacing the top portion of the antenna with a top hat which has a large capacitance so that the voltage has a greater effect. ;o) --- Reg, G4FGQ |
#6
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Reg Edwards wrote:
Cecil Moore wrote: Reg, we have a clear example of where the high voltage part of the antenna is not allowed to radiate (much). That would be a balanced top hat. Not allowing the high voltage part of the antenna to radiate leaves the high current part to do most of the radiating. Cecil, Reg makes a good point. We know that the same amplitude (less ohmic losses) of current travels the entire length of the antenna in both directions. The relative phase of forward and reverse currents simply makes the superposition of the two currents greater at one end than another. We might measure the standing wave current with an ammeter, but it is the traveling wave currents which radiate. 73, Jim AC6XG ============================ Jim, are you one of the crackpots who think that it's the voltage parts of the antenna which do the radiating which is proved by replacing the top portion of the antenna with a top hat which has a large capacitance so that the voltage has a greater effect. ;o) --- Reg, G4FGQ Hi Reg, Were it not for this group, I would never have known the full extent of my crackpottedness! My colleagues and associates have been keeping it a secret from me all these years evidently. With that in mind, yes. Nevermind Farady. The size of the hat should indeed determine the size of the effect. I wear a 7 3/4. 73, Jim AC6XG |
#7
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Reg, G4FGQ wrote:
"One old wife asserts it is obvious radiation occurs mainly from the middle portion of a dipole because that is where the current is strongest and the magnetic field is most concentrated." All sections of a dipole are needed to establish the wave launcher / grabber. Seems to me the old wife quoted above is right. Radiation from a dipole is concentrated in a doughnut pattern around the middle of the wire. What influences are sensed at a distance point perpendicular to the middle of the dipole? There are electric fields, plus and minus, which cancel. The current on one side of the dipole flows into the source while the current on the other side of the source flows out. This places current on both sides of the dipole in the same direction. The magnetic fields from both sides of the dipole are additive because the currents producing them are in-phase. Never mind that an electromagnetic wave must have an electric field as well as a magnetic field. The emerging magnetic field generates an electric field which generates a magnetic field ad infinitum. Best regards, Richard Harrison, KB5WZI |